Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Chapter 3, Problem 15P
To determine
Whether the curve is long enough to provide passing sight distance for a
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A 800-ft equal-tangent sag vertical curve connects tangents that intersect at elevation 650 ft. The curve starts at station 20+30. The initial grade is -3.5% and the final grade is +2%. Determine the elevation of the middle point of the curve.
A 750-ft equal-tangent crest vertical curve connects tangents that intersect at elevation 572 ft. The curve starts at station 15+25. The initial grade is +5% and the final grade is -3%. Determine the elevation of the middle point of the curve.
An equal-tangent sag vertical curve is designed for 45 mi/h. The low point is 237 ft from the PVC at station 112 + 37 and the final offset at the PVT is 19.355 ft. If the PVC is at station 110 + 00, what is the elevation difference between the PVT and a point on the curve at station 111 + 00?
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- . An equal-tangent crest curve connects a +1.0%and a -0.5% grade. The PVC is at station 54 + 24 and the PVI is at station 56 + 92. Is this curve long enough to provide passing sight distance for a 60-mi/h design speed?arrow_forwardAn equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?arrow_forwardA 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forward
- a +7% grade meets a -4% grade at the vertex V with elevation of 30m and stationing of 2+000. It is required to connect the two tangents with an asymmetrical vertical parabolic curve, 60m on the back tangent and 40m on the forward tangent. Compute the elevation at station 1+950m.arrow_forwardA 4.5% grade intersects a -1% grade at STA 5+180 at an elevation of 195m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the summit.arrow_forwardAn equal-tangent crest vertical curve is designed for 70 mi/h. The high point is at elevation 1011.4 ft. The initial grade is +2% and the final grade is -1%. What is the elevation of the PVT?arrow_forward
- A 5.3% grade intersects a -1.9% grade at STA 5+180 at an elevation of 186m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the curve below PVI.arrow_forward1) An equal-tangent crest vertical curve has a 50 mi/h design speed. The initial grade is +3%. The high point is at station 33+37.43 and the PVT is at station 37+18.26. What is the elevation difference between the high point and the PVT? 2) A 1400-ft-long sag vertical curve (equal tangent) has a PVC at stateion 115+00 and elevation 750ft. The intial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT. If you could show as many steps taken as possible that would be helpful in me actually understanding how to do the problem. Thanksarrow_forwardA 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1% b) determine the highest and the lowest points on this vertical curve by using the K-value.arrow_forward
- An equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950 ft, the PVI at station 110 + 77 and elevation 947.34 ft, and the low point at station 110 + 50. Determine the design speed of the curve.arrow_forwardA 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -5% c) determine the desing speed for this vertical curve( in 10 km/h increments )arrow_forwardA 400-ft equal tangent sag vertical to curve has its PC at station 100+00 and elevation 500ft. The initial grade is -4.0% and the final grade is +2.5%. Determine the elevation of the lowest point of curvaturearrow_forward
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