Chapter 8, Problem 118A

Interpretation Introduction

(a)

Interpretation:

The atom which is more negatively charged, in $\text{C}-\text{H}$, is to be predicted.

Concept introduction:

The ability of an atom to attract electrons in a chemical bond is termed as the electro negativity of that atom. The most electronegative element in the periodic table is fluorine (3.98) and the least electronegative element in the periodic table is francium (0.70).

Answer to Problem 118A

The atom which is more negatively charged, in $\text{C}-\text{H}$, is carbon (C).

Explanation of Solution

It is known that the atom which has the greatest electro negativity will be most negatively charged. The given bond is $\text{C}-\text{H}$. The electronegative value of carbon (C) is 2.55 and the electronegative value of hydrogen (H) is 2.20. Since carbon (C) has the greatest electro negativity, hence, carbon (C) is most negatively charged in $\text{C}-\text{H}$ bond.

Interpretation Introduction

(b)

Interpretation:

The atom which is more negatively charged, in $\text{C}-\text{N}$, is to be predicted.

Concept introduction:

The ability of an atom to attract electrons in a chemical bond is termed as the electro negativity of that atom. The most electronegative element in the periodic table is fluorine (3.98) and the least electronegative element in the periodic table is francium (0.70).

Answer to Problem 118A

The atom which is more negatively charged, in $\text{C}-\text{N}$, is nitrogen (N).

Explanation of Solution

It is known that the atom which has the greatest electro negativity will be most negatively charged. The given bond is $\text{C}-\text{N}$. The electronegative value of carbon (C) is 2.55 and the electronegative value of nitrogen (N) is 3.04. Since nitrogen (N) has the greatest electro negativity, hence, nitrogen (N) is most negatively charged in $\text{C}-\text{N}$ bond.

Interpretation Introduction

(c)

Interpretation:

The atom which is more negatively charged, in $\text{C}-\text{S}$, is to be predicted.

Concept introduction:

The ability of an atom to attract electrons in a chemical bond is termed as the electro negativity of that atom. The most electronegative element in the periodic table is fluorine (3.98) and the least electronegative element in the periodic table is francium (0.70).

Answer to Problem 118A

The atom which is more negatively charged, in $\text{C}-\text{S}$, is sulfur (S).

Explanation of Solution

It is known that the atom which has greatest electro negativity will be most negatively charged. The given bond is $\text{C}-\text{S}$. The electronegative value of carbon (C) is 2.55 and the electronegative value of sulfur (S) is 2.58. Since, sulfur (S) has greatest electro negativity hence sulfur (S) is most negatively charged in $\text{C}-\text{S}$ bond.

Interpretation Introduction

(d)

Interpretation:

The atom which is more negatively charged, in $\text{C}-\text{O}$, is to be predicted.

Concept introduction:

The ability of an atom to attract electrons in a chemical bond is termed as the electro negativity of that atom. The most electronegative element in the periodic table is fluorine (3.98) and the least electronegative element in the periodic table is francium (0.70).

Answer to Problem 118A

The atom which is more negatively charged, in $\text{C}-\text{O}$, is oxygen (O).

Explanation of Solution

It is known that the atom which has the greatest electro negativity will be most negatively charged. The given bond is $\text{C}-\text{O}$. The electronegative value of carbon (C) is 2.55 and the electronegative value of oxygen (O) is 3.44. Since oxygen (O) has the greatest electro negativity, hence, oxygen (O) is most negatively charged in $\text{C}-\text{O}$ bond.