Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3.2, Problem 52PPS

a.

To determine

To solve: the system of two equation that represents the number of students who rented two types of skates.

a.

Expert Solution
Check Mark

Answer to Problem 52PPS

  x+y=134x+2y=38 .

Explanation of Solution

Given:

Total number of students on a birthday party is 21.

And the rent for roller skates is $3 and single inline skates $5.

Total rent for 22 students is $96.

Calculation:

Let x be the number of roller skates and y be the number of inline skates.

As the total number of students invited in a birthday party is 21, and add one member who is inviting for birthday.

Therefore, total member is 22.

Therefore, according to the question,

  x+y=22 .

As the total rent for 22 students is $96. Therefore,

  3x+5y=96

Hence, the system of two equation is x+y=223x+5y=96 .

b.

To determine

To find: the number of students rented roller skates and inline skates.

b.

Expert Solution
Check Mark

Answer to Problem 52PPS

  Number of roller skates is 7 Andnumber of inline skates is 15 .

Explanation of Solution

Given:

Total number of students on a birthday party is 21.

And the rent for roller skates is $3 and single inline skates $5.

Total rent for 22 students is $96.

Calculation:

Let x be the number of roller skates and y be the number of inline skates.

From part (a),

  x+y=223x+5y=96 .

Now, solve the system of equation so that to find the number of matches of each kind are in progress.

Using elimination to find the value of system of equation.

Since none of the expressions is same on both the equation, therefore multiply by 3 in 1st equation and then equate:

  3(x+y)=22×33x+3y=66

Now, subtract the equation

  3x+3y=663x+5y=96_2y=30y=302=15

Now, substitutes the value of x in 1st equation, then:

  x+y=22x+15=22{y=15}x=2215x=7

Hence, the number of roller skates is 7 and number of inline skates is 15.

Chapter 3 Solutions

Algebra 2

Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42HPCh. 3.1 - Prob. 43HPCh. 3.1 - Prob. 44HPCh. 3.1 - Prob. 45HPCh. 3.1 - Prob. 46HPCh. 3.1 - Prob. 47HPCh. 3.1 - Prob. 48HPCh. 3.1 - Prob. 49HPCh. 3.1 - 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