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Civil Engineering Steel Design (Activate Learning with these NEW titles from Engineering!)6th Edition

A built-up shape consisting of two 3 4 × 18 flanges and a 3 4 × 52 web is used as a beam. If A572 Grade 50 steel is used, what is the nominal flexural strength based on flange local buckling? For width-thickness ratio limits for welded shapes, refer to Table B4.1b in Chapter B of the AISC Specification, “Design Requirements?

Steel Design (Activate Learning wi...

6th Edition

Segui + 1 other

Publisher: Cengage Learning

ISBN: 9781337094740

Chapter 5, Problem 5.6.3P

Textbook Problem

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A built-up shape consisting of two 3 4 × 18 flanges and a 3 4 × 52 web is used as a beam. If A572 Grade 50 steel is used, what is the nominal flexural strength based on flange local buckling? For width-thickness ratio limits for welded shapes, refer to Table B4.1b in Chapter B of the AISC Specification, “Design Requirements?

To determine

The nominal flexural strength of the given built-up shape based on flange local buckling

Explanation of Solution

Given:

Two 34×18 flangesOne 34×52 webA572 Grade 50 steel

Formula used:

λ=bf2tfλp=0.38EFyλr=0.95kcEFLkc=4h/twFL=0.7Fy

λ,λp and λr are width to thickness parameters

Mn=Mp−(Mp−0.7FySx)(λ−λpλr−λp)Mn is nominal moment strength

Calculation:

Check whether the shape is compact, non compact and slender:

λ=bf2tfλ=182×0.75λ=12λp=0.38EFyλp=0.382900050λp=9.15 λr=0.95kcEFLkc=4h/tw, (0.35≤kc≤0.763)kc=452/0.75 =0.4804, FL=0.7Fy λr=0.950.4804(29000)0.7×50=18.95

Since λp<λ<λr, this shape is non compact.

For the web, λ=htw=520.75=69.3

λ=htw=520

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Chapter 5 Solutions

Steel Design (Activate Learning with these NEW titles from Engineering!)

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