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Science
ChemistryOrganic And Biological Chemistry7th Edition

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Chapter 5, Problem 5.71EP
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Organic And Biological Chemistry

7th Edition
STOKER + 1 other
ISBN: 9781305081079

Solutions

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Section
Problem 5.1EP
Problem 5.2EP
Problem 5.3EP
Problem 5.4EP
Problem 5.5EP
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Problem 5.7EP
Problem 5.8EP
Problem 5.9EP
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Problem 5.162EP
Problem 5.163EP
Problem 5.164EP
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Organic And Biological Chemistry

7th Edition
STOKER + 1 other
ISBN: 9781305081079
Textbook Problem

How many ions are present in one formula unit of each of the compounds in Problem 16-69?

  1. 1. Sodium formate
  2. 2. Potassium pentanedioate
  3. 3. Calcium oxalate
  4. 4. Magnesium propanoate

(a)

Interpretation Introduction

Interpretation:

The number of ions that is present in one formula unit of the given salt of carboxylic acid has to be given.

Concept Introduction:

The name of the carboxylic acid itself implies that it is acidic.  Addition of carboxylic acid to water results in ionization.  Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed.  Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.

Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid.  Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.

If the negative ion contains two carboxylate groups in it then it is a dicarboxylate.  The parent acid of this has to be dicarboxylic acid.  If the negative ion contains one carboxylate group in it then it is a monocarboxylate.  The parent acid of this has to be monocarboxylic acid.

This can also be found from the name of the salt given.  If the IUPAC name contains suffix “-ate” alone means it is a salt of monocarboxylic acid.  If the IUPAC name contains prefix “di-” that is preceded by “-ate” in the ending means it is a salt dicarboxylic acid.

Total number of ions in one formula unit of carboxylic acid salt is found by counting the number of discrete ions present in the structure.

Explanation

Given compound name is sodium formate.  The structure of sodium formate can be given as shown below,

(b)

Interpretation Introduction

Interpretation:

The number of ions that is present in one formula unit of the given salt of carboxylic acid has to be given.

Concept Introduction:

The name of the carboxylic acid itself implies that it is acidic.  Addition of carboxylic acid to water results in ionization.  Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed.  Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.

Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid.  Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.

If the negative ion contains two carboxylate groups in it then it is a dicarboxylate.  The parent acid of this has to be dicarboxylic acid.  If the negative ion contains one carboxylate group in it then it is a monocarboxylate.  The parent acid of this has to be monocarboxylic acid.

This can also be found from the name of the salt given.  If the IUPAC name contains suffix “-ate” alone means it is a salt of monocarboxylic acid.  If the IUPAC name contains prefix “di-” that is preceded by “-ate” in the ending means it is a salt dicarboxylic acid.

Total number of ions in one formula unit of carboxylic acid salt is found by counting the number of discrete ions present in the structure.

(c)

Interpretation Introduction

Interpretation:

The number of ions that is present in one formula unit of the given salt of carboxylic acid has to be given.

Concept Introduction:

The name of the carboxylic acid itself implies that it is acidic.  Addition of carboxylic acid to water results in ionization.  Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed.  Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.

Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid.  Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.

If the negative ion contains two carboxylate groups in it then it is a dicarboxylate.  The parent acid of this has to be dicarboxylic acid.  If the negative ion contains one carboxylate group in it then it is a monocarboxylate.  The parent acid of this has to be monocarboxylic acid.

This can also be found from the name of the salt given.  If the IUPAC name contains suffix “-ate” alone means it is a salt of monocarboxylic acid.  If the IUPAC name contains prefix “di-” that is preceded by “-ate” in the ending means it is a salt dicarboxylic acid.

Total number of ions in one formula unit of carboxylic acid salt is found by counting the number of discrete ions present in the structure.

(d)

Interpretation Introduction

Interpretation:

The number of ions that is present in one formula unit of the given salt of carboxylic acid has to be given.

Concept Introduction:

The name of the carboxylic acid itself implies that it is acidic.  Addition of carboxylic acid to water results in ionization.  Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed.  Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.

Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid.  Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.

If the negative ion contains two carboxylate groups in it then it is a dicarboxylate.  The parent acid of this has to be dicarboxylic acid.  If the negative ion contains one carboxylate group in it then it is a monocarboxylate.  The parent acid of this has to be monocarboxylic acid.

This can also be found from the name of the salt given.  If the IUPAC name contains suffix “-ate” alone means it is a salt of monocarboxylic acid.  If the IUPAC name contains prefix “di-” that is preceded by “-ate” in the ending means it is a salt dicarboxylic acid.

Total number of ions in one formula unit of carboxylic acid salt is found by counting the number of discrete ions present in the structure.

