Chapter 4, Problem 32A

(a)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

Answer to Problem 32A

Gold (III) bromide

Explanation of Solution

Gold has more than one oxidation state. So, binary compound is of type −II.

Rules for naming these compounds:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

In the formula, $AuB{r}_3$ gold is attached to three bromine atoms. It means its oxidation state is three. So the name is Gold (III) bromide.

(b)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

Answer to Problem 32A

Cobalt (III) cyanide

Explanation of Solution

Cobalt has more than one oxidation state. So, binary compound is of type −II.

Rules for naming these compounds:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

In the formula, $Co{\left(CN\right)}_3$ gold is attached to three cyanide ions. It means its oxidation state is three. So the name is Cobalt (III) cyanide.

(c)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

Answer to Problem 32A

Magnesium hydrogen phosphate

Explanation of Solution

Magnesium has one oxidation state. So, binary compound is of type −I. it is combined with polyatomic ion.

Rules for naming these compounds:

• Name of metal cation is written as name of element.
• Name of anion is written
• Writing these names in the same sequence gives the name of compound.

In the formula, $MgHP{O}_4$ magnesium is attached to hydrogen phosphate group. So the name is Magnesium hydrogen phosphate.

(d)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

Answer to Problem 32A

Diboron hexahydride

Explanation of Solution

The binary compound is of type −III.

Rules for naming these compounds:

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for first element.

In the formula, $B_2{H}_6$ two boron atoms are attached to six hydrogen atoms. So the name is diboron hexahydride.

(e)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

Answer to Problem 32A

Nitrogen trihydride or ammonia.

Explanation of Solution

The binary compound is of type −III.

Rules for naming these compounds:

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for first element.

In the formula, $N{H}_3$ one nitrogen atom is attached to three hydrogen atoms. So the name is Nitrogen trihydride or ammonia.

(f)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

Answer to Problem 32A

Silver sulphate

Explanation of Solution

Silver has one oxidation state. So, binary compound is of type −I. it is combined with polyatomic ion sulphate.

Rules for naming these compounds:

• Name of metal cation is written as name of element.
• Name of anion is written
• Writing these names in the same sequence gives the name of compound.

In the formula, $A{g}_{2}S{O}_4$ silver is attached to sulphate group. So the name is silver sulphate.

(g)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

Answer to Problem 32A

Berrylium hydroxide

Explanation of Solution

Berrylium has one oxidation state. So, binary compound is of type −I. it is combined with hydroxide ion.

Rules for naming these compounds:

• Name of metal cation is written as name of element.
• Name of anion is written
• Writing these names in the same sequence gives the name of compound.

In the formula, $Be{\left(OH\right)}_2$ berrylium is attached to hydroxide group. So the name is Berrylium hydroxide.