Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Question
Chapter 5, Problem 5.5.5P
To determine
(a)
To find whether W 18X 60 of A992 steel is adequate using LFRD method.
To determine
(b)
To find whether W 18X 60 of A992 steel is adequate using ASD method.
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2. The beam shown in Figure P5.8-3 is a W16 × 31 of A992 steel and has continuous lateral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate for flexure and shear.
a. Use LRFD. b. Use ASD.
A W 360 x 744 is used as a beam to support a concrete floor system. The floor is to carry atotal load of 250 kPa. The beam is simply supported over a span of 6 m. Assume the beamis laterally supported over its length. Use A36 steel with Fy = 250 MPa. Allowabledeflection is L/360.a. Determine the center to center spacing of the beams without exceeding the allowableshear stress.b. Determine the center to center spacing of the beams without exceeding the allowablebending stress.c. Determine the center to center spacing of the beams without exceeding the allowabledeflection.
A W21 3 68 of A992 steel is used as a simply supported beam with a span length of 50 feet. The only load in addition to the beam weight is a uniform live load. If lateral support is provided at 10-foot intervals, what is the maximum service live load, in kipsyft, that can be supported? a. Use LRFD. b. Use ASD.
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
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- If the beam in Problem 5.5-9 i5 braced at A, B, and C, compute for the unbr Cb aced length AC (same as Cb for unbraced length CB). Do not include the beam weight in the loading. a. Use the unfactored service loads. b. Use factored loads.arrow_forwardA plate girder must be designed for the conditions shown in Figure P10.7-4. The given loads are factored, and the uniformly distributed load includes a conservative estimate of the girder weight. Lateral support is provided at the ands and at the load points. Use LRFD for that following: a. Select the, flange and web dimensions so that intermediate stiffeners will he required. Use Fy=50 ksi and a total depth of 50 inches. Bearing stiffeners will be used at the ends and at the load points, but do not proportion them. b. Determine the locations of the intermediate stiffeners, but do not proportion them.arrow_forwardRead the question carefully and give me right solution according to the question. A W12x79 of A573 Grade 60 (Fy=415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at the bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows: A = 14,500 mm^2 Ix = 258.6 x 10^6 mm^4 Iy = 84.375 x 10^6 mm^4 Calculate the effective slenderness ratio with respect to strong axis buckling using theoretical value of k.arrow_forward
- The beam in the figure carries a uniform load of 20 kN/m including its own weight, a concentrated load of 400 kN at 2.4 m from the left support and another concentrated load at 280 kNat 1.2 m from right end. The beam is laterally unsupported except at the two vertical ends. The beam is to be made of W 16 x 77. Use AISC Specifications for A36 steel Fy= 248.69 MPa. a. Determine the maximum bending moment of the beam. b. Determine the maximum or actual flexural stress of the beam. c. Determine the allowable flexural stress of the beam. d. Is it safe to use the said steel as beam? Why?arrow_forward5.5-9 The beam shown in Figure P5.5-9 is a W36 x 182. It is laterally supported at A and B. The 300 kip load is a service live load. Using the unfactored service loads, a. Compute Cb. Do not include the beam weight in the loading b. Compute Cb, Include the beam weight in the loadingarrow_forwardThe T-beam in the floor system has a slab thickness of 90 mm and supported by beams 6.5 m span. The beam is casts monolithically with the slab. The spacing of beams is 2 m on centers and width the web is 400 mm. The effective depth of the beam is 600 mm. It is reinforced at tension side with 8-28mm Φ bars. fc’ = 28 MPa, fy = 415 MPa 1. Which of the following most nearly give the effective width of the flange? a. 1565 mm b. 1305 mm c. 1275 mm d. 1625 mm 2. Which of the following most nearly gives the depth of compression block? a. 62.25 mm b. 52.86 mm c. 60.26 mm d. 58.29 mm 3. Which of the following gives the nominal moment capacity of the beam? a. 1461.25 kN/m b. 1156.36 kN/m c. 1163.15 kN/m d. 1172.58 kN/marrow_forward
- A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom. The properties are as follows: Ag = 14,968 sq.mm. rx= 133.65 mm, Ty = 77.47 mm Calculate the critical slenderness ratio if there is an additional lateral support in the weak direction at mid-height. If the columns sustains a service axial live load of 990 kN calculate the safe service axial dead load in kN by URFD. Calculate the allowable axial strength (kN) by ASD Calculate the allowable axial strength (kN) by ASD Calculate the design axial strength (kN) of the colurn by LRFD.arrow_forward1. A W21 × 48 is used as a simply supported, uniformly loaded beam with a span length of 50 feet and continuous lateral support. The yield stress, Fy, is 60 ksi. If the ratio of live load to dead load is 3, compute the available strength and determine the maximum total service load (D+L), in kips/ft, that can be supported considering the flexure and shear strength of the beam. a. Use LRFD. b. Use ASD.arrow_forward
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