   Chapter 15, Problem 18P

Chapter
Section
Textbook Problem

(a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in Figure P15.10.(b) If a charge of −2.00 μC is placed at this point, what are the magnitude and direction of the force on it?

(a)

To determine
The electric field at a point 1.00 cm from q2 .

Explanation

The force diagram is given by,

In the above diagram,

• Fq1 is the force due to q1 .
• Fq2 is the force due to q2 .
• Fq3 is the force due to q3 .
• E1 , E2 and E3 are the electric field corresponding to the three charges.

Formula to calculate the electric is given by,

E=keQr2

• ke is the Coulomb constant.
• Q is the charge.
• r is the distance of separation.

Formula to calculate the electric field at a point 1.00 cm from q2 is,

E=E1+E3E2=(keq1r12)+(keq3r32)(keq2r22)

• r1 is the distance between q1 and the point.
• r2 is the distance between q2 and the point.
• r3 is the distance between q3 and the point.

Substitute 8.99×109N.m2/C2 for ke , 6μC for q1 , 1.5μC for q2 , 2μC for q3 , 2

(b)

To determine
The force on the charge placed at a point 1.00 cm from q2 .

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