Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 36P
To determine
The possible lowest grade for the constant grade section that will still complete the alignment.
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A tangent section of highway has a -1.0% grade and ends at station 4+75 and elevation 82 ft. It must be connected to another section of highway that has a -1% grade and that begins at station 44+12 and elevation 131.2 ft. The connecting alignment should consist of a sag curve, and be designed for a speed of 50 mi/h. What is the lowest grade possible for the constant-grade section that will complete this alignment?
A 4.5% grade intersects a -1% grade at STA 5+180 at an elevation of 195m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the summit.
A 5.3% grade intersects a -1.9% grade at STA 5+180 at an elevation of 186m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the curve below PVI.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- 1) An equal-tangent crest vertical curve has a 50 mi/h design speed. The initial grade is +3%. The high point is at station 33+37.43 and the PVT is at station 37+18.26. What is the elevation difference between the high point and the PVT? 2) A 1400-ft-long sag vertical curve (equal tangent) has a PVC at stateion 115+00 and elevation 750ft. The intial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT. If you could show as many steps taken as possible that would be helpful in me actually understanding how to do the problem. Thanksarrow_forwardA vertical summit curve connects a +6% grade to a -3% grade at Pl at station 150+ 00 whose elevation is 48 m A crossroad is located at statiion 150 + 70. Elevation of the centerline of the crossroad us 37.5m a.) Compute the length of the vertical curve needed to make the highest point on the vertical curve come out exacity over the centerline of the crossroad at station 150 + 70? b.) Compute the clearance between the profile grade on the vertical curve and the centerline of the crossroad? c.) If the design speed is 120kph determine the minimum length of the curve required considering. apperance criteria?arrow_forwardA 1025 ft long vertical curve has a 4% grade on the back tangent and a -2% grade on the forward tangent. The PVC is located at sta 6+10 and has an elvation of 180 ft. At sta 8+31, what is the elevation of the vertical curve?arrow_forward
- A vertical parabolic happy curve underpass has a grade of -4% followed by a grade of 2% intersecting at Sta. 12+150.60 at elevation of 124.80 m above sea level. The change of grade of the sag curve is restricted to 0.6%. a. Compute the length of curve.arrow_forwardA parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.4% at sta. 10 + 020. The max. Allowable change of grade per 20 m. station is 0.15%. Elevation at station 10 + 020 is 240.60 m. Compute the lowest elevation point of the curve. CORRECT ANSWER: 240.81arrow_forwarda +7% grade meets a -4% grade at the vertex V with elevation of 30m and stationing of 2+000. It is required to connect the two tangents with an asymmetrical vertical parabolic curve, 60m on the back tangent and 40m on the forward tangent. Compute the elevation at station 1+950m.arrow_forward
- 25. A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.4% at sta. 10 + 020. The max. Allowable change of grade per 20 m. station is 0.15%. Elevation at station 10 + 020 is 240.60 m. Compute the lowest elevation point of the curve.arrow_forwardTwo tangents intersect at V with back tangent having a grade of -4% and forward tangent of 5%. A 205 m curve lies on the side of PC and 95 on the other side. Stationing of V is at 10+520 having an elevation of 103.5 m. If a bridge is located above the curve, with its centerline having an elevation of 120 m and stationing of 10+565, with underside of the bridge located 95 cm below the given elevation, determine the height of highest vehicle it can accommodate if the bridge has a width of 10 m.arrow_forwardA sag curve and crest curve connect -2.75% tangent section of highway (to the west) with -1.25% tangent section of highway (to be the east). The -1.25% tangent section is at higher elevation than the -2.75% tangent section. The two tangent section are separated by 450m of horizontal distance. If the design speed of the curve is 70KPH. Which of the following most nearly gives the common grade in percent between the sag and crest curvearrow_forward
- A -6% grade and a +2% intersect at Sta 12 + 200 whose elevation is at 14.375 m. The two grades are to be connected by a parabolic curve, 160 m long. Find the elevation of the first quarter point on the curve.arrow_forwardThe length of a sag vertical curve is 415 m with tangent grade if -2% and +4% intersecting at a point whose stationing is at 160+00 and elevation of 55 m above sea level. A pipe is to be positioned along the curve for drainage. The roadway at this point consists of two 3.6 m lanes with a normal crown slope of 2%. If surface of the roadway must clear the pipe by 0.75 m, what is the maximum elevation of the top of the pipe?arrow_forwardAn equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. Design the curve.arrow_forward
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