Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3.4, Problem 15PPS
To determine

To calculate: The coordinates of the vertices of the feasible region formed by graphing the given inequalities x≥−8,3x+6y≤36 and 2y+12≥3x . Also maximum and minimum values of the function f(x,y)=10x−6y in this region.

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Answer to Problem 15PPS

The graph of the given system of inequalities is,

  Algebra 2, Chapter 3.4, Problem 15PPS , additional homework tip 1

The coordinates of the feasible region are (−8,10),(6,3) and (−8,−18) .

The maximum value of the function is 42 at (6,3) and minimum value of the function is −140 at (−8,10) .

Explanation of Solution

Given information:

The inequalities x≥−8,3x+6y≤36 and 2y+12≥3x and the function f(x,y)=10x−6y .

Formula used:

Linear programming is a technique to find the maximum and the minimum value of a given function over a given system of some inequalities, with each inequality representing a constraint. Graph the inequalities and obtain the vertices of the feasible region (solution set). Substitute the coordinates of the feasible region in the function and determine the maximum and the minimum value.

Calculation:

Consider the provided system of inequalities x≥−8,3x+6y≤36 and 2y+12≥3x .

Recall that linear programming is a technique to find the maximum and the minimum value of a given function over a given system of some inequalities, with each inequality representing a constraint. Graph the inequalities and obtain the vertices of the feasible region (solution set).

Graph the given inequalities as,

  Algebra 2, Chapter 3.4, Problem 15PPS , additional homework tip 2

In the above graph, red region represents the inequality x≥−8 , blue region represents the inequality 3x+6y≤36 and green region represents 2y+12≥3x .

The feasible region is the region common to all the inequalities which is represented as,

  Algebra 2, Chapter 3.4, Problem 15PPS , additional homework tip 3

The coordinates of the vertices of the feasible region are (−8,10),(6,3) and (−8,−18) .

Now, to find the maximum and minimum value of the function, substitute the coordinates of the feasible region in the function and determine the maximum and the minimum value.

So, substitute (−8,10),(6,3) and (−8,−18) in the function f(x,y)=10x−6y and evaluate the maximum and minimum value as,

  (x,y)10x−6yf(x,y)(−8,10)10(−8)−6(10)−140(6,3)10(6)−6(3)42(−8,−18)10(−8)−6(−18)28

From the above table, it is observed that the maximum value of the function is 42 at (6,3) and minimum value of the function is −140 at (−8,10) .

Thus, graph of the given system of inequalities is,

  Algebra 2, Chapter 3.4, Problem 15PPS , additional homework tip 4

The coordinates of the feasible region are (−8,10),(6,3) and (−8,−18) and the maximum value of the function is 42 at (6,3) and minimum value of the function is −140 at (−8,10) .

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Chapter 3 Solutions

Algebra 2

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