Chapter 8, Problem 41P

Two fluids at different temperatures enter a mixer and come out at the same temperature. The heat capacity of fluid A is given by:

$c_p=3.381+1.804\times {10}^{-2}T-4.300\times {10}^{-6}{T}^2$

and the heat capacity of fluid B is given by:

$c_p=8.592+1.290\times {10}^{-1}T-4.078\times {10}^{-5}{T}^2$

where $c_p$ is in units of $\text{cal}/\text{mol K, and }T$ is in units of K. Note that

$\Delta H={\int }_{T_1}^{T_2}{c}_{p}dT$

A enters the mixer at $400°\text{C}$. B enters the at $600°\text{C}$, There is twice as much A as there is B entering into the mixer. At what temperature do the two fluids exit the mixer?