Concept explainers
To analyze:
To recognize the amino acid carried by
a.
b.
c.
d.
e.
Introduction:
The sequence of the three nucleotides forming a unit of genetic code (Amino acid) corresponding to a complementary codon in
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GENETIC ANALYSIS: INTEGRATED - ACCESS
- For each polypeptide derived in the following sequences: 5' CAA GAG GUA UCC UAC AGA 3' 5' GUC AUC UGG AGG GGC AUU 3' 5' CUA UGC AGU AGG ACA CCC 3' 1. Draw the structure of each polypeptide. 2. Label the amide bonds. 3. Identify the N-terminal and C-terminal amino acids. 4. Write the name of each polypeptide.arrow_forwardA tridecapeptide yields the following fragments when partially hydrolized. Determine the sequence of amino acids in the tridecapeptidedrolyzed. Determine the sequence of the tri decapeptide. tridecapeptide à lys-arg + gly-phe-pro + phe-ser-asp-lys + pro-phe-ser + asp-lys-arg-val + gln-ala-tyr + val-trp-gln. Determine the sequence of amino acids in the tridecapeptidearrow_forward5'-TAGCTGATCGAATATGCGGTCTCTATCTTCGTAGACGA-3' 3'-ATCGACTAGCTTATACGCCAGAGATAGAAGCATCTGCT -5' Determine the amino acids that will be encoded by this sequence Second letter First letter U C A G U UUU Phe UUC UUA UUG Leu CUU CUC CUA CUG Leu GUU GUC GUA GUG Val UCU UCC UCA UCGJ AUU AUC lle AUA ACA AUG Met ACG CCU CCC C CCA CCG ACU ACC GCU GCC GCA GCG Ser - Pro Thr Ala A UGU UACTyr Cys UGC. UAA Stop UGA Stop A UAG Stop UGG Trp G CAC His CAA Gin CAG GAUT GAC Asp GAA AAU Asn ACC Ser AGU AAG LYS AA Glu GAGJ Oa. N-Met-Arg - Ser-Leu-Ser - Ser-C Ob. N-Met-Pro-Arg - Asn-Asp - Ser-C d. N-Met-Lys - Val-Glu-Ala-C Oc. N-Asp-Pro-Lys - Ser - Val-Ile-C Oe. N- Met-Ala-Asp-Pro-Lys - Ser-C G CGU CGC CGA CGG AGA AGG. GGU GGC GGA GGG Arg SCAO Gly U UCAG UUA DUAG Arg G Third letter 13arrow_forward
- Determine the sequence of a polypeptide treated with trypsin and chimotripsine. Below are the fragments generated with each treatment. Determine the original sequence for both fragmentations (reduerde that they must be equal in the order of amino acids) Quimotripsina 1. Leu-His-Lys-Gln-Ala-Asn-Gln-Ser-Gly-Gly-Gly-Pro-Ser 1. Gln-Gln-Ala-Gln-His-Leu-Arg-Ala-Cys-Gln-Gln-Trp 2. Arg-lle-Pro-Lys-Cys-Arg-Lys-Phe Trypsin 1. Arg 2. Ala-Cys-Gln-GIn-Trp-Leu-His-Lys 3. Cys-Arg 4. Gln-Ala-Asn-Gln-Ser-Gly-Gly-Gly- Pro-Ser 5. lle-Pro-Lys 6. Light 7. Phe-Gin-Gln-Ala-Gln-His-Leu-Argarrow_forwardThe sequence of a 29 aa long peptide can be determined from the following data: Treatment of the peptide with dansyl chloride reveals that the amino-terminal is Val. Trypsin digestion, separation of peptides, and Edmann technique give the sequences for peptide fragments as follows: T-1 V-G-A-H-A-G-E-Y-G-A-E-A-T-E T-2 A-A-W-G-KT-3 V-L-S-P-A-K T-4 T-N-V-Karrow_forwardA tRNA has an anticodon sequence 3′– GGU–5′. Identify the amino acidit is carrying?arrow_forward
- Using the following sequence and the amino acid chart, please give the amino acid sequence: 5'-UCAGAUGGGAAGCUUGAUCUUGUGA-3'. Abreviations for the amino acids are accepted. Second Position U A G UGU Cys UUU Phe UUC UCU UCC UCA UCG UAU ]Tyr UAC UGC UGA Stop UGG Trp Ser UUA Levu UUG UAA Stop UAG Stop CUU CỤC CUA CUG CU CC ССА CCG CAU His CAC CGU CGC CGA CGG Leu Pro Arg CAA CAG Gln AUU AUC le AUA AUG Met ACU AAU AAC AAA AAG AGU Ser AGC AGA Arg JAsn ACC The АCА Jlys ACG AGG GCU GGU GGC Gly GUU GAU JAsp GAC GUC Val GUA GCC Ala GCA GAA GGA GGG- GCG- GAG JGlu GUG Third Position (3' end) First Position (5' end)arrow_forwardWhat is the length in AA’s of the LilP protein? Assume fMet is NOT CLEAVED. Write out the sequence of the polypeptide in AA: use the three letter notation, e.g. Met-Ser-Pro-arrow_forwardA sample of an unknown peptide was divided into two aliquots. One aliquot was treated with trypsin, and the other with cyanogen bromide. Given the following sequences of the resulting fragments, deduce the sequence of the original peptide. Trypsin treatment: Asn-Thr-Trp-Met-Ile-Lys Gly-Tyr-Met-Gln-Phe Val-Leu-Gly-Met-Ser-Arg Cyanogen Bromide treatment: Gln-Phe Ile-Lys-Gly-Tyr-Met Ser-Arg-Asn-Thr-Trp-Metarrow_forward
- Translate the following mRNA nucleotide sequence into an amino acid sequence, starting at the first base: 5’ - UGUCAUGCUCGUCUUGAAUCUUGUGAUGCUCGUUGGAUUAAUUGU - 3’arrow_forwardConsider the peptide Asp-Lys-Phe-Glu-Asn-Tyr-Gln-Val-Cys. In a single beaker, you treat this peptide with 2 proteases. One protease cleaves at the N-terminus of aromatic R groups and the other cleaves at the C-terminus of polar, non-ionizable R groups. Following the enzymatic digestion, you want to separate your peptide fragments so that you can identify them. You choose to separate the fragments using an anion exchange column. Beginning at pH=6 you apply your peptide fragments to the column and you gradually decrease the pH of the column stopping the separation when the pH of the column equals 4. Omitting chemical structures, write the amino acid sequence of the peptide fragments that are produced from this digest. Write the order that these fragments will elute from the column (if at all). (Relevant pKa values are: 2.1, 3.8, 4.3, 8.3, 9.6, 10.1, and 10.5)arrow_forwardTranslate the following mRNA nucleotide sequence into an amino acid sequence, starting at the second base: 5’ - UGUCAUGCUCGUCUUGAAUCUUGUGAUGCUCGUUGGAUUAAUUGU - 3’arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning