Explanation Given: The required value of gain is -50V/V Open loop gain of op-amp is 500V/V. Larger resistance = 100kΩ Resistor at input = 2kΩ Calculation: The expression of the closed loop gain is G = − R 2 R 1 As the closed loop is greater than unity, therefore, value of R 2 will be maximum as compared to the R 1 . Thus, R 2 = 100 kΩ The inverting op-amp circuit can be drawn as The open loop gain is given by A = v o V + − V − As, V + = 0 V A = v o 0 − V − − A = v o V − v o V − = − 500 V/V The value of close loop gain will be G = v o v I − 50 = v o v I v o v I = − 50 V/V Applying the Kirchhoff’s current law at the inverting terminal, V − − v I R 1 + V − − v o R 2 = 0 V − − v I R 1 = v o − V − R 2 R 1 = R 2 ( V − − v I v o − V − )

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

7th Edition

ISBN: 9780199339136

Author: Adel S. Sedra, Kenneth C. Smith

Publisher: Oxford University Press

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An operational amplifier also called op amp is an integrated circuit or analog circuit that takes input as a differential voltage and produces output as a single-ended voltage. It is an IC that can amplify weak electric signals.An op amp has one output p…

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Chapter 2, Problem 2.19P

To determine

The value of the smaller resistor.

The value of shunt across the 2kΩ resistor.

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Chapter 2, Problem 2.18P

Chapter 2, Problem D2.20P

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Chapter 2 Solutions

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

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The value of the smaller resistor. The value of shunt across the 2kΩ resistor.

Solution Summary: The author calculates the value of the inverting op-amp circuit, based on the Kirchhoff's current law.