Essentials Of Genetics (9th Global Edition)
9th Edition
ISBN: 9780134143637
Author: William S. Klug, Michael R. Cummings
Publisher: Pearson Global Edition
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Chapter 3, Problem 3PDQ
When working out genetics problems in this and succeeding chapters, alwaysassumethatmembersof the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.
In a cross between a black and a white guinea pig, all members of the F1 generation are black. The F2 generation is made up of approximately 3/4 black and 1/4 white guinea pigs. Diagram this cross, and show the genotypes and
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Unpacking the Problem 44John and Martha are contemplating having children, butJohn’s brother has galactosemia (an autosomal recessivedisease) and Martha’s great-grandmother also had galactosemia. Martha has a sister who has three children, none ofwhom have galactosemia. What is the probability that Johnand Martha’s first child will have galactosemia?1. Can the problem be restated as a pedigree? If so, writeone.2. Can parts of the problem be restated by using Punnettsquares?3. Can parts of the problem be restated by using branchdiagrams?4. In the pedigree, identify a mating that illustratesMendel’s first law.5. Define all the scientific terms in the problem, and lookup any other terms about which you are uncertain.6. What assumptions need to be made in answering thisproblem?7. Which unmentioned family members must be considered? Why?8. What statistical rules might be relevant, and in whatsituations can they be applied? Do such situations existin this problem?9. What are two generalities…
Question:
Suppose the progeny were crossed. Fill in the Punnett Squares below and answer the following questions.
Seed Color
Seed Shape
R
r
A
a
In a pea plant experiment, the allele (R) producing yellow seed color is dominant, and the allele (r) producing green seed color is recessive. A homozygous recessive genotype would produce green seeds. Similarly, the allele (A) producing round seed shape is dominant to the allele (a) that produces wrinkled seed shape. A homozygous recessive genotype would produce wrinkled seeds. Both traits sort independently of each other.
Given a pure-breeding cross between a round, green pea plant and a wrinkled yellow plant, complete the rest of the Punnett Squares below, and answer the following questions.
R
R
A
A
RA
Ra
Ra
ra
Question: This is a normal 3 point test cross, except that instead of regular phenotypes, you are looking at DNA markers on a gel. One parent, according to the gel, is heterozygous at each marker. The other parent is homozygous for each marker. (Again, this means it is a test cross: AaEeHh x AAEEHH --but don't be confused by that, because these are not "dominant" and "recessive" per se; the phenotype is just a band on a gel). For each offspring, figure out its genotype (homozygous or heterozygous for each gene. Then, figure that one parent made only AEH gametes, so you can cross that out if it helps.) Then treat it pretty much the same as a 3 point test cross.
Chapter 3 Solutions
Essentials Of Genetics (9th Global Edition)
Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - CASE STUDY | To test or not to test Thomas first...Ch. 3 -
CASE STUDY | To test or not to test
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When working out genetics problems in this and...
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