Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Chapter 3, Problem 28P
To determine
The highest possible value of the final grade in daytime conditions and in nighttime conditions.
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A sag curve is being built under an existing overpass. The point of vertical intersection (PVI) of the proposed curve is at elevation 312 ft and the bottom of the overpass is at elevation 329 ft. The curve is being designed to match a -2.3% grade to a 2.5% grade at a design speed of 40 mph. If the curve is positioned to give maximum clearance to the overpass, will it provide at least 15 ft of clearance? Please do all calculations in feet so I can check my answer. Include a sketch of the curve
Two vertical parabolic curves have been connected to form a roadway by three
gradients: -5.30 %, 4.10 % and -3.70 % respectively. If the length of the second
curve is twice as the length of the first curve, compute the following:
a. The length of the second curve in ft given that the design speed of the first
curve is 80 kph assuming a vertical radial acceleration of 0.3m/s2 for
comfort criterion.
b. The length of the second curve in m if the headlight height of the vehicle is
0.73 m above the first curve and the inclined upward angle of the headlight
beam relative to the horizontal plane of the vehicle is 1.57% The design
speed for the first curve for this situation is 90 kph.
c. The length of the first curve in yard if the total length of the roadway is 7451
m given that the second curve has a design speed of 70 kph for passing sight
distance with the driver's eye height assumed to be 1.5 m and object height
of 0.33 m.
d.The total length of the roadway in km if a bridge…
What is the length in stations for a symmetrical vertical curve with an entering grade of +5% which meets an existing grade of -2.5% at station 100+00 with an elevation of 100.00 ft? The r, rate of allowable change in grade, is -0.2%
2
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- A tangent section of highway has a -1.0% grade and ends at station 4+75 and elevation 82 ft. It must be connected to another section of highway that has a -1% grade and that begins at station 44+12 and elevation 131.2 ft. The connecting alignment should consist of a sag curve, and be designed for a speed of 50 mi/h. What is the lowest grade possible for the constant-grade section that will complete this alignment?arrow_forwardA 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forwardA vertical curve of 1,000-ft is designed to connect a grade of +4% to a grade of -5%. The V.P.I, is located at station 1,500 + 55 and has a known elevation of 500 ft. Find the following:a. The station of the V.P.C. and the V.P.T.b. The elevation of the VP.C. and the VPT1c. The elevation of points along the vertical curve at 100-ft intervalsd. "The location and elevation of the high point on the curve.arrow_forward
- A +0.7% grade meets a -0.4% grade at sta 2+700 and at elevation 30 m. The max allowable change in grade per station is 0.2%. Determine the length of the curve.arrow_forwardAn equal-tangent sag vertical curve is designed for 100 kph. The lowest point is at elevation 308.0 m. The initial grade is -2% and the final grade is +1%. What is the elevation of the PVC?arrow_forward1) An equal-tangent crest vertical curve has a 50 mi/h design speed. The initial grade is +3%. The high point is at station 33+37.43 and the PVT is at station 37+18.26. What is the elevation difference between the high point and the PVT? 2) A 1400-ft-long sag vertical curve (equal tangent) has a PVC at stateion 115+00 and elevation 750ft. The intial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT. If you could show as many steps taken as possible that would be helpful in me actually understanding how to do the problem. Thanksarrow_forward
- A 5.3% grade intersects a -1.9% grade at STA 5+180 at an elevation of 186m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the curve below PVI.arrow_forwardA sag curve is being built under an existing overpass. The point of vertical intersection (PVI) of the proposed curve is at elevation 312 ft and the bottom of the overpass is at elevation 329 ft. The curve is being designed to match a -2.3% grade to a 2.5% grade at a design speed of 40 mph. If the curve is positioned to give maximum clearance to the overpass, will it provide at least 15 ft of clearance? Include a sketch of the curvearrow_forwardA sag vertical curve is to be designed to join a -4% grade to a +2% grade. If the design speed is 45 mi/h, determine the minimum length of the curve that will satisfy all criteria. Assume a = 11.2 ft/sec2 and perception-reaction time t = 2.5 sec. Use g = 32.2 ft/sec2arrow_forward
- 5. A vertical sag curve consists of an initial grade of -3.5% with a final grade of +0.5%. The elevation for the point of vertical curvature (also known as beginning of vertical curve) is 1000 ft above MSL at Station 170+00. For a vertical curve length of 600ft, calculate the elevation, in ft, or the lowest point of the curve.arrow_forward1. A parabolic curve has an ascending grade of 4% which meets a descending grade of 3% at sta. 1+ 180 whose elevation is at 320 m. Compute the elevation of the PVT(point of vertical tangency) if the length of the curve is 280 m 2. The driver of a car traveling at 65 mph saw an obstruction ahead. If the reaction distance is 72.2 m, compute the reaction time.arrow_forwardA 1400-ft–long sag vertical curve (equal tangent) has a PVC at station 115 + 00 and elevation 750 ft. The initial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT.arrow_forward
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