GENETIC ANALYSIS: AN INTEG. APP. W/MAS
2nd Edition
ISBN: 9781323142790
Author: Sanders
Publisher: Pearson Custom Publishing
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Chapter 10, Problem 20P
Restriction enzymes recognize specific double
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Restriction sites are palindromic; that is, they read the same in the5' to 3' direction on each strand of DNA. What is the advantage ofhaving restriction sites organized this way?
When circular DNA is sequenced, the nucleotide base pairs are numbered starting from a fixed position on the DNA, all the way around, usually in a clockwise manner. a DNA molecule that is 3133 base pairs long is digested with RsaI restriction enzyme recognition sites at base numbers 366, 1534, and 2207. What are the sizes of the DNA fragments that will be produced after the DNA is digested with RsaI?
The partial sequence of one strand of a double-stranded DNA molecule is
5'-GACGAAGTGCTGCAGAAAGTCCGCGTTATAGGCATGAATTCCTGAGG
-3'
EcoRI is a restriction enzyme that cleaves after G in the sequence 5'-GAATTC-3'. PstI is a restriction enzyme that cleaves after
A in the sequence 5'-CTGCAG-3'.
Write the sequence of both strands of the DNA fragment created when this DNA is cleaved with both EcoRI and PstI. The first
strand of your duplex DNA fragment should be derived from the given strand sequence.
5'-
-3'
3'-
-5'
Chapter 10 Solutions
GENETIC ANALYSIS: AN INTEG. APP. W/MAS
Ch. 10 - Define the following terms as described in this...Ch. 10 - 2. Using sickle cell disease as an example,...Ch. 10 -
3. Compare and contrast the contributions of...Ch. 10 - Why do differences in protein electrophoretic...Ch. 10 - Prob. 5PCh. 10 - Prob. 6PCh. 10 - Prob. 7PCh. 10 - 8. Wildtype βglobin protein is composed of amino...Ch. 10 - Prob. 9PCh. 10 - Prob. 10P
Ch. 10 - 11. How is an autoradiograph produced from a...Ch. 10 - Prob. 12PCh. 10 - Prob. 13PCh. 10 - Prob. 14PCh. 10 - The family represented in the pedigree and...Ch. 10 - Suppose the mating couple (I-1 and I-2) shown in...Ch. 10 - What are restriction endonucleases, and why are...Ch. 10 - 18. Following restriction digestion, DNA fragments...Ch. 10 - 19. The doublestranded DNA sequence below is part...Ch. 10 - 20. Restriction enzymes recognize specific...Ch. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - 25. A second strain of dwarf plants has a...Ch. 10 - During gel electrophoresis of linear DNA...Ch. 10 - Prob. 27PCh. 10 - 28. In molecular biology, restriction...Ch. 10 - A complete plant gene containing four introns and...Ch. 10 - Prob. 30PCh. 10 - The map below illustrates three alleles in a...Ch. 10 - Prob. 32PCh. 10 - 33. Northern blot analysis is performed on mRNA...
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- A restriction endonuclease breaks a bacterial plasmid into sticky ends to create recombinant DNA. The same restriction endonuclease is used to cleave the DNA segments that will be added to the plasmid. What are sticky ends, and why are complementary sticky ends on the target DNA and the plasmid it will be inserted into so important?arrow_forwardAfter restriction enzymes cut, they contain unpaired bases. Type II restriction enzymes leave ends that may be 5' overhanging, 3' overhanging, or blunt. In all cases each end is left with a 3' OH and a 5' phosphate. All blunt ends, and any complementary overhanging ends may be re-ligated with T4 DNA ligase, as long as at least one 5'- phosphate is present. In the tables below G^AATTC means that the end after cutting with enzyme will be: -----G 3' -----CTTAA 5' GTGCA^C means that the end will be: -----GTGCA 3' -----C 5' Which RE’s from table below have a 5’ overhang? Which ones have a 3’ Overhang? AccI GT^CGAC BamHI G^GATCC ClaI AT^CGAT NsiI ATGCA^T PstI CTGCA^G BglII A^GATCT TaqI T^CGAarrow_forwardRestriction endonucleases are bacterial enzymes that cleave duplex (double-stranded) DNA at specific nucleotide sequences. The mode of replication of the animal virus SV40 has been investigated by using restriction endonucleases that cleave SV40 DNA into a number of unique segments. Like most viruses, SV40 DNA is circular. The map positions of the 11 fragments produced by a pair of restriction endonucleases are shown on the next page. Immediately following a 5 or 10 minute pulse of radioactively labeled thymidine, labeled SV40 molecules that have completed replication during the pulse are isolated. These newly replicated DNA molecules are digested by the restriction endonucleases and the resulting fragments are analyzed for the relative amounts of pulse label they contain. The results are in the table below. Assume that at the time the label was added there was a random population of replicating SV40 DNA molecules in all possible stages of synthesis. From the information given below,…arrow_forward
- When linear DNA is sequenced, the nucleotide base pairs are numbered from the start to finish. a DNA molecule that is 3133 base pairs long is digested with RsaI restriction enzyme recognition sites at base numbers 366, 1534, and 2207. What are the sizes of the DNA fragments that will be produced after the DNA is digested with RsaI?arrow_forwardA molecule of double-stranded DNA that is 5 million base pairs long has a base composition that is 62% G + C. How many times, on average, are restriction sites for the following restriction enzymes likely to be present in this DNA molecule? a. HindIII (recognition sequence is AAGCTT)arrow_forwardThe sequences below indicated the 6bp recognition site for the restriction enzyme EcoRI. The lines indicate the sites where the enzyme will cut each strand. 1). write the sequence and structure of the two DNA pieces after the enzyme cuts (hydrogen bonds holding the strands together between the lines are broken after enzyme cuts) 2). indicate whether EcoRI generates blunt or sticky overhangs 5'- G I A A T T C - 3' 3' - C T T A A l G - 5'arrow_forward
- In the formation of recombinant DNA, a restriction endonuclease cuts a bacterial plasmid to give sticky ends. The DNA segments that are to be added to the plasmid are cleaved with the same restriction endonuclease. What aresticky ends and why is it important that the target DNA and the plasmid it will be incorporated into have complementary sticky ends?arrow_forwardFor a restriction enzyme that recognizes the restriction site GGCC, Which of the following statements is/are true?arrow_forwardFor the following short sequence of double stranded DNA and the given primers, there will be one major duplex DNA product after many cycles (imagine 10 cycles) of PCR. Provide the sequence of this one major duplex product and label the 5’ and 3’ ends of each strand. Sequence to be amplified: 5’- GGTATTGGCTACTTACTGGCATCG- 3’ 3’- CCATAACCGATGAATGACCGTAGC- 5’ Primers: 5’-TGGC-3’ and 5’-TGCC-3’arrow_forward
- What, if any, are potential restriction enzyme recognition sequences in this DNA? (Only consider sequences of 6 bp or longer.) Using any of the sites which you identified in above, illustrate cleavage positions for that site which will result in a 5’ overhang or a 3’ overhang respectively.arrow_forwardTable 21.3 describes the cleavage sites of five different restrictionenzymes. After these restriction enzymes have cleaved the DNA, four of them produce sticky ends that can hydrogen bond with complementary sticky ends, as shown in Figure 21.1. The efficiency of sticky ends binding together depends on the number of hydrogen bonds; more hydrogen bonds makes the ends “stickier” and more likely to stay attached. Rank these four restriction enzymes from Table 21.3 (from best to worst)with regard to the efficiency of their sticky ends binding to each other.arrow_forwardA circular plasmid of 10,000 base pairs (bp) is digested with two restriction enzymes, A and B, to produce a 3000 bp and a 2000 bp bands when visualized on an agarose gel. When digested with one enzyme at a time, only one band is visible at 5000 bp. If the first site for enzyme A (A1) is present at the 100h base, the order in which the remaining sites (A2, B1 and B2) are present is - (A) 3100, 5100, 8100 115. (B) 8100, 3100, 5100 (C) 5100, 3100, 8100 (D) 8100, 5100,. 3100arrow_forward
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