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Sect-5.1 P-1QQSect-5.1 P-2QQSect-5.1 P-3QQSect-5.1 P-4QQSect-5.1 P-5QQSect-5.2 P-1QQSect-5.2 P-2QQSect-5.2 P-3QQSect-5.2 P-4QQSect-5.2 P-5QQ
Sect-5.3 P-1QQSect-5.3 P-2QQSect-5.3 P-3QQSect-5.4 P-1QQSect-5.4 P-2QQSect-5.4 P-3QQSect-5.5 P-1QQSect-5.5 P-2QQSect-5.5 P-3QQSect-5.6 P-1QQSect-5.6 P-2QQSect-5.7 P-1QQSect-5.7 P-2QQSect-5.7 P-3QQSect-5.8 P-1QQSect-5.8 P-2QQSect-5.8 P-3QQSect-5.8 P-4QQSect-5.9 P-1QQSect-5.9 P-2QQSect-5.10 P-1QQSect-5.10 P-2QQSect-5.11 P-1QQSect-5.11 P-2QQSect-5.11 P-3QQSect-5.12 P-1QQSect-5.12 P-2QQSect-5.12 P-3QQSect-5.12 P-4QQSect-5.13 P-1QQSect-5.13 P-2QQSect-5.14 P-1QQSect-5.14 P-2QQSect-5.14 P-3QQSect-5.15 P-1QQSect-5.15 P-2QQSect-5.15 P-3QQSect-5.16 P-1QQSect-5.16 P-2QQSect-5.16 P-3QQSect-5.17 P-1QQSect-5.17 P-2QQSect-5.18 P-1QQSect-5.18 P-2QQSect-5.18 P-3QQSect-5.19 P-1QQSect-5.19 P-2QQSect-5.19 P-3QQSect-5.19 P-4QQSect-5.20 P-1QQSect-5.20 P-2QQSect-5.20 P-3QQSect-5.20 P-4QQCh-5 P-5.1EPCh-5 P-5.2EPCh-5 P-5.3EPCh-5 P-5.4EPCh-5 P-5.5EPCh-5 P-5.6EPCh-5 P-5.7EPCh-5 P-5.8EPCh-5 P-5.9EPCh-5 P-5.10EPCh-5 P-5.11EPCh-5 P-5.12EPCh-5 P-5.13EPCh-5 P-5.14EPCh-5 P-5.15EPCh-5 P-5.16EPCh-5 P-5.17EPCh-5 P-5.18EPCh-5 P-5.19EPCh-5 P-5.20EPCh-5 P-5.21EPCh-5 P-5.22EPCh-5 P-5.23EPCh-5 P-5.24EPCh-5 P-5.25EPCh-5 P-5.26EPCh-5 P-5.27EPCh-5 P-5.28EPCh-5 P-5.29EPCh-5 P-5.30EPCh-5 P-5.31EPCh-5 P-5.32EPCh-5 P-5.33EPCh-5 P-5.34EPCh-5 P-5.35EPCh-5 P-5.36EPCh-5 P-5.37EPCh-5 P-5.38EPCh-5 P-5.39EPCh-5 P-5.40EPCh-5 P-5.41EPCh-5 P-5.42EPCh-5 P-5.43EPCh-5 P-5.44EPCh-5 P-5.45EPCh-5 P-5.46EPCh-5 P-5.47EPCh-5 P-5.48EPCh-5 P-5.49EPCh-5 P-5.50EPCh-5 P-5.51EPCh-5 P-5.52EPCh-5 P-5.53EPCh-5 P-5.54EPCh-5 P-5.55EPCh-5 P-5.56EPCh-5 P-5.57EPCh-5 P-5.58EPCh-5 P-5.59EPCh-5 P-5.60EPCh-5 P-5.61EPCh-5 P-5.62EPCh-5 P-5.63EPCh-5 P-5.64EPCh-5 P-5.65EPCh-5 P-5.66EPCh-5 P-5.67EPCh-5 P-5.68EPCh-5 P-5.69EPCh-5 P-5.70EPCh-5 P-5.71EPCh-5 P-5.72EPCh-5 P-5.73EPCh-5 P-5.74EPCh-5 P-5.75EPCh-5 P-5.76EPCh-5 P-5.77EPCh-5 P-5.78EPCh-5 P-5.79EPCh-5 P-5.80EPCh-5 P-5.81EPCh-5 P-5.82EPCh-5 P-5.83EPCh-5 P-5.84EPCh-5 P-5.85EPCh-5 P-5.86EPCh-5 P-5.87EPCh-5 P-5.88EPCh-5 P-5.89EPCh-5 P-5.90EPCh-5 P-5.91EPCh-5 P-5.92EPCh-5 P-5.93EPCh-5 P-5.94EPCh-5 P-5.95EPCh-5 P-5.96EPCh-5 P-5.97EPCh-5 P-5.98EPCh-5 P-5.99EPCh-5 P-5.100EPCh-5 P-5.101EPCh-5 P-5.102EPCh-5 P-5.103EPCh-5 P-5.104EPCh-5 P-5.105EPCh-5 P-5.106EPCh-5 P-5.107EPCh-5 P-5.108EPCh-5 P-5.109EPCh-5 P-5.110EPCh-5 P-5.111EPCh-5 P-5.112EPCh-5 P-5.113EPCh-5 P-5.114EPCh-5 P-5.115EPCh-5 P-5.116EPCh-5 P-5.117EPCh-5 P-5.118EPCh-5 P-5.119EPCh-5 P-5.120EPCh-5 P-5.121EPCh-5 P-5.122EPCh-5 P-5.123EPCh-5 P-5.124EPCh-5 P-5.125EPCh-5 P-5.126EPCh-5 P-5.127EPCh-5 P-5.128EPCh-5 P-5.129EPCh-5 P-5.130EPCh-5 P-5.131EPCh-5 P-5.132EPCh-5 P-5.133EPCh-5 P-5.134EPCh-5 P-5.135EPCh-5 P-5.136EPCh-5 P-5.137EPCh-5 P-5.138EPCh-5 P-5.139EPCh-5 P-5.140EPCh-5 P-5.141EPCh-5 P-5.142EPCh-5 P-5.143EPCh-5 P-5.144EPCh-5 P-5.145EPCh-5 P-5.146EPCh-5 P-5.147EPCh-5 P-5.148EPCh-5 P-5.149EPCh-5 P-5.150EPCh-5 P-5.151EPCh-5 P-5.152EPCh-5 P-5.153EPCh-5 P-5.154EPCh-5 P-5.155EPCh-5 P-5.156EPCh-5 P-5.157EPCh-5 P-5.158EPCh-5 P-5.159EPCh-5 P-5.160EPCh-5 P-5.161EPCh-5 P-5.162EPCh-5 P-5.163EPCh-5 P-5.164EP

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