Chapter 4, Problem 50A

(a)

Interpretation Introduction

Interpretation: Correct formula of the ionic compounds needs to be determined.

Concept introduction: Ionic compounds are made up of positive and negative ions. The name of the ionic compounds is written such that the name of the cation is written first followed by the name of the anion.

Generally, the names of the polyatomic anion ends with −ate with a few exceptions.

Answer to Problem 50A

Correct formula for “a” is ${\text{AgClO}}_4.$

Explanation of Solution

Cation is ${\text{Ag}}^{+}$ (silver) and anion is ${\text{ClO}}_{\text{4}}{}^{-}$ (perchlorate). To make the compound neutral we need one ${\text{Ag}}^{+}$ and one ${\text{ClO}}_{\text{4}}{}^{-}.$

(b)

Interpretation Introduction

Interpretation: Correct formula of the ionic compounds needs to be determined.

Concept introduction: Ionic compounds are made up of positive and negative ions. The name of the ionic compounds is written such that the name of the cation is written first followed by the name of the anion.

Generally, the names of the polyatomic anion ends with −ate with a few exceptions.

Answer to Problem 50A

Correct formula for “b” is $\text{Co}{\left(\text{OH}\right)}_3.$

Explanation of Solution

Cation is ${\text{Co}}^{3+}$ (cobalt) and anion is ${\text{OH}}^{-}$ (hydroxide). To make the compound neutral we need one ${\text{Co}}^{3+}$ and three ${\text{OH}}^{-}.$

(c)

Interpretation Introduction

Interpretation: Correct formula of the ionic compounds needs to be determined.

Concept introduction: Ionic compounds are made up of positive and negative ions. The name of the ionic compounds is written such that the name of the cation is written first followed by the name of the anion.

Generally, the names of the polyatomic anion ends with −ate with a few exceptions.

Answer to Problem 50A

Correct formula for “c” is $\text{NaOCl}.$

Explanation of Solution

Cation is ${\text{Na}}^{+}$ (sodium) and anion is ${\text{ClO}}^{-}$ (hypochlorite). To make the compound neutral we need one ${\text{Na}}^{+}$ and one ${\text{ClO}}^{-}.$

(d)

Interpretation Introduction

Interpretation: Correct formula of the ionic compounds needs to be determined.

Concept introduction: Ionic compounds are made up of positive and negative ions. The name of the ionic compounds is written such that the name of the cation is written first followed by the name of the anion.

Generally, the names of the polyatomic anion ends with −ate with a few exceptions.

Answer to Problem 50A

Correct formula for “d” is ${\text{K}}_{\text{2}}{\text{Cr}}_{\text{2}}{\text{O}}_{\text{7}}.$

Explanation of Solution

Cation is ${\text{K}}^{+}$ (potassium) and anion is ${\text{Cr}}_{\text{2}}{\text{O}}_{\text{7}}{}^{2-}$ (chromate). To make the compound neutral we need two ${\text{K}}^{\text{+}}$ and one ${\text{Cr}}_{\text{2}}{\text{O}}_{\text{7}}{}^{2-}.$

(e)

Interpretation Introduction

Interpretation: Correct formula of the ionic compounds needs to be determined.

Concept introduction: Ionic compounds are made up of positive and negative ions. The name of the ionic compounds is written such that the name of the cation is written first followed by the name of the anion.

Generally, the names of the polyatomic anion ends with −ate with a few exceptions.

Answer to Problem 50A

Correct formula for “e” is ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{2}}.$

Explanation of Solution

Cation is ${\text{NH}}_{\text{4}}{}^{+}$ (ammonium) and anion is ${\text{NO}}_{\text{2}}{}^{-}$ (nitrite). To make the compound neutral we need one ${\text{NH}}_{\text{4}}{}^{+}$ and one ${\text{NO}}_{\text{2}}{}^{-}.$

(f)

Interpretation Introduction

Interpretation: Correct formula of the ionic compounds needs to be determined.

Concept introduction: Ionic compounds are made up of positive and negative ions. The name of the ionic compounds is written such that the name of the cation is written first followed by the name of the anion.

Generally, the names of the polyatomic anion ends with −ate with a few exceptions.

Answer to Problem 50A

Correct formula for “f” is ${\text{Fe(OH)}}_{\text{3}}.$

Explanation of Solution

Cation is ${\text{Fe}}^{\text{3+}}$ (iron) and anion is ${\text{OH}}^{-}$ (hydroxide).To make the compound neutral we need one ${\text{Fe}}^{\text{3+}}$ and three ${\text{OH}}^{-}.$

(g)

Interpretation Introduction

Interpretation: Correct formula of the ionic compounds needs to be determined.

Concept introduction: Ionic compounds are made up of positive and negative ions. The name of the ionic compounds is written such that the name of the cation is written first followed by the name of the anion.

Generally, the names of the polyatomic anion ends with −ate with a few exceptions.

Answer to Problem 50A

Correct formula for “g” is ${\text{NH}}_{\text{4}}{\text{HCO}}_{\text{3}}.$

Explanation of Solution

Cation is ${\text{NH}}_{\text{4}}{}^{+}$ (ammonium) and anion is ${\text{HCO}}_{\text{3}}{}^{-}$ (hydrogen carbonate). To make the compound neutral we need one ${\text{NH}}_{\text{4}}{}^{+}$ and one ${\text{HCO}}_{\text{3}}{}^{-}.$

(h)

Interpretation Introduction

Interpretation: Correct formula of the ionic compounds needs to be determined.

Concept introduction: Ionic compounds are made up of positive and negative ions. The name of the ionic compounds is written such that the name of the cation is written first followed by the name of the anion.

Generally, the names of the polyatomic anion ends with −ate with a few exceptions.

Answer to Problem 50A

Correct formula for “h” is ${\text{KBrO}}_{\text{4}}.$

Explanation of Solution

Cation is ${\text{K}}^{+}$ (potassium) and anion is ${\text{BrO}}_4{}^{-}$ (perbromate). To make the compound neutral we need one ${\text{K}}^{+}$ and one ${\text{BrO}}_4{}^{-}.$