ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5
ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5
2nd Edition
ISBN: 9780393664034
Author: KARTY
Publisher: NORTON
Question
Book Icon
Chapter 19, Problem 19.38P
Interpretation Introduction

(a)

Interpretation:

The synthesis of given Grignard reagent from an alkyl, alkenyl, alkynyl, or aryl halide is to be suggested.

Concept introduction:

Grignard reagent can be prepared from an alkyl, alkenyl, alkynyl, or aryl halide where the CX bond is converted to CMgX. The halides, on reaction with Mg metal in an ether, forms Grignard reagent.

Expert Solution
Check Mark

Answer to Problem 19.38P

The synthesis of the given Grignard reagent from an alkynyl halide is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  1

Explanation of Solution

The given Grignard reagent is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  2

The given Grignard reagent can be prepared from alkynyl bromide as MgBr is bonded to triple bonded carbon. The carbon bonded to Mg is bonded to Br in alkynyl bromide. Thus, alkynyl bromide on reaction with Mg metal in ether yields this Grignard reagent.

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  3

Conclusion

The synthesis of the given Grignard reagent is provided by identifying alkynyl halide.

Interpretation Introduction

(b)

Interpretation:

The synthesis of given Grignard reagent from an alkyl, alkenyl, alkynyl, or aryl halide is to be suggested.

Concept introduction:

Grignard reagent can be prepared from an alkyl, alkenyl, alkynyl, or aryl halide where the CX bond is converted to CMgX. The halides, on reaction with Mg metal in an ether forms Grignard reagent.

Expert Solution
Check Mark

Answer to Problem 19.38P

The synthesis of given Grignard reagent from an alkyl halide is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  4

Explanation of Solution

The given Grignard reagent is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  5

The given Grignard reagent can be prepared from alkyl iodide as MgI is bonded to sp3 carbon. The carbon bonded to Mg is bonded to I in the alkyl iodide. Thus, alkyl iodide on reaction with Mg metal in ether yields this Grignard reagent.

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  6

Conclusion

The synthesis of given Grignard reagent is provided by identifying alkyl halide.

Interpretation Introduction

(c)

Interpretation:

The synthesis of given Grignard reagent from an alkyl, alkenyl, alkynyl, or aryl halide is to be suggested.

Concept introduction:

Grignard reagent can be prepared from an alkyl, alkenyl, alkynyl, or aryl halide where the CX bond is converted to CMgX. The halides, on reaction with Mg metal in an ether forms Grignard reagent.

Expert Solution
Check Mark

Answer to Problem 19.38P

The synthesis of given Grignard reagent from an aryl halide is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  7

Explanation of Solution

The given Grignard reagent is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  8

The given Grignard reagent can be prepared from aryl bromide as MgBr is bonded to carbon of aromatic ring. The carbon bonded to Mg is bonded to Br in aryl bromide. Thus, aryl bromide on reaction with Mg metal in ether yields this Grignard reagent.

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  9

Conclusion

The synthesis of the given Grignard reagent is provided by identifying aryl halide.

Interpretation Introduction

(d)

Interpretation:

The synthesis of given Grignard reagent from an alkyl, alkenyl, alkynyl, or aryl halide is to be suggested.

Concept introduction:

Grignard reagent can be prepared from an alkyl, alkenyl, alkynyl, or aryl halide where the CX bond is converted to CMgX. The halides on reaction with Mg metal in an ether forms Grignard reagent.

Expert Solution
Check Mark

Answer to Problem 19.38P

The synthesis of the given Grignard reagent from an aryl halide is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  10

Explanation of Solution

The given Grignard reagent is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  11

The given Grignard reagent can be prepared from aryl bromide as MgBr is bonded to carbon of aromatic ring. The carbon bonded to Mg is bonded to Br in aryl bromide. Thus, aryl bromide on reaction with Mg metal in ether yields this Grignard reagent.

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  12

Conclusion

The synthesis of given Grignard reagent is provided by identifying the aryl halide.

Interpretation Introduction

(e)

Interpretation:

The synthesis of given Grignard reagent from an alkyl, alkenyl, alkynyl, or aryl halide is to be suggested.

Concept introduction:

Grignard reagent can be prepared from an alkyl, alkenyl, alkynyl, or aryl halide where the CX bond is converted to CMgX. The halides on reaction with Mg metal in an ether forms Grignard reagent.

