GENETIC ANALYSIS: AN INTEG. APP. W/MAS
2nd Edition
ISBN: 9781323142790
Author: Sanders
Publisher: Pearson Custom Publishing
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 10, Problem 16P
Suppose the mating couple (
Is it possible that their fetus could have sickle cell disease? If so, what is the probability? If not, explain whynot.
Fetal DNA is collected and analyzed by Southern blotting. The fetus has a single DNA band that is
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Using figure 1 and the following background information answer the following questions.
Identification of the genetic cause of hornlessness in cattle has been the subject of intensive genetic and genomic research, culminating in the nomination of two different candidate neomutations on cattle chromosome 1 that are predicted to have arisen 500-1,000 years ago: a complex allele of Friesian origin (PF), an 80,128 base pair (bp) duplication (1909352–1989480 bp), and a second, simple allele of Celtic origin (PC) corresponding to a duplication of 212 bp (chromosome 1 positions 1705834–1706045) in place of a 10-bp deletion (1706051–1706060)We report the use of genome editing using transcription activator-like effector nucleases (TALENs) to introgress the putative PC POLLED allele into the genome of bovine embryo fibroblasts to try and produce a genotype identical to what is achievable using natural mating, but without the attendant genetic drag and admixture. In our previous studies, we…
A normal appearing female infant was identified with a positive newborn screen, linked to chromosome 12. Few years ago, her older sibling had
developed profound hypoglycemia, liver failure leading to coma, and subsequent irreparable brain damage, following a viral illness. The sibling was
subsequently shown by clinical testing to have the same disorder that this female infant is screened positive for.
a. What is the most likely diagnosis?
b. What biomarkers would confirm this on the newborn screening process? Describe the mechanism that causes this metabolic defect.
Suppose, you want to detect the CAG repeat expansion within a particular gene (30 repeats in normal changes to 250 repeats in disease) in a certain disease. How will you diagnose this disease condition?
Can you identify Y chromosome microdeletion (which involves the deletion of AZF locus) using conventional karyotyping? If not, then why?
How will you diagnose a chromosomal translocation event? (Discuss any one of the processes)
Chapter 10 Solutions
GENETIC ANALYSIS: AN INTEG. APP. W/MAS
Ch. 10 - Define the following terms as described in this...Ch. 10 - 2. Using sickle cell disease as an example,...Ch. 10 -
3. Compare and contrast the contributions of...Ch. 10 - Why do differences in protein electrophoretic...Ch. 10 - Prob. 5PCh. 10 - Prob. 6PCh. 10 - Prob. 7PCh. 10 - 8. Wildtype βglobin protein is composed of amino...Ch. 10 - Prob. 9PCh. 10 - Prob. 10P
Ch. 10 - 11. How is an autoradiograph produced from a...Ch. 10 - Prob. 12PCh. 10 - Prob. 13PCh. 10 - Prob. 14PCh. 10 - The family represented in the pedigree and...Ch. 10 - Suppose the mating couple (I-1 and I-2) shown in...Ch. 10 - What are restriction endonucleases, and why are...Ch. 10 - 18. Following restriction digestion, DNA fragments...Ch. 10 - 19. The doublestranded DNA sequence below is part...Ch. 10 - 20. Restriction enzymes recognize specific...Ch. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - 25. A second strain of dwarf plants has a...Ch. 10 - During gel electrophoresis of linear DNA...Ch. 10 - Prob. 27PCh. 10 - 28. In molecular biology, restriction...Ch. 10 - A complete plant gene containing four introns and...Ch. 10 - Prob. 30PCh. 10 - The map below illustrates three alleles in a...Ch. 10 - Prob. 32PCh. 10 - 33. Northern blot analysis is performed on mRNA...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Question 7 Which of the following is inconsistent (not consistent) with inheritance of a maternal effect trait? A) Progeny from the same parents have the same maternal effect phenotype as each other but not their mother. B) Progeny can show a recessive phenotype even though the progeny have dominant genotypes. C) Both parents contribute recessive alleles to an offspring yet it has a dominant phenotype for the maternal effect trait. D) Progeny from the same parents have different traits related to the maternal effect gene in question. CS Scanned with CamScannerarrow_forwardIn drosophila, a recessive mutation (m-) of a maternal effect gene results in an abnormal phenotype wherein homozygous (m-m-) females produce eggs that cannot support embryonic development. Homozygous (m-m-) males, however, can still produce viable sperm. (A) Using m+ to denote a normal gene, determine the genotypes and phenotypes of the F1s produce by a cross between a heterozygous female and a recessive male. (B) From the offspring, backcross the recessive female with the paternal strain. What are the genotypes and phenotypes of the F2s? (C) If m-m- females produce useless eggs, then how are m-m- produced?arrow_forwardThe DNA of every individual in the pedigree shown below has been sequenced at the causative locus. All the non-shaded individuals are wild type apart from III.1. III.1 has been proven to have the causative mutation for this autosomal dominant condition, but they exhibit no symptoms. Based on this small pedigree, what is the level of penetrance for the condition? Please give your answer as a WHOLE percentage, give the number only, no percentage symbol. Answer: The level of penetrance for the condition shown in the pedigree below is Blank 1 percent. 1:1 1:2 Il:1 I1:2 I1:3 Il:4 I1:5 I1:6 II:1 I:2 III:3 III:4 III:3 III:6 III:7 III:8 III:9 III:10 III:11 III12 II:13 III:14 IV:1 | IV:2 IV:3 IV:4 IV:5 IV:6 IV:7 IV:8 IV:9 IV:10 IV:11 IV:12 IV:13 IV:14 IV:15 IV:16 IV:17 IV:18 IV:19 V:1 V:2 V:3 V:4 V:5 V:6 V:7 V:8 V:9 V:10 V:11 V:12arrow_forward
