Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
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Question
Chapter 38, Problem 53P
(a)
To determine
The graph showing the valence and
(b)
To determine
The graph showing the valence and conduction band edges and Fermi energy of a
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Students have asked these similar questions
In a p-n junction diode, the current I can be expressed as
eV
1= 1, exp
( 2k„T
where I, is called the reverse saturation current, V is the voltage across the diode and is
positive for forward bias and negative for reverse bias, and I is the current through the
diode, køis the Boltzmann constant (8.6x10- eV/K) and T is the absolute temperature.
If for a given diode I, = 5 x 10-12 A and T = 300 K, then
(a) What will be the forward current at a forward voltage of 0.6 V?
1.0 Biased PN Junctions
Consider two PN diodes, A and B as depicted below. Suppose the junction area for
each diode is 1.0 x10-8 cm² (1 square-micron)
P-doped
N-doped
N = 1016 1/ cm3
Ng = 1017 1/cm³
X,
*po
Vo
в
P-doped
Na = 1018 1/cm3
N-doped
Ng = 1017 1/cm3
Х ро
Xno
V.
a) At VD =0 Volts, which diode has the wider total depletion region width (value
(in microns) and what is it?
b) At Vp =0 Volts, in which diode the magnitude of the maximum electric field in
the depletion region is the largest and what is its value (in V/cm)?
c) Under a reverse bias Vp <0, which diode will breakdown first (i.e. at a
smaller magnitude of the negative bias).
Q/ A Germanium p-n junction diode has a reverse saturation current of
3.97 x 10-19A at room temperature. The diode is forward-biased with a
voltage source of 1 V. Calculate the dynamic resistance of the Ge diode at
room temperature.
Chapter 38 Solutions
Physics for Scientists and Engineers, Vol. 1
Ch. 38 - Prob. 1PCh. 38 - Prob. 2PCh. 38 - Prob. 3PCh. 38 - Prob. 4PCh. 38 - Prob. 5PCh. 38 - Prob. 6PCh. 38 - Prob. 7PCh. 38 - Prob. 8PCh. 38 - Prob. 9PCh. 38 - Prob. 10P
Ch. 38 - Prob. 11PCh. 38 - Prob. 12PCh. 38 - Prob. 13PCh. 38 - Prob. 14PCh. 38 - Prob. 15PCh. 38 - Prob. 16PCh. 38 - Prob. 17PCh. 38 - Prob. 18PCh. 38 - Prob. 19PCh. 38 - Prob. 20PCh. 38 - Prob. 21PCh. 38 - Prob. 22PCh. 38 - Prob. 23PCh. 38 - Prob. 24PCh. 38 - Prob. 25PCh. 38 - Prob. 26PCh. 38 - Prob. 27PCh. 38 - Prob. 28PCh. 38 - Prob. 29PCh. 38 - Prob. 30PCh. 38 - Prob. 31PCh. 38 - Prob. 32PCh. 38 - Prob. 33PCh. 38 - Prob. 34PCh. 38 - Prob. 35PCh. 38 - Prob. 36PCh. 38 - Prob. 37PCh. 38 - Prob. 38PCh. 38 - Prob. 39PCh. 38 - Prob. 40PCh. 38 - Prob. 41PCh. 38 - Prob. 42PCh. 38 - Prob. 43PCh. 38 - Prob. 44PCh. 38 - Prob. 45PCh. 38 - Prob. 46PCh. 38 - Prob. 47PCh. 38 - Prob. 48PCh. 38 - Prob. 49PCh. 38 - Prob. 50PCh. 38 - Prob. 51PCh. 38 - Prob. 52PCh. 38 - Prob. 53PCh. 38 - Prob. 54PCh. 38 - Prob. 55PCh. 38 - Prob. 56PCh. 38 - Prob. 57PCh. 38 - Prob. 58PCh. 38 - Prob. 59PCh. 38 - Prob. 60PCh. 38 - Prob. 61PCh. 38 - Prob. 62PCh. 38 - Prob. 63PCh. 38 - Prob. 64PCh. 38 - Prob. 65PCh. 38 - Prob. 66PCh. 38 - Prob. 67PCh. 38 - Prob. 68PCh. 38 - Prob. 69PCh. 38 - Prob. 70PCh. 38 - Prob. 71PCh. 38 - Prob. 72PCh. 38 - Prob. 73PCh. 38 - Prob. 74PCh. 38 - Prob. 75PCh. 38 - Prob. 76P
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Similar questions
- Why does the horizontal Line in the graph in Figure 9.12 suddenly stop at the Fermi energy? Figure 9.12 (a) Density of state for a free electron gas; (b) probability that a state is occupied at T = 0 K; (c) density if occupied states at T = 0 k.arrow_forwardTo obtain a more clearly defined picture of the FermiDirac distribution, consider a system of 20 FermiDirac particles sharing 94 units of energy. By drawing diagrams like Figure P10.11, show that there are nine different microstates. Using Equation 10.2, calculate and plot the average number of particles in each energy level from 0 to 14E. Locate the Fermi energy at 0 K on your plot from the fact that electrons at 0 K fill all the levels consecutively up to the Fermi energy. (At 0 K the system no longer has 94 units of energy, but has the minimum amount of 90E.) 1 Microstate8 others? One of the nine equally probable microstates for 20 FD particles with a total energy of 94E.arrow_forwardConsider a simple pn-junction diode. Suppose this diode carries a current of 50 mA with a forward bias voltage of 200 mV at room temperature (293 K). What is the current when a reverse bias of 200 mV is applied?arrow_forward
- = Consider a silicon pn junction diode at T 300K. The reverse saturation current is ls 10-14 A and the ideality factor n = 1. Determine the diode current for a diode voltage of VD = 0.685 V and use that to determine the DC and AC resistance of the diode. RDC = 307 Q2 = rac =7Ω RDC = 224 22 rac 8 Ω RDC = 115 Q2 = rac = 40 RDC = 36 Q rac = 10arrow_forwardLet's look at a copper crystal, where each copper atom donates one conduction electron to the crystal. a) Use the free electron model to determine the prediction for copper fermi energy EF, fermi temperature TF and degeneration pressure Pdeg (at temperature T = 0 K). b) Further calculate the contribution of the degeneration pressure to the isothermal compression coefficient of copper. B = -V др (SP) T c) Finally, determine the model prediction for the electronic molar specific heat capacity Cy . The empirical form for this is Cy = yT and the experimentally determined value for copper is Y = 0.695 mJ mol-¹ k-². = Compare this numerical value with your resultarrow_forward
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