Expert Solution
Check Mark

Answer to Problem 19.38P

The synthesis of given Grignard reagent from an alkyl halide is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  13

Explanation of Solution

The given Grignard reagent is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  14

The given Grignard reagent can be prepared from alkyl iodide as MgI is bonded to sp3 carbon. The carbon bonded to Mg is bonded to I in alkyl iodide. Thus, alkyl iodide on reaction with Mg metal in ether yields this Grignard reagent.

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  15

Conclusion

The synthesis of given Grignard reagent is provided by identifying alkyl halide.

Interpretation Introduction

(f)

Interpretation:

The synthesis of given Grignard reagent from an alkyl, alkenyl, alkynyl, or aryl halide is to be suggested.

Concept introduction:

Grignard reagent can be prepared from an alkyl, alkenyl, alkynyl, or aryl halide where the CX bond is converted to CMgX. The halides on reaction with Mg metal in an ether forms Grignard reagent.

Expert Solution
Check Mark

Answer to Problem 19.38P

The synthesis of the given Grignard reagent from an aryl halide is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  16

Explanation of Solution

The given Grignard reagent is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  17

The given Grignard reagent can be prepared from aryl chloride as MgCl is bonded to carbon of aromatic ring. The carbon bonded to Mg is bonded to Cl in aryl chloride. Thus, aryl chloride on reaction with Mg metal in ether yields this Grignard reagent.

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 19, Problem 19.38P , additional homework tip  18

Conclusion

The synthesis of given Grignard reagent is provided by identifying aryl halide.

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Chapter 19 Solutions

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5

Ch. 19 - Prob. 19.11PCh. 19 - Prob. 19.12PCh. 19 - Prob. 19.13PCh. 19 - Prob. 19.14PCh. 19 - Prob. 19.15PCh. 19 - Prob. 19.16PCh. 19 - Prob. 19.17PCh. 19 - Prob. 19.18PCh. 19 - Prob. 19.19PCh. 19 - Prob. 19.20PCh. 19 - Prob. 19.21PCh. 19 - Prob. 19.22PCh. 19 - Prob. 19.23PCh. 19 - Prob. 19.24PCh. 19 - Prob. 19.25PCh. 19 - Prob. 19.26PCh. 19 - Prob. 19.27PCh. 19 - Prob. 19.28PCh. 19 - Prob. 19.29PCh. 19 - Prob. 19.30PCh. 19 - Prob. 19.31PCh. 19 - Prob. 19.32PCh. 19 - Prob. 19.33PCh. 19 - Prob. 19.34PCh. 19 - Prob. 19.35PCh. 19 - Prob. 19.36PCh. 19 - Prob. 19.37PCh. 19 - Prob. 19.38PCh. 19 - Prob. 19.39PCh. 19 - Prob. 19.40PCh. 19 - Prob. 19.41PCh. 19 - Prob. 19.42PCh. 19 - Prob. 19.43PCh. 19 - Prob. 19.44PCh. 19 - Prob. 19.45PCh. 19 - Prob. 19.46PCh. 19 - Prob. 19.47PCh. 19 - Prob. 19.48PCh. 19 - Prob. 19.49PCh. 19 - Prob. 19.50PCh. 19 - Prob. 19.51PCh. 19 - Prob. 19.52PCh. 19 - Prob. 19.53PCh. 19 - Prob. 19.54PCh. 19 - Prob. 19.55PCh. 19 - Prob. 19.56PCh. 19 - Prob. 19.57PCh. 19 - Prob. 19.58PCh. 19 - Prob. 19.59PCh. 19 - Prob. 19.60PCh. 19 - Prob. 19.61PCh. 19 - Prob. 19.62PCh. 19 - Prob. 19.63PCh. 19 - Prob. 19.64PCh. 19 - Prob. 19.65PCh. 19 - Prob. 19.66PCh. 19 - Prob. 19.67PCh. 19 - Prob. 19.68PCh. 19 - Prob. 19.69PCh. 19 - Prob. 19.70PCh. 19 - Prob. 19.71PCh. 19 - Prob. 19.72PCh. 19 - Prob. 19.73PCh. 19 - Prob. 19.74PCh. 19 - Prob. 19.75PCh. 19 - Prob. 19.76PCh. 19 - Prob. 19.77PCh. 19 - Prob. 19.78PCh. 19 - Prob. 19.79PCh. 19 - Prob. 19.1YTCh. 19 - Prob. 19.2YTCh. 19 - Prob. 19.3YTCh. 19 - Prob. 19.4YTCh. 19 - Prob. 19.5YTCh. 19 - Prob. 19.6YTCh. 19 - Prob. 19.7YTCh. 19 - Prob. 19.8YTCh. 19 - Prob. 19.9YTCh. 19 - Prob. 19.10YT
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