EBK ELEMENTARY PRINCIPLES OF CHEMICAL P
4th Edition
ISBN: 9781119192107
Author: BULLARD
Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT
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Question
Chapter 3, Problem 3.15P
Interpretation Introduction
(a)
Interpretation:
Calculate the body weight and the body volume of the man.
Concept introduction:
Archimedes’ Principle is defined as:
The upward buoyant force that is exerted on a body immersed in a fluid is equal to the weight of the fluid that the body displaces or weight of the body immersed in a fluid.
This can be rewritten as,
Buoyant force (up) = Weight of block (down)
The specific gravity of the liquid is 0.996.
Interpretation Introduction
(b)
Interpretation:
Assume the body can be divided into nonfat and fat components. Derive an expression for the ratio of the mass of fat to mass of the whole body.
Concept introduction:
Assume the body can be divided into nonfat and fat components and the following notations are defined,
Fraction of total body mass that is fat =
Average density of the whole body =
Density of the fat component =
Density of the nonfat component =
Mass of the fat component =
Mass of the body =
Volume of the fat component =
Volume of the body =
This problem can be solved by, first derive expressions for the three densities then eliminate volumes algebraically so you can approach the final answer.
Interpretation Introduction
(c)
Interpretation:
Calculate the fraction of fat in a human body for the given case.
Concept introduction:
Assume the body can be divided into nonfat and fat components. The fraction of fat can be calculated using the following relationship.
Where,
Fraction of total body mass that is fat =
Average density of the whole body =
Density of the fat component =
Density of the nonfat component =
Interpretation Introduction
(d)
Interpretation:
Improve the estimation of
Concept introduction:
Assume the body can be divided into nonfat and fat components. The fraction of fat can be calculated using the following relationship.
Where,
Fraction of total body mass that is fat =
Average density of the whole body =
Density of the fat component =
Density of the nonfat component =
The above relationship includes the gas in tract, sinuses and lungs. The total volume is 1.4 liters. Assume that the mass of gas is negligible.
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In our chemistry laboratory class, the formula for surface tension given is y=mg/2(pi) x r x f where y=surface tension, m= mass of the drop, g= gravitational acceleration, pi is 3.1415, r= outer radius of burette, f=correction factor.
Now I searched the internet and it says that the unit for surface tension is kg x m/s^2. The problem is I have grams for the mass of the drop and that the outer radius of the burette is in centimeter while the gravitational acceleration is in meter. What will happen is like this:
(1 g x 9.8 m/s^2) / 2 (3.1415) x 0.15 cm x 0.74643 (correction factor no unit)
As you can see, if I don't cancel m and cm, the unit will be g x cm x m x s^2. However if change the radius of the burette into meter, it will cancel, the unit will be g x s^2 (missing meter).
What can I do to get kg x m/s^2 as the unit for final answer?
On December 1, 1783, Jacque Charles became the first human to pilot a non-tethered hydrogen balloon. He flew the balloon for fifteen miles and stayed in the air for a total flight time of 45 minutes. The balloon was made of silk coated with a thin layer of natural rubber and had a diameter of 27 feet. He generated the hydrogen gas needed to lift the balloon by mixing a large amount of iron with aqueous sulfuric acid. If he used 1 x 103 lbs. of iron and excess sulfuric acid, how many liters of hydrogen gas were made?
Fe(s) + H2SO4(aq) = FeSO4 (aq) + H2(g)
Chapter 3 Solutions
EBK ELEMENTARY PRINCIPLES OF CHEMICAL P
Ch. 3 - Perform the following estimations without using a...Ch. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - A rectangular block of solid carbon (graphite)...
Ch. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - 3.16. In April 2010, the worst oil spill ever...Ch. 3 - Prob. 3.17PCh. 3 - The following data have been obtained for the...Ch. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - A mixture of methanol and propyl acetate contains...Ch. 3 - The feed to an ammonia synthesis reactor contains...Ch. 3 - Prob. 3.24PCh. 3 - A mixture is 10.0 molc% methyl alcohol, 75.0 mole%...Ch. 3 - Certain solid substances, known as hydrated...Ch. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31PCh. 3 - Prob. 3.32PCh. 3 - Prob. 3.33PCh. 3 - Prob. 3.34PCh. 3 - Prob. 3.35PCh. 3 - Prob. 3.36PCh. 3 - Prob. 3.37PCh. 3 - Prob. 3.38PCh. 3 - Prob. 3.39PCh. 3 - Prob. 3.40PCh. 3 - Prob. 3.41PCh. 3 - Prob. 3.42PCh. 3 - Prob. 3.43PCh. 3 - Prob. 3.44PCh. 3 - Prob. 3.45PCh. 3 - Prob. 3.46PCh. 3 - In the movie, Willy Wonka and the Chocolate...Ch. 3 - Prob. 3.48PCh. 3 - Prob. 3.49PCh. 3 - Prob. 3.50PCh. 3 - Prob. 3.51PCh. 3 - Prob. 3.52PCh. 3 - Prob. 3.53PCh. 3 - Prob. 3.54PCh. 3 - Prob. 3.55PCh. 3 - Prob. 3.56PCh. 3 - Prob. 3.57PCh. 3 - Prob. 3.58PCh. 3 - Prob. 3.59PCh. 3 - Prob. 3.60PCh. 3 - Prob. 3.61PCh. 3 - Prob. 3.62PCh. 3 - Convert the temperatures in Parts (a) and (b) and...Ch. 3 - Prob. 3.64PCh. 3 - Prob. 3.65PCh. 3 - Prob. 3.66PCh. 3 - Prob. 3.67PCh. 3 - Prob. 3.68PCh. 3 - Prob. 3.69P
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