- Prader-Willi syndrome is caused by a mutation in anautosomal maternally imprinted gene. Label the following statements as true or false, assuming that thetrait is 100% penetrant.a. Sons of affected males have a 50% chance of showing the syndrome.b. Daughters of affected males have a 50% chance ofshowing the syndrome.arrow_forwardFamilial retinoblastoma, a rare autosomal dominant defect, arose in a large family that had no prior history of the disease. Consider the following pedigree (the darkly colored symbols represent affected individuals): a. Circle the individual(s) in which the mutation most likely occurred. b. Is the person who is the source of the mutation affected by retinoblastoma? Justify your answer. c. Assuming that the mutant allele is fully penetrant, what is the chance that an affected individual will have an affected child?arrow_forwardThe Klinefelter syndrome (disomy of the X chromosome in males) is a genetic disease caused by aneuploidy of the sex chromosomes in humans. Patients with the 47,XXY karyotype are male. Describe two genetic scenarios leading to patients with the Klinefelter syndrome.arrow_forward
- Take a look at question 3 in More Genetic TIPS. Let’s suppose amale is heterozygous for two polymorphic sequence-tagged sites.STS-1 exists in two sizes: 211 bp and 289 bp. STS-2 also exists intwo sizes: 115 bp and 422 bp. A sample of sperm was collectedfrom this man, and individual sperm were placed into 30 separatetubes. Into each of the 30 tubes were added the primers that amplifySTS-1 and STS-2, and then the samples were subjected toPCR. The following results were obtained:arrow_forwardCampomelic dysplasia (CMD1) is a congenital humansyndrome featuring malformation of bone and cartilage.It is caused by an autosomal dominant mutation of agene located on chromosome 17. Consider the followingobservations in sequence, and in each case, draw whateverappropriate conclusions are warranted.(a) Of those with the syndrome who are karyotypically46,XY, approximately 75 percent are sex reversed,exhibiting a wide range of female characteristics.(b) The nonmutant form of the gene, called SOX9, isexpressed in the developing gonad of the XY male,but not the XX female.(c) The SOX9 gene shares 71 percent amino acid codingsequence homology with the Y-linked SRY gene.(d) CMD1 patients who exhibit a 46,XX karyotypedevelop as females, with no gonadal abnormalities.arrow_forwardThe woman in Problem 24 has had two miscarriages. She has come to you, an established genetic counselor, with these questions: Is there a genetic explanation of her frequent miscarriages? Should she abandon her attempts to have a child of her own? If not, what is the chance that she could have a normal child? Provide an informed response to her concerns.arrow_forward
- The fruit fly Drosophila melanogaster has about 2 x 10^8 base pairs of DNA per haploid genome, of which about 75% in nonrepeated DNA. The DNA is distributed among four pairs of homologous chromosomes, which have a total of about 5,000 visible bands when in polytene forms in the salivary gland. The number of genes initially estimated from mutational studies was also about 5,000 but recent DNA sequencing studies suggest that the gene number may be somewhat higher. a. Why was it tempting to speculate that each band corresponds to a single gene? What does this suggest about the number of different proteins Drosophila can make? Does that seem like a reasonable number to you? b. Assuming all the nonrepeated DNA is uniformly distributed in the chromosomes, how much nonrepeated DNA (in base pairs) is there in average band?arrow_forwardSuppose a man carries a very uncommon dominant mutation for a deadly muscular disease that doesn't show up until people are usually over 50 years of age (he has the disease). He and his wife are expecting their first child--a girl. What is the probability she will also have the disease if... (1) it is autosomal(2) it is X-linked(3) it is Y-linked Explain each answer in detail. Assume the penetrance of the trait is 100%.arrow_forwardHuman adult hemoglobin is a tetramer containing two alpha (a) and two beta (b) polypeptide chains. The a gene cluster on chromosome 16 and the b gene cluster on chromosome 11 share amino acid similarities such that 61 of the amino acids of the a@globin polypeptide (141 amino acids long) are shared in identical sequence with the b@globin polypeptide (146 amino acids long). How might one explain the existence of two polypeptides with partially shared function and structure on two different chromosomes?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Serology 101: Testing for IgG and IgM antibodies; Author: Beckman Coulter Dx;https://www.youtube.com/watch?v=LtqKB-qpJrs;License: Standard youtube license