Steel Design (Activate Learning with these NEW titles from Engineering!)
Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 5, Problem 5.5.4P
To determine

(a)

To find: if A 992 steel W12×35 is adequate using LRFD method.

To determine

(b)

To find: whether A 992 steel W12×35 is adequate using ASD method.

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A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member.  It is 7 m long, pinned at the top fixed at bottom, and has additional support in the weak direction 3 m from the top.  Properties of the section are as follows:          A = 14,500 mm^2         Ix = 258.6 x 10^6 mm^4         Iy = 84.375 x 10^6 mm^4 1. calculate the nominal axial load capacity of the column a. 3104 kN b. 4851 kN c. 4213 kN d. 5344 kN 2. calculalte the service axial dead load if the service axial live load is twice as that of the dead load. Use LRFD. a. 1354 kN b. 992 kN c. 1093 kN d. 634 kN
How much service live load, in kips per foot, can be supported? The member weight is the only dead load. The axial compressive load consists of a service dead load of 10 kips and a service live load of 20 kips. Do not consider moment amplification. Bending is about the x axis, and the steel is A992.                 a. Use LRFD.                                                                                                           b. Use ASD.
A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6  mm ^4 Iy=84.375 x 10^6 mm^4.   57. Calculate the flexural buckling stress Fcr in MPa

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Steel Design (Activate Learning with these NEW titles from Engineering!)

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Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning