Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 2, Problem D2.86P
To determine
The transfer function of the low- pass active filter.
To prove:DC gain of first order low pass active filter is given by
To design: Low pass active filter circuit for a given input resistance,dc gain and 3-dB frequency.
Also,the frequency at which the magnitude of the transfer function reduces to a given value.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Consider the active circuit:a. Assuming it's an ideal op amp, derive the circuit’s transfer function as a function of frequency, H(jw) in canonical form.b. We want a DC gain of 40dB. If the op amp has value of Rin = 10MΩ and Rout = 50Ω, choose appropriate values for R1 and R2. Explain why your selected values of R1 and R2 allow you to ignore Rin and Rout for the remainder of the problem.
For the circuit in the figure, extract the following as the formula according to r model and π model.
a) IB, IC and IE currents
b) The voltages at the X, B, C, E points and the voltage VCE
c) Ri input resistance and output resistance Ro
d) Av Voltage gains
e) Low cutoff frequencies
f) Formulate the high cutoff frequencies.
(a) What are the worst-case values (minimum or maximum, as appropriate) of the following parameters of the AD745 op amp: open-loop gain, CMRR, PSRR, VOS, IB1, IB2, IOS, RID, slew rate, gain-bandwidth product, and power supply voltages? (b) Repeat for an LT1028 op amp.
Chapter 2 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 2.1 - Prob. 2.1ECh. 2.1 - Prob. 2.2ECh. 2.1 - Prob. 2.3ECh. 2.2 - Prob. D2.4ECh. 2.2 - Prob. 2.5ECh. 2.2 - Prob. 2.6ECh. 2.2 - Prob. D2.7ECh. 2.2 - Prob. D2.8ECh. 2.3 - Prob. 2.9ECh. 2.3 - Prob. 2.10E
Ch. 2.3 - Prob. D2.11ECh. 2.3 - Prob. 2.12ECh. 2.3 - Prob. 2.13ECh. 2.3 - Prob. 2.14ECh. 2.4 - Prob. 2.15ECh. 2.4 - Prob. D2.16ECh. 2.4 - Prob. 2.17ECh. 2.5 - Prob. 2.18ECh. 2.5 - Prob. D2.19ECh. 2.5 - Prob. D2.20ECh. 2.6 - Prob. 2.21ECh. 2.6 - Prob. 2.22ECh. 2.6 - Prob. 2.23ECh. 2.6 - Prob. 2.24ECh. 2.6 - Prob. 2.25ECh. 2.7 - Prob. 2.26ECh. 2.7 - Prob. 2.27ECh. 2.7 - Prob. 2.28ECh. 2.8 - Prob. 2.29ECh. 2.8 - Prob. 2.30ECh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. D2.12PCh. 2 - Prob. D2.13PCh. 2 - Prob. D2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. D2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. D2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. D2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. D2.33PCh. 2 - Prob. D2.34PCh. 2 - Prob. D2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. D2.37PCh. 2 - Prob. D2.38PCh. 2 - Prob. D2.39PCh. 2 - Prob. D2.40PCh. 2 - Prob. D2.41PCh. 2 - Prob. D2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. D2.44PCh. 2 - Prob. D2.45PCh. 2 - Prob. D2.46PCh. 2 - Prob. D2.47PCh. 2 - Prob. D2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. D2.51PCh. 2 - Prob. D2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. D2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. D2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. D2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. D2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. D2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. D2.76PCh. 2 - Prob. 2.77PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. D2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. D2.82PCh. 2 - Prob. D2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. D2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. D2.92PCh. 2 - Prob. D2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. D2.99PCh. 2 - Prob. D2.100PCh. 2 - Prob. 2.101PCh. 2 - Prob. 2.102PCh. 2 - Prob. 2.103PCh. 2 - Prob. 2.104PCh. 2 - Prob. 2.105PCh. 2 - Prob. 2.106PCh. 2 - Prob. 2.107PCh. 2 - Prob. 2.108PCh. 2 - Prob. 2.109PCh. 2 - Prob. 2.110PCh. 2 - Prob. 2.111PCh. 2 - Prob. 2.112PCh. 2 - Prob. 2.113PCh. 2 - Prob. 2.114PCh. 2 - Prob. 2.115PCh. 2 - Prob. D2.116PCh. 2 - Prob. D2.117PCh. 2 - Prob. D2.118PCh. 2 - Prob. 2.119PCh. 2 - Prob. 2.120PCh. 2 - Prob. 2.121PCh. 2 - Prob. 2.122PCh. 2 - Prob. 2.123PCh. 2 - Prob. 2.124PCh. 2 - Prob. 2.125PCh. 2 - Prob. 2.126PCh. 2 - Prob. D2.127P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- bls 3 Why the amplifier called a unity - gain while it provides 180 degree phase ? inversionarrow_forwardFind the transfer function G(s) = Vo(s)/Vi(s), for each operational amplifier circuit shown in Figure P2.6. [Section: 2.4]arrow_forwardConsider the active circuit with the schematic:a. Assuming it's an ideal op amp, derive the circuit’s transfer function as a function of frequency, H(jw). Make sure it in canonical form.b. We want a DC gain of 40dB. If the op amp has value of Rin = 10MΩ and Rout = 50Ω, choose appropriate values for R1 and R2. Explain why your selected values of R1 and R2 allow you to ignore Rin and Rout for the remainder of the problem. c. If L = 1H, sketch the straight-line approximation of the Bode plot for the circuit’s gain assuming the op amp can still be considered as ideal.d. The op amp you select turns out to be non-ideal, and it has a real pole at wC = 1krad/s. Write the updated transfer function for your circuit (using your values of R1, R2, and L = 1H). Make it in the canonical form.e. Sketch the straight-line approximation of the Bode plot for the circuit with your updated transfer function from D.arrow_forward
- Consider the active circuit with the schematic:a. Assuming it's an ideal op amp, derive the circuit’s transfer function as a function of frequency, H(jw). Make sure it in canonical form.b. We want a DC gain of 40dB. If the op amp has value of Rin = 10MΩ and Rout = 50Ω, choose appropriate values for R1 and R2. Explain why your selected values of R1 and R2 allow you to ignore Rin and Rout for the remainder of the problem.arrow_forward40. Given that fc(ol) = 100 Hz, Aol = 50 dB, and fc(cl) = 3 kHz, determine the closed-loop gain in decibels What is the unity-gain bandwidth in Problem 40? 42 to 44. For each amplifier in the Figures shown determine the closed-loop gain, Acl and bandwidth, BWcl. The op-amps in each circuit exhibit an open-