Chapter 3, Problem 15ALQ

### Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404

Chapter
Section

### Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404
Textbook Problem

# Chlorine exists mainly as two isotopes, 37Cl and 33Cl. Which is more abundant? How do you know?

Interpretation Introduction

Interpretation: The more abundant isotope of chlorine, between 37Cl and 35Cl , is to be stated.

Concept introduction: A different form of the same element having the same proton number but a different neutron number in its nucleus is known as an isotope of the element.

To determine: The more abundant isotope of chlorine.

Explanation

The molar mass of Cl is 35.5g/mol .

The molar mass of 35Cl is 35g/mol .

The molar mass of 37Cl is 37g/mol .

The molar mass of the chlorine atom in the periodic table is stated as the average mass of its two isotopes (weighed in accordance to their abundance).

Formula

The average mass of the chlorine atom is calculated using the formula,

M(Cl)=[(M(35Cl))×(%abundance(35Cl))+(M(37Cl))×(1%abundance(35Cl))]

Where,

• M(Cl) is the molar mass of chlorine.
• M(35Cl) is the molar mass of 35Cl .
• M(37Cl) is the molar mass of 37Cl .
• %abundance(35Cl) is the percent abundance of 35Cl .

Substitute the values of M(Cl) , M(35Cl) , M(37Cl) and %abundance(35Cl) in the above expression.

35

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