Chapter 4, Problem 4.51AP

Interpretation Introduction

(a)

Interpretation:

The two structures from which $\text{1-bromo-1-methylcyclopentane}$ can be formed on addition of $\text{HBr}$ are to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with $\text{HBr}$, a alkyl bromide is formed. The substitution of $\text{HBr}$ in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Interpretation Introduction

(b)

Interpretation:

Whether the products will be same or not when $\text{1-methylcyclopent-1-ene}$ and $\text{1-methylenecyclopentane}$ reacts with $\text{DBr}$ is to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with $\text{HBr}$, an alkyl bromide is formed. The substitution of $\text{HBr}$ in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.