Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3, Problem 15MCQ
To determine

To explain: The system of equations that can be used to find the number of tickets sold on each day.

  Fft=56f+t=406

  Gt56=ff+t=406

  Hft=406f+t=56

  I.  ft=56f+406=t

Expert Solution & Answer
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Answer to Problem 15MCQ

The system of equations that can be used to find number of tickets sold on each day is ft=56f+t=406 . Option F. is correct.

Explanation of Solution

Given information:

On Thursday, the art museum sold 56 fewer tickets than they sold on Friday. They sold a total of 406 tickets on Thursday and Friday.

Formula used:

To frame system of equations, convert the language of word problem to mathematical statements by assuming the values of unknown as variables.

Calculation:

Consider the provided information that On Thursday, the art museum sold 56 fewer tickets than they sold on Friday. They sold a total of 406 tickets on Thursday and Friday.

Recall that to frame system of equations, convert the language of word problem to mathematical statements by assuming the values of unknown as variables.

Let the number of tickets sold on Thursday be t and number of tickets sold on Friday be f.

Then according to the statement that “They sold a total of 406 tickets on Thursday and Friday”, the mathematical statement in terms of variable will be,

  f+t=406

Now, according to statement that “On Thursday, the art museum sold 56 fewer tickets than they sold on Friday”, the equation so formed will be,

  f56=tft=56

Therefore, the system of equation is,

  f+t=406ft=56

Thus, the system of equations that can be used to find number of tickets sold on each day is ft=56f+t=406 . Option F. is correct.

Chapter 3 Solutions

Algebra 2

Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42HPCh. 3.1 - Prob. 43HPCh. 3.1 - Prob. 44HPCh. 3.1 - Prob. 45HPCh. 3.1 - Prob. 46HPCh. 3.1 - Prob. 47HPCh. 3.1 - Prob. 48HPCh. 3.1 - Prob. 49HPCh. 3.1 - 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