Essentials Of Genetics (9th Global Edition)
9th Edition
ISBN: 9780134143637
Author: William S. Klug, Michael R. Cummings
Publisher: Pearson Global Edition
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 3, Problem 15PDQ
When working out genetics problems in this and succeeding chapters, alwaysassumethatmembersof the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.
Shown are F2 results of two of Mendel's monohybrid crosses. State a null hypothesis that you will test using chi-square analysis. Calculate the χ2 value and determine the p value for both crosses, then interpret the p values. Which cross shows a greater amount of deviation?
(a) Full pods | 882 |
Constricted pods | 299 |
(b) Violet flowers | 705 |
White flowers | 224 |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Question:
Suppose the progeny were crossed. Fill in the Punnett Squares below and answer the following questions.
Seed Color
Seed Shape
R
r
A
a
In a pea plant experiment, the allele (R) producing yellow seed color is dominant, and the allele (r) producing green seed color is recessive. A homozygous recessive genotype would produce green seeds. Similarly, the allele (A) producing round seed shape is dominant to the allele (a) that produces wrinkled seed shape. A homozygous recessive genotype would produce wrinkled seeds. Both traits sort independently of each other.
Given a pure-breeding cross between a round, green pea plant and a wrinkled yellow plant, complete the rest of the Punnett Squares below, and answer the following questions.
R
R
A
A
RA
Ra
Ra
ra
Question: This is a normal 3 point test cross, except that instead of regular phenotypes, you are looking at DNA markers on a gel. One parent, according to the gel, is heterozygous at each marker. The other parent is homozygous for each marker. (Again, this means it is a test cross: AaEeHh x AAEEHH --but don't be confused by that, because these are not "dominant" and "recessive" per se; the phenotype is just a band on a gel). For each offspring, figure out its genotype (homozygous or heterozygous for each gene. Then, figure that one parent made only AEH gametes, so you can cross that out if it helps.) Then treat it pretty much the same as a 3 point test cross.
Autosomal Recessive Problem: What is probability of individual 2 III in pedigree 1 and individual 1 III in pedigree 2 to have an affect child?
Chapter 3 Solutions
Essentials Of Genetics (9th Global Edition)
Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - CASE STUDY | To test or not to test Thomas first...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...
Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - Prob. 26PDQCh. 3 -
When working out genetics problems in this and...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- MODIFIED TRUE OR FALSE. In the following items, read each statement carefully. I. The Mendelian pattern of inheritance is a general term that refers to any pattern of inheritance in which traits do not segregate in accordance with Mendel’s lawsII. As an example, a characteristic may be controlled by one gene with two alleles, but the two alleles have a same relationship like the simple dominant-recessive relationship a. The first statement (I) is correct and the second statement (II) is wrong b. The first statement (I) is wrong and the second statement (II) is correct c. Both statements are correct d. Both statements are wrong MODIFIED TRUE OR FALSE. In the following items, read each statement carefully. I. The continuity of life from one cell to another has its foundation in the reproduction of cells by way of the cell cycle.II. The cell cycle is an orderly sequence of events in the life of a cell from the division of a single parent cell to produce…arrow_forwardInstruction: Solve for the genetic problems. a. Genotype of the parentsb. Phenotype of the parentsc. Punnett squared. Genotypic ratioe. Phenotypic ratio Question: Two individuals with widow’s peaks want to have a child with a continuous hairline. Is this possible?arrow_forwardpls dont copy existing answers or i will dislike your answer thanks Phenylketonuria (PKU) is a disorder caused by a recessive allele. Two carrier individuals have progeny. Answer the following questions in order and show solutions whenever relevant. 1. If they have a normal child, what is the probability that he or she will be heterozygous? 2. If they have three children, what is the probability of having 2 affected children and one normal child?arrow_forward
