Essentials Of Genetics (9th Global Edition)
9th Edition
ISBN: 9780134143637
Author: William S. Klug, Michael R. Cummings
Publisher: Pearson Global Edition
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Chapter 3, Problem 27PDQ
When working out genetics problems in this and succeeding chapters, alwaysassumethatmembersof the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.
To assess Mendel's law of segregation using tomatoes, a true-breeding tall variety (SS) is crossed with a true-breeding short variety (ss). The heterozygous tall plants (Ss) were crossed to produce the two sets of F2 data as follows:
| Set 1 | Set II |
| 30 tall | 300 tall |
| 5 short | 50 short |
(a) Using chi-square analysis, analyze the results for both datasets. Calculate x2 values, and estimate the p values in both cases.
(b) From the analysis in part (a), what can you conclude about the importance of generating large datasets in experimental settings?
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Question:
Suppose the progeny were crossed. Fill in the Punnett Squares below and answer the following questions.
Seed Color
Seed Shape
R
r
A
a
In a pea plant experiment, the allele (R) producing yellow seed color is dominant, and the allele (r) producing green seed color is recessive. A homozygous recessive genotype would produce green seeds. Similarly, the allele (A) producing round seed shape is dominant to the allele (a) that produces wrinkled seed shape. A homozygous recessive genotype would produce wrinkled seeds. Both traits sort independently of each other.
Given a pure-breeding cross between a round, green pea plant and a wrinkled yellow plant, complete the rest of the Punnett Squares below, and answer the following questions.
R
R
A
A
RA
Ra
Ra
ra
Question: This is a normal 3 point test cross, except that instead of regular phenotypes, you are looking at DNA markers on a gel. One parent, according to the gel, is heterozygous at each marker. The other parent is homozygous for each marker. (Again, this means it is a test cross: AaEeHh x AAEEHH --but don't be confused by that, because these are not "dominant" and "recessive" per se; the phenotype is just a band on a gel). For each offspring, figure out its genotype (homozygous or heterozygous for each gene. Then, figure that one parent made only AEH gametes, so you can cross that out if it helps.) Then treat it pretty much the same as a 3 point test cross.
Unpacking the Problem 44John and Martha are contemplating having children, butJohn’s brother has galactosemia (an autosomal recessivedisease) and Martha’s great-grandmother also had galactosemia. Martha has a sister who has three children, none ofwhom have galactosemia. What is the probability that Johnand Martha’s first child will have galactosemia?1. Can the problem be restated as a pedigree? If so, writeone.2. Can parts of the problem be restated by using Punnettsquares?3. Can parts of the problem be restated by using branchdiagrams?4. In the pedigree, identify a mating that illustratesMendel’s first law.5. Define all the scientific terms in the problem, and lookup any other terms about which you are uncertain.6. What assumptions need to be made in answering thisproblem?7. Which unmentioned family members must be considered? Why?8. What statistical rules might be relevant, and in whatsituations can they be applied? Do such situations existin this problem?9. What are two generalities…
Chapter 3 Solutions
Essentials Of Genetics (9th Global Edition)
Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - CASE STUDY | To test or not to test Thomas first...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...
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When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - Prob. 26PDQCh. 3 -
When working out genetics problems in this and...
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- Question: Red color (R) allele is dominant over blue color (r) for carnations (a type of flower). You will cross a heterozygous red carnation with a blue carnation. Show all your work filling out the required parts of the diagram. Then, select the correct statement below. (Picture below) 1. 75% red - 25% blue 75% heterozygous - 25% homozygous 2. 75% red - 25% blue 75% heterozygous - 25% homozygous 3. 50% red - 50% blue 50% heterozygous - 50% homozygous 4. 25% red - 75% blue 25% heterozygous - 75% homozygousarrow_forwardInstruction - Please answer them correctly - Please answer all of them, they are connected. PEDIGREE ANALYSIS and SYMBOLOGY Examine the pedigree which has X linked Dominant inheritance of disorder. Use letter X* (asterisk denotes disorder) as genotype of the individuals which can be XX, XY, X*X*, X*X and X*Y. a. What is the genotype of IV-6? b. What is the genotype of III-6? c. What is the genotype of II-3? d. What is the genotype of III-8? e. If couple I-1 and I-2 will have a son, what is the probability of having the disorder? f. If couple III-8 and III-9 will have another child, what is the probability of having the disorder? g. Theoretically, if individual IV-3 and individual IV-5 will marry and will have a child, what is the probability of having a child without the X-linked disorder?arrow_forwardPEDIGREE ANALYSIS — please answer all of them, they are all connectedarrow_forward
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