Chapter 4, Problem 47A

(a)

Interpretation Introduction

Interpretation: The formula for simple binary ionic compound calcium chloride is to be named.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 47A

  ${\text{CaCl}}_{\text{2}}$

Explanation of Solution

The given compound is calcium chloride. Here, Ca has +2 charge and Cl has -1 charge. Thus, Ca and Cl must be combined in 1:2 ratio to form CaCl₂.

Name	Formula	Comments
Calcium chloride	${\text{CaCl}}_{\text{2}}$	Contains two ${\text{Cl}}^{-}$ to balance, Ca (Group 2) always forms ${\text{Ca}}^{2+}$.

(b)

Interpretation Introduction

Interpretation: The formula for simple binary ionic compound silver (I) oxide is to be named.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 47A

  ${\text{Ag}}_{\text{2}}\text{O}$

Explanation of Solution

Given ionic compound is silver (I) oxide. Here, silver has +1 charge and O has -2 charge. Thus, Ag and O must be combined in 2:1 ratio.

Name	Formula
Silver(I) oxide	${\text{Ag}}_{\text{2}}\text{O}$

(c)

Interpretation Introduction

Interpretation: The formula for simple binary ionic compound aluminium sulfide is to be named.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 47A

  ${\text{Al}}_{\text{2}}{\text{S}}_{\text{3}}$

Explanation of Solution

The given compound is aluminium sulfide. Here, Al has +3 charge and sulfur has -2 charge thus, Al and S must be combined in 2:3 ratio.

Name	Formula
Aluminum sulfide	${\text{Al}}_{\text{2}}{\text{S}}_{\text{3}}$

(d)

Interpretation Introduction

Interpretation: The formula for simple binary ionic compound beryllium bromide is to be named.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 47A

  ${\text{BeBr}}_{\text{2}}$

Explanation of Solution

The given compound is beryllium bromide. The charge on Be is 2+ and that on Br is -1 thus, Be and Br must be combined in 1:2 ratio.

Name	Formula
Beryllium bromide	${\text{BeBr}}_{\text{2}}$

(e)

Interpretation Introduction

Interpretation: The formula for simple binary ionic compounds is to be named.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 47A

  ${\text{H}}_{\text{2}}\text{S}$

Explanation of Solution

The given compound is hydrogen sulfide or hydrosulfuric acid. Here, H has +1 charge and S has -2 charge thus, H and S must be combined in 2:1 ratio.

Name	Formula	Comments
Hydro sulfuric acid	${\text{H}}_{\text{2}}\text{S}$	2 ${\text{H}}^{\text{+}}$ to balance ${\text{S}}^{\text{2-}}$

(f)

Interpretation Introduction

Interpretation: The formula for simple binary ionic compound potassium hydride is to be named.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 47A

KH.

Explanation of Solution

The given compound is potassium hydride. The charge on K is +1 and that on H is -1 thus, they ,must be combined in 1:1 ratio.

Name	Formula
Potassium hydride	KH

(g)

Interpretation Introduction

Interpretation: The formula for simple binary ionic compound magnesium iodide is to be named.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 47A

  ${\text{MgI}}_2$

Explanation of Solution

The given compound is magnesium iodide. Here, Mg has +2 charge and I has -1 charge. In the formula, Mg and I must be combined in 1:2 ratio.

Name	Formula
Magnesium iodide	${\text{MgI}}_2$

(h)

Interpretation Introduction

Interpretation: The formula for simple binary ionic compound cesium fluoride is to be named.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 47A

  $\text{CsF}$

Explanation of Solution

The given compound is cesium fluoride. Here, Cs has +1 charge and F has -1 charge thus, Cs and F must be combined in 1:1 ratio.

Name	Formula
Cesium fluoride	$\text{CsF}$