Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 40P
To determine
The elevation difference between the two road segments.
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An equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?
A 1025 ft long vertical curve has a 4% grade on the back tangent and a -2% grade on the forward tangent. The PVC is located at sta 6+10 and has an elvation of 180 ft. At sta 8+31, what is the elevation of the vertical curve?
A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1%
b) determine the highest and the lowest points on this vertical curve by using the K-value.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- A vertical curve must begin at the center of manhole 1 (Sta. 56 + 000, Elev. 60 m) and end at manhole 2 (Sta. 56 + 231, Elev. 58.731 m). The entering grade (at manhole 1) of -4% and the exiting grade (at manhole 2) of +3% cannot be changed. It is required to design an asymmetrical vertical curve from manhole 1 to manhole 2. a. At what distance from manhole 1 will the two grades intersect in m? b. What is the grade of the line connecting the PI of the first vertical curve with the PI of the second vertical curve (g3) through the asymmetrical curve? c. What is the elevation of the compound vertical curvature point in m?arrow_forwardA vertical curve must begin at the center of manhole 1 (Sta. 56 + 000, Elev. 60 m) and end at manhole 2 (Sta. 56 + 231, Elev. 58.731 m). The entering grade (at manhole 1) of -4% and the exiting grade (at manhole 2) of +3% cannot be changed. It is required to design an asymmetrical vertical curve from manhole 1 to manhole 2. a. At what distance from manhole 1 will the two grades intersect in m? b. What is the grade of the line connecting the PI of the first vertical curve with the PI of the second vertical curve (g3) through the asymmetrical curve? c. What is the elevation of the compound vertical curvature point in m? (Please be mindful of the given values)arrow_forwardA vertical parabolic curve is to be used under a grade-separation structure. The curve is 250 m long and the minus grade of 3.8 percent intersects the plus grade of 5.4 percent at station of 0+120.424. Calculate the low point of the curve if the intersection at station 0+120.424 is at elevation 230.085 m.arrow_forward
- A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -5% c) determine the desing speed for this vertical curve( in 10 km/h increments )arrow_forward1. A parabolic curve has an ascending grade of 4% which meets a descending grade of 3% at sta. 1+ 180 whose elevation is at 320 m. Compute the elevation of the PVT(point of vertical tangency) if the length of the curve is 280 marrow_forwardA 4.5% grade intersects a -1% grade at STA 5+180 at an elevation of 195m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the summit.arrow_forward
- A symmetrical parabolic curve passes through point A whose elevation is 23.23 m at a distance of 54 m from the PVC. The elevation of the PVC at Station 4 + 100 is 22.56 m. The grade of the back tangent is +2% and the length of the curve is 120 marrow_forwardWhen my first grade is (g1) and the second grade is (g2), what type or vertical curve is created? "Summit curve" or "valley curve"? A. g1=10% ; g2=4% B. g1=-2% ; g2=6% C. g1=-5% ; g2=-2% D. g1=2% ; g2=6%arrow_forwardA vertical parabolic curve has a back tangent of -5% and a forward tangent of +3% intersecting at station 1 + 240 at an elevation of 100.00 m. If the stationing of P.C. is at 1 + 120. Evaluate the stationing of the lowest point in the curve. Evaluate the elevation of the lowest point in the curve. Evaluate the rate of change of grade of the sag curve per 20 m length.arrow_forward
- A vertical curve of 600 ft connects a +4% grade to a -2% grade. The elevation of the V.P.C. is 1,250 ft. Find the elevation of the PVI., the high point on the curve, and the VP.Tarrow_forwardA symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass through a point “P” the stationing of which is 35+280 and the elevation is 193.13 m. If the elevation of the grade intersection is 200 m with stationing 35 + 300. Determine the following: a. Length of the curve b. Determine the stationing and elevation of PC and PT.arrow_forwardA vertical summit curve connects a +6% grade to a -3% grade at Pl at station 150+ 00 whose elevation is 48 m A crossroad is located at statiion 150 + 70. Elevation of the centerline of the crossroad us 37.5m a.) Compute the length of the vertical curve needed to make the highest point on the vertical curve come out exacity over the centerline of the crossroad at station 150 + 70? b.) Compute the clearance between the profile grade on the vertical curve and the centerline of the crossroad? c.) If the design speed is 120kph determine the minimum length of the curve required considering. apperance criteria?arrow_forward
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