Mechanical engineers, as well as most other engineers, use thermodynamics extensively in their work. The following polynomial can be used to relate the zero-pressure specific heat of dry air,
Determine the temperature that corresponds to a specific heat of
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- A company that manufacturers gas cylinder is interested in assessing the relationship between pressure dependent variable and volume of the gas independent variable. The table below gives experimental values of pressure of a given mass of gas corresponding to various of the volume. According to the thermodynamic principles, the relationship be of the form of PVy=C where y and C are constants Volume 53.3 61.8 72.4 88.7 119 194 Pressure 61.2 49.5 37.6 28.4 19.2 10 Find the values y and c that best fit the dataarrow_forward4. Referring to the property table below for saturated liquid, using linear interpolation to determine the following values: a. Pat T = 94°C b. U at P = 0.4285 bar C. vat U= 315.67 kJ/kg Internal Energy, Specific Volume, v x 10 (m*/kg) U ("C) (bar) (kJ/kg) 0.3858 1.0259 313.90 75 80 0.4739 1.0291 334.86 85 0.5783 1.0325 355.84 90 0.7014 1.0360 376.85 95 0.8455 1.0397 397.88 100 1.014 1.0435 418.94arrow_forwardA food product containing 75% moisture content is being frozen. Estimate the specific heat of the product at -10 ° C when 85% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). it is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. Cp of frozen product = .... kJ / kg ° Carrow_forward
- A food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6 ° C when 80% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). it is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and the specific heat of ice follows the function Cp ice = 0.0062 T frozen + 2.0649. Cp frozen products = Answer kJ / kg ° C.arrow_forwardThermodynamics is extensively used in engineering field. The following polynomial can be used to relate the zero-pressure specific heat of dry air c, kl/(kg K) to temperature (K) c, = 0.99403 + 1.671 x 104T +9.7215 x 10-872-9.5838 x 10-"T³ + 1.9520 x 10-4T Which of the following(s) is/are the correct method to determine the temperature that corresponds to a specific heat of 1.1 kl/(kg K). (Choose all that applyl) O A) Gauss-Seidel Method O B) Lagrange Interpolation O C) Newton-Divided Difference O 0) Bisection Method Newton Methodarrow_forwardA closed thermodynamic system consists of a fixed amount of substance (i.e. mass) in which no substance can flow across the boundary, but energy can. For a closed themodynamic system we cannot add energy to the system, via substance (E ) (1.e. matter which contains energy is not allowed across the boundary) Across the Boundaries E° = No Q = = Yes W mass NO CLOSED = Yes SY STEM m = constant | energy YES Figure 1.1. If the substance inside the thermodynamic system shown in figure 1.1. (i.e. piston cylinder device) is air, is the system a Fixed closed system Moveable closed system A. В.arrow_forward
- Q (2): A laboratory experiment has been executed to calculate the thermal conductivity of a specimen. The specimen is a bar with (Diameter= 0.04 m) and (length = 0.06 m). At steady state condition, the following data have been recorded: Voltage(V) Current(A) 8 0.8 T₁ (°C) 46.8 T₂ (°C) T3 (°C) 42.2 34.6 T. (°C) 31.4 By taking into consideration that the temperature changes linearly with position, refer to the figure aside, and calculate he thermal conductivity for the specimen (intermediate section). T₂ T₂ The face Told face T₂ T₂ 6 cm 4 cm 6 cm 4 cm 6 cm Hot section Int. section Cold sectionarrow_forwardA cryogenic substance is found to have a specific heat capacity (at constant volume) c_v that varies with temperature according to c_v = AT^2, where A is an empirically derived constant with units J/(K^3 kg). If 220 J of energy must be transferred thermally (at constant volume) to an 8,750 mg sample of this substance to raise the temperature of the sample from 1.0 K to 6.6 K, what is the value of A? Your Answer: Answer unitsarrow_forwardA food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6 ° C when 82% of the water is frozen. The specific heat of the dry product is 2.5 kJ / (kg ° C). it is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. Cp frozen products = AnswerkJ / kg ° C.arrow_forward
- A food product containing 85% moisture content is being frozen. Estimate the specific heat of the product at -10 ° C when 80% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and that the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. Cp frozen product = Answerarrow_forwardA food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6 ° C when 80% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and that the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. Cp frozen product = Answer kJ / kg ° C.arrow_forwardA food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -8 ° C when 80% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and that the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649.arrow_forward
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