Chapter 8, Problem 25P

Using the simply supported beam from Prob. 8.24, the moment along the beam, $M\left(x\right)$, is given by:

$\begin{array}{l}M\left(x\right)=-10\left[{\langle x-0\rangle }^2-{\langle x-5\rangle }^2\right]+15{\langle x-8\rangle }^1\\ +150{\langle x-7\rangle }^0+57x\end{array}$

Use a numerical method to find the point $\left(\text{s}\right)$ where the moment equals zero.