- Solving complex genetic problems with the rules of probability (3 traits) 1. Calculate the probability of getting an offspring of pea plant with the genotype, PpyyRr, when crossing PpYyRr and ppyyrr. Show your work. 2. States the phenotypes of the parents and offspring.arrow_forwardInstruction - Please answer them correctly - Please answer all of them, they are connected. PEDIGREE ANALYSIS and SYMBOLOGY Examine the pedigree which has X linked Dominant inheritance of disorder. Use letter X* (asterisk denotes disorder) as genotype of the individuals which can be XX, XY, X*X*, X*X and X*Y. a. What is the genotype of IV-6? b. What is the genotype of III-6? c. What is the genotype of II-3? d. What is the genotype of III-8? e. If couple I-1 and I-2 will have a son, what is the probability of having the disorder? f. If couple III-8 and III-9 will have another child, what is the probability of having the disorder? g. Theoretically, if individual IV-3 and individual IV-5 will marry and will have a child, what is the probability of having a child without the X-linked disorder?arrow_forwardPractice Pedigree Problem help. I am confused so please show. Label Phenotypes and genotypes as you go about the Pedigree (and whatever else might be required)! Thank you again for your help, these questions confuse me). Hair or fur length in cats is controlled by a single, autosomal gene; the short hair-allele is dominant to the allele for long hair. Hair color is produced by a different gene which is located on the X chromosome. One allele for this sex-linked gene produces yellow, while an alternate allele produces black fur color; individuals which are heterozygous for these alleles are calico or tortiseshell in color. a). If a long-haired, black male is mated with a calico female homozygous for short hair, what kind of kittens will be produced in the F1generation? Give both genotypes and phenotypes; express the genotypes both symbolically and in words.arrow_forward
- Hi, I'm having trouble with my study guide for my upcoming genetics exam. If someone could please help with work shown and an explanation it would help so much! Thank you!! 2a. The pedigree below represents inheritance of rare condition. What pattern of inheritance is most consistent with the data? Assign alleles to all individuals to support your answer. If an allele is unknown, assign it a ? symbol. NOTE: Individuals whose phenotype or genotype cannot be determined are assumed to be unaffected and homozygous, unless otherwise indicated. 2b. In addition to the alleles you’ve indicated, describe 2 overall features of the pedigree that make it consistent with your chosen form of inheritance. 2c. Based on your mode of inheritance, what is the probability that the child of couple IV-4 x IV-5 will be affected? Show your work. attached is the pedigreearrow_forwardNeed help, please. What are the ratios for the progeny phenotype(s)?arrow_forwardKeeping it in the family!”- How do you think consanguinity is increasing the risk factors of genetic disorders? Explain with examples (at least two). It won’t be possible to change the tradition all of a sudden. If you are a clinical geneticist, how you will be managing this type of community?arrow_forward
- GENETICS Question; 1. Give the genotypes and its ratio of the dihybrid cross of FIGURE 7. Regarding this problem, you may refer the genotype of the monohybrid cross of pea flower color in Figure 6.arrow_forwardQuestion: Red color (R) allele is dominant over blue color (r) for carnations (a type of flower). You will cross a heterozygous red carnation with a blue carnation. Show all your work filling out the required parts of the diagram. Then, select the correct statement below. (Picture below) 1. 75% red - 25% blue 75% heterozygous - 25% homozygous 2. 75% red - 25% blue 75% heterozygous - 25% homozygous 3. 50% red - 50% blue 50% heterozygous - 50% homozygous 4. 25% red - 75% blue 25% heterozygous - 75% homozygousarrow_forwardD) Genetics Problem show the table and word In certain breeds of chickens, the allele "B" is responsible for black feathers whereas the contrasting allele "b" produces feathers that are white. Another r pair of alleles influences the shape of the feathers. "F" produces straight feathers whereas the contrasting gene for "f results in the frizzled condition. Give the genotypic and phenotypic ratios to be expected from the following cross: white, frizzled hen with a heterozygous black, homozygous straight rooster. Genotypic Ratio: Phenotypic Ratio:arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY