Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 5.7, Problem 8KCP
Write the equation for Fick’s second law of diffusion in solids, and define each of the terms.
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Answer in a brief and concise essay. 1. Why does diffusion in solids important?
Rank the magnitudes of the diffusion coefficients from greatest to least for the following systems:
N in Fe at 700°C
Cr in Fe at 700°C
N in Fe at 900°C
Cr in Fe at 900°C
Now justify this ranking. (Note: Both Fe and Cr have the BCC crystal structure, and the atomic radii for Fe, Cr, and N are 0.124, 0.125, and 0.065 nm, respectively. You may also want to refer to Section 5.4.)
What does(do) determine a diffusion coefficient (diffusivity)? (choose all)a. Concentration gradientb. Diffusing species and host metalc. Geometryd. Temperature
Chapter 5 Solutions
Foundations of Materials Science and Engineering
Ch. 5.7 - Prob. 1KCPCh. 5.7 - Write an equation for the number of vacancies...Ch. 5.7 - Prob. 3KCPCh. 5.7 - Prob. 4KCPCh. 5.7 - Describe the substitutional and interstitial...Ch. 5.7 - Prob. 6KCPCh. 5.7 - What factors affect the diffusion rate in solid...Ch. 5.7 - Write the equation for Ficks second law of...Ch. 5.7 - Prob. 9KCPCh. 5.7 - Prob. 10KCP
Ch. 5.7 - (a) Calculate the equilibrium concentration of...Ch. 5.7 - Prob. 12AAPCh. 5.7 - Determine the diffusion flux of zinc atoms in a...Ch. 5.7 - The diffusion flux of copper solute atoms in...Ch. 5.7 - Prob. 15AAPCh. 5.7 - Prob. 16AAPCh. 5.7 - Prob. 17AAPCh. 5.7 - A gear made of 1020 steel (0.20 wt% C) is to be...Ch. 5.7 - Prob. 19AAPCh. 5.7 - The surface of a steel gear made of 1020 steel...Ch. 5.7 - Prob. 21AAPCh. 5.7 - If boron is diffused into a thick slice of silicon...Ch. 5.7 - Prob. 23AAPCh. 5.7 - Prob. 24AAPCh. 5.7 - Prob. 25AAPCh. 5.7 - Prob. 26AAPCh. 5.7 - Prob. 27AAPCh. 5.7 - Prob. 28AAPCh. 5.7 - Prob. 29AAPCh. 5.7 - Prob. 30AAPCh. 5.7 - The diffusivity of copper atoms in the aluminum...Ch. 5.7 - Prob. 32AAPCh. 5.7 - Prob. 33SEPCh. 5.7 - Prob. 34SEPCh. 5.7 - Prob. 37SEPCh. 5.7 - Prob. 38SEPCh. 5.7 - The activation energy of nickel atoms in FCC iron...Ch. 5.7 - Prob. 40SEPCh. 5.7 - The self-diffusion of iron atoms in BCC iron is...Ch. 5.7 - Would you expect the diffusion rate of copper...Ch. 5.7 - Would you expect the diffusion rate of copper...Ch. 5.7 - Prob. 44SEPCh. 5.7 - Prob. 45SEPCh. 5.7 - Prob. 46SEPCh. 5.7 - Prob. 47SEPCh. 5.7 - Prob. 48SEPCh. 5.7 - Prob. 49SEPCh. 5.7 - Prob. 50SEP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Please kindly help. I will give a like. Thank you! a. Describe the S-curve model of diffusion on how does ‘rate of adoption’ change over time? At which-point is the rate of diffusion the fastest? b. S-curve model of diffusion: (true/false) and reasoning - k = 0, the rate of diffusion is instantaneous? - fixed k ≥ 0, the carrying capacity is determined only by the ratio of a and b? - fixed k ≥ 0, the rate of diffusion is determined only by the ratio of a and b? c. The diffusion of hybrid corn in the 1940s, who or which region seems to have adopted the hybrids more quickly and why?arrow_forward6. (20%) Pure zinc is to be diffused into the copper by dipping copper into molten zinc at 450°C. Calculate how long would take to obtain 10wt% zinc at a depth of 0.5 mm beneath the copper surface. Is this commercially feasible? What practical problems might arise if we raise the temperature to 1000°C ? Use Table below for error function values as needed. At 450°C, the diffusion coefficient D = 6.3 10-17 m²/s.arrow_forwardCompare the diffusion coefficients for hydrogen and nitrogen in FCC iron at 1000°C and explain the reason for the difference in their values.arrow_forward
- Calculate the value of the diffusion coefficient D (in m2/s) at 750°C for the diffusion of some species in a metal; assume that the values of D0 and Qd are 5.6 × 10-5 m2/s and 177 kJ/mol, respectively.arrow_forwardThe activation energy for the diffusion of copper in silver is 193,000 J/mol. Calculate the diffusion coefficient at 1200 K (927C), given that D at 1000 K (727C) is 1.0 x10^-14 m2 /s.arrow_forwardDiffusion of carbon into the surface of BCC steel at 600oC for 10 hours results in a carbon concentration of 0.2wt% at a depth of 1.5 mm below the surface. At what depth will the same concentration be obtained if the diffusion time is increased to 20 hours, leaving the temperature at 600oarrow_forward
- why diffusion coefficient of caarbon inBCC and FCC iron at temperature 912 is different?arrow_forwardThe diffusion coefficient of nickel in an austenitic stainless steel is 10-22 m2/s at 500°C and 10^-15 m^2/s at 1000°C. Calculate the activation energy for the diffusion of nickel in this alloy over this temperature range.arrow_forwardOne method of fabricating complex aerospace components is diffusion bonding. We wish to join a nickel sheet, intended to rapidly transfer lightning strike data away from critical locations, to an FCC iron (stainless steel) plate. We find that we can accomplish a good bond in 8 hours when the two metals are joined at 800°C. How long will it take to obtain an equally good bond if we decide to perform the bonding at 600°C? (Assume that the quality of the bond is determined by the rate of diffusion into the FCC iron).arrow_forward
- Calculate the value of the diffusion coefficient D (in m^2/s) at 694°C for the diffusion of some species in a metal; assume that the values of D0 and Qd are 5.6 x 10^-5 m^2/s and 177 kJ/mol, respectively. R=8.314 J/(mol*K)arrow_forwardA copper–nickel diffusion couple similar to that shown in Figure 5.1a is fashioned. After a 700-h heat treatment at 1100C (1373 K), the concentration of Cu is 2.5 wt% at the 3.0-mm position within the nickel. At what temperature must the diffusion couple be heated to produce this same concentration (i.e., 2.5 wt% Cu) at a 2.0-mm position after 700 h? The preexponential and activation energy for the diffusion of Cu in Ni 2.7*10^-5(m^2/s) and 256 kJ/mol.arrow_forwardThe diffusivity of aluminum in a commercial aluminum alloy is 10-20 m2/s at 400°C. The activation energy for diffusion of Aluminum in this system is 195 kJ/mol. Calculate the diffusivity at 600°Carrow_forward
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Introduction to Diffusion in Solids; Author: Engineering and Design Solutions;https://www.youtube.com/watch?v=K_1QmKJvNjc;License: Standard youtube license