Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 20P
To determine
The elevation and stationing of the low pointPVI, and PVT.
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A 1400-ft–long sag vertical curve (equal tangent) has a PVC at station 115 + 00 and elevation 750 ft. The initial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT.
A 850-ft equal-tangent creat vertical cuve has its PVC at station 102+00 and elevation 1000 ft. The initial grade is 3.5% and the final grade is -3%. Determine the station of the highest point of the curve
A 500-ft-long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1322 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT.
Solve this problem using parabolic equation and offset method.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Similar questions
- A 777m equal tangent crest vertical curve has PVC at Sta 16+430 and at elevation 115m. The initial grade is 7.9% and the final grade is -3.3%. Determine the elevation (m) of PVT.arrow_forwardAn equal-tangent sag vertical curve is designed for 100 kph. The lowest point is at elevation 308.0 m. The initial grade is -2% and the final grade is +1%. What is the elevation of the PVC?arrow_forwardDetermine the minimum length (ft) for a vertical curve with 55mph design speed if the grades to be connected are -1.97% and 1.55%. Use the table provided by AASHTO.arrow_forward
- A 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forward-3% grade is connected to a +1.2% grade by means of 200 m vertical curve. The PJ station is 100+ 00 and the Pl is at elevation 100 m above sea level. What is the design sight distance for the curve?arrow_forwardA 591m equal tangent crest vertical curve has PVC at Sta 19+252 and at elevation 124m. The initial grade is 4.8% and the final grade is -5.97%. Determine the station of PVT.arrow_forward
- a +7% grade meets a -4% grade at the vertex V with elevation of 30m and stationing of 2+000. It is required to connect the two tangents with an asymmetrical vertical parabolic curve, 60m on the back tangent and 40m on the forward tangent. Compute the elevation at station 1+950m.arrow_forwardHighway engineering: A 520-ft–long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1325 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT.arrow_forwarda)A 1600-ft-long sag vertical curve (equal tangent) has a PVC at station 120+00 and elevation at 1500 ft. The initial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT. b) 1200-ft equal tangent crest vertical curve is currently designed for 50mph. A civil engineering student contends that 60mph is safe in a van because of the higher driver’s eye height in the van. If all the design inputs are standard, what must be the height of driver’s eye (in the van) for the student’s claim to be valid?arrow_forward
- An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. Design the curve.arrow_forwarda 2300 ft equal tangent crest vertical curve is currently designed for 60 mph.this curve connects an initial grade of +3.5% and a negative grade, final grade what is the min k-value under 60 mph design speed use the min-k value as your deisn value determine A and G2 where is the highest point along curvearrow_forwardA +4% grade meets a -5% grade at sta 50+00. Using a 600 ft equal-tangent vertical curve, what is most nearly the distance from the point of vertical curvature (PVC) to the high point? A. 0.44 ft ahead from PVC B. 2.7 ft ahead from PVC C. 44 ft ahead from PVC D. 300 ft ahead from PVCarrow_forward
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