Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 19P
To determine
The elevation of the curve at station
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A 1025 ft long vertical curve has a 4% grade on the back tangent and a -2% grade on the forward tangent. The PVC is located at sta 6+10 and has an elvation of 180 ft. At sta 8+31, what is the elevation of the vertical curve?
A 600-ft crest vertical curve is to be developed from a +1.80% grade intersecting with a-3.4% grade at Station 15+50.00 and elevation of 315.76 ft.a. Find the elevation and station of the highest point on the curve.b. Is the curve long enough for a design speed of 60 mph? Explain
A 777m equal tangent crest vertical curve has PVC at Sta 16+430 and at elevation 115m. The initial grade is 7.9% and the final grade is -3.3%. Determine the elevation (m) of PVT.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- The length of a sag vertical curve is 415 m with tangent grade if -2% and +4% intersecting at a point whose stationing is at 160+00 and elevation of 55 m above sea level. A pipe is to be positioned along the curve for drainage. The roadway at this point consists of two 3.6 m lanes with a normal crown slope of 2%. If surface of the roadway must clear the pipe by 0.75 m, what is the maximum elevation of the top of the pipe?arrow_forwardAn equal tangent crest vertical curve is designed for 65 mi/hr. The initial grade is 3.4% and the final grade is negative. What is the elevation difference between the PVC and the high point of the curve? Hand written work only pleasearrow_forwardA vertical sag curve has tangent grades of -3.6% and +4.8% meeting at point S whose elevation is 446.5 m. If the length of the curve is 420 m, find the elevation of the PC.arrow_forward
- A 400-ft equal tangent sag vertical to curve has its PC at station 100+00 and elevation 500ft. The initial grade is -4.0% and the final grade is +2.5%. Determine the elevation of the lowest point of curvaturearrow_forwardA +4% grade meets a -5% grade at sta 50+00. Using a 600 ft equal-tangent vertical curve, what is most nearly the distance from the point of vertical curvature (PVC) to the high point? A. 0.44 ft ahead from PVC B. 2.7 ft ahead from PVC C. 44 ft ahead from PVC D. 300 ft ahead from PVCarrow_forwardA 618m equal tangent crest vertical curve has PVC at Sta 19+218 and at elevation 177m. The initial grade is 4.05% and the final grade is -6.26%. Determine the elevation (m) of PVI. Round your answer to 3 decimal places.arrow_forward
- An equal-tangent crest vertical curve is designed for 70 mi/h. The high point is at elevation 1011.4 ft. The initial grade is +2% and the final grade is -1%. What is the elevation of the PVT?arrow_forwardAn equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. Design the curve.arrow_forwardA sag curve is being built under an existing overpass. The point of vertical intersection (PVI) of the proposed curve is at elevation 312 ft and the bottom of the overpass is at elevation 329 ft. The curve is being designed to match a -2.3% grade to a 2.5% grade at a design speed of 40 mph. If the curve is positioned to give maximum clearance to the overpass, will it provide at least 15 ft of clearance? Include a sketch of the curvearrow_forward
- A vertical summit curve connects a +6% grade to a -3% grade at Pl at station 150+ 00 whose elevation is 48 m A crossroad is located at statiion 150 + 70. Elevation of the centerline of the crossroad us 37.5m a.) Compute the length of the vertical curve needed to make the highest point on the vertical curve come out exacity over the centerline of the crossroad at station 150 + 70? b.) Compute the clearance between the profile grade on the vertical curve and the centerline of the crossroad? c.) If the design speed is 120kph determine the minimum length of the curve required considering. apperance criteria?arrow_forwarda 2300 ft equal tangent crest vertical curve is currently designed for 60 mph.this curve connects an initial grade of +3.5% and a negative grade, final grade what is the min k-value under 60 mph design speed use the min-k value as your deisn value determine A and G2 where is the highest point along curvearrow_forwardA 4.5% grade intersects a -1% grade at STA 5+180 at an elevation of 195m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the summit.arrow_forward
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