Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3, Problem 2SGR
To determine

To fill: The blank in the statement “The ——————— is an algebraic method for solving systems of linear equations that eliminates a variable by adding or subtracting the equations”.

Expert Solution & Answer
Check Mark

Answer to Problem 2SGR

The complete statement is “The elimination method is an algebraic method for solving systems of linear equations that eliminates a variable by adding or subtracting the equations”.

Explanation of Solution

Given information:

The statement “The ——————— is an algebraic method for solving systems of linear equations that eliminates a variable by adding or subtracting the equations”.

Consider the provided statement “The ——————— is an algebraic method for solving systems of linear equations that eliminates a variable by adding or subtracting the equations”.

In a system of two or more equations add or subtract the equation if variable is same in both the equations. Then eliminate it accordingly.

For example: consider the system of equations

  x3y=62x+3y=6

Use the method of elimination to solve the system above.

Add both the equations,

  x3y=62x+3y=6+3x+0=12

Therefore,

  3x=12x=4

Now substitute x=4 in the equation x3y=6 ,

  43y=63y=2y=23

Therefore, solution is the coordinate pair, (4,32).

Thus, the complete statement is “The elimination method is an algebraic method for solving systems of linear equations that eliminates a variable by adding or subtracting the equations”.

Chapter 3 Solutions

Algebra 2

Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42HPCh. 3.1 - Prob. 43HPCh. 3.1 - Prob. 44HPCh. 3.1 - Prob. 45HPCh. 3.1 - Prob. 46HPCh. 3.1 - Prob. 47HPCh. 3.1 - Prob. 48HPCh. 3.1 - Prob. 49HPCh. 3.1 - 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Prob. 5ECh. 3.3 - Prob. 6ECh. 3.3 - Prob. 7ECh. 3.3 - Prob. 8ECh. 3.3 - Prob. 9ECh. 3.4 - Prob. 1ACYPCh. 3.4 - Prob. 1BCYPCh. 3.4 - Prob. 2ACYPCh. 3.4 - Prob. 2BCYPCh. 3.4 - Prob. 3CYPCh. 3.4 - Prob. 1CYUCh. 3.4 - Prob. 2CYUCh. 3.4 - Prob. 3CYUCh. 3.4 - Prob. 4CYUCh. 3.4 - Prob. 5CYUCh. 3.4 - Prob. 6CYUCh. 3.4 - Prob. 7CYUCh. 3.4 - Prob. 8PPSCh. 3.4 - Prob. 9PPSCh. 3.4 - Prob. 10PPSCh. 3.4 - Prob. 11PPSCh. 3.4 - Prob. 12PPSCh. 3.4 - Prob. 13PPSCh. 3.4 - Prob. 14PPSCh. 3.4 - Prob. 15PPSCh. 3.4 - Prob. 16PPSCh. 3.4 - Prob. 17PPSCh. 3.4 - Prob. 18PPSCh. 3.4 - Prob. 19PPSCh. 3.4 - Prob. 20PPSCh. 3.4 - Prob. 21PPSCh. 3.4 - Prob. 22PPSCh. 3.4 - Prob. 23PPSCh. 3.4 - Prob. 24PPSCh. 3.4 - Prob. 25PPSCh. 3.4 - Prob. 26PPSCh. 3.4 - Prob. 27PPSCh. 3.4 - Prob. 28PPSCh. 3.4 - Prob. 29PPSCh. 3.4 - Prob. 30HPCh. 3.4 - Prob. 31HPCh. 3.4 - Prob. 32HPCh. 3.4 - Prob. 33HPCh. 3.4 - Prob. 34HPCh. 3.4 - Prob. 35HPCh. 3.4 - Prob. 36HPCh. 3.4 - Prob. 37HPCh. 3.4 - Prob. 38STPCh. 3.4 - Prob. 39STPCh. 3.4 - Prob. 40STPCh. 3.4 - 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