Chapter 4, Problem 25A

(a)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

Answer to Problem 25A

Formula of compound is Li₂O.

Explanation of Solution

Formula of compound is Li₂O as charge on Lithium ion is +1 and that on oxide ion is -2.

(b)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

Answer to Problem 25A

Formula of compound is AlI₃.

Explanation of Solution

Formula of compound is AlI₃ as charge on Aluminium ion is +3 and that on iodide ion is -1.

(c)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

Answer to Problem 25A

Formula of compound is Ag₂O.

Explanation of Solution

Formula of compound is Ag₂O as charge on Silver ion is +1 and that on oxide ion is -2.

(d)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

Answer to Problem 25A

Formula of compound is K₃N.

Explanation of Solution

Formula of compound is K₃N as charge on Potassium ion is +1 and that on nitride ion is -3.

(e)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

Answer to Problem 25A

Formula of compound is Ca₃P₂.

Explanation of Solution

Formula of compound is Ca₃P₂ as charge on Calcium ion is +2 and that on phosphide ion is -3.

(f)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

Answer to Problem 25A

Formula of compound is MgF₂.

Explanation of Solution

Formula of compound is MgF₂ as charge on Magnesium ion is +2 and that on fluoride ion is -1.

(g)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

Answer to Problem 25A

Formula of compound is Na₂S.

Explanation of Solution

Formula of compound is Na₂S as charge on Sodium ion is +1 and that on sulfide ion is -1.

(h)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

Answer to Problem 25A

Formula of compound is BaH₂.

Explanation of Solution

Formula of compound is BaH₂ as charge on Barium ion is +2 and that on hydride ion is -1.