Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 21P
To determine
The design speed of the curve.
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Students have asked these similar questions
An equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950 ft, the PVI at station 110 + 77 and elevation 947.34 ft, and the low point at station 110 + 50. Determine the design speed of the curve.
An equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?
A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -5%
c) determine the desing speed for this vertical curve( in 10 km/h increments )
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- An equal-tangent sag vertical curve is designed for 45 mi/h. The low point is 237 ft from the PVC at station 112 + 37 and the final offset at the PVT is 19.355 ft. If the PVC is at station 110 + 00, what is the elevation difference between the PVT and a point on the curve at station 111 + 00?arrow_forwardCompute the ruling minimum radius of horizontal curve for a design speed of 80 kph,f=0.18 and e = 0.078. For ruling minimum radius, increase the design speed by 16 kph.arrow_forwardA 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forward
- A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1% b) determine the highest and the lowest points on this vertical curve by using the K-value.arrow_forwardA 800-ft equal-tangent sag vertical curve connects tangents that intersect at elevation 650 ft. The curve starts at station 20+30. The initial grade is -3.5% and the final grade is +2%. Determine the elevation of the middle point of the curve.arrow_forwardA 750-ft equal-tangent crest vertical curve connects tangents that intersect at elevation 572 ft. The curve starts at station 15+25. The initial grade is +5% and the final grade is -3%. Determine the elevation of the middle point of the curve.arrow_forward
- A vertical parabolic curve has a back tangent of -5% and a forward tangent of +3% intersecting at station 1 + 240 at an elevation of 100.00 m. If the stationing of P.C. is at 1 + 120. Evaluate the stationing of the lowest point in the curve. Evaluate the elevation of the lowest point in the curve. Evaluate the rate of change of grade of the sag curve per 20 m length.arrow_forwardA vertical curve of 600 ft connects a +4% grade to a -2% grade. The elevation of the V.P.C. is 1,250 ft. Find the elevation of the PVI., the high point on the curve, and the VP.Tarrow_forwardA simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3 + 65.00 ft, what is the length (ft) of roadway to the first full station on the curve? The first full station occurs at 4+00arrow_forward
- An unsymmetrical parabolic curve has a forward tangent of -8% and a back tangent of +5%. The curve length on the left side is 40 m, while that of the right side is 60 m long. PC is at Sta 6+780 and elevation 110 m. Determine the value of the common grade.arrow_forwardA +3% grade intersects a -2% grade at STA 4+350 meter at an elevation of 190.50 meter. Given that a 250 meter symmetrical parabolic curve is used, find, draw and plot the elevation of the curve at every 20 meter interval starting at STA 4+240 meter including its critical point.arrow_forwardThe ascending of a vertical curve is 1/45 and descending gradient is 1/55. If the design speed is 60 km/hr and rate of change of acceleration of 0.4 m/s3, calculate the minimum length of the curve.arrow_forward
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