a.
To solve: the system of linear equation so that to find the time at which the peter will catch up to Julian.
a.
Answer to Problem 43PPS
Explanation of Solution
Given:
The total distance of the cycling courses is 104.8 miles.
Julian starts from 8 hrs. and rides at 12 miles per hrs.
Peter starts from 10 hrs. and rides at 16 miles per hrs.
Calculation:
Let x be the distance for each person and y be the speed.
According to the question,
Now, solve the both equation so that to get the numbers
Now, to equate:
Multiply equation (1) by 2 to get
Hence, after 6 hours, peter will catch up to Julian.
b.
To explain: the how could he change his starting time.
b.
Answer to Problem 43PPS
Explanation of Solution
Given:
The total distance of the cycling courses is 104.8 miles.
Julian starts from 8 hrs. and rides at 12 miles per hrs.
Peter wants to reduce the time; it takes him to catch up to Julian by 1 hrs.
Calculation:
Suppose Peter wants to catch up in 7 hours and remains at the same speed. Peter starts t hours after Julian.
According to the question,
Hence, after 1.75 hours, peter will catch up to Julian.
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Algebra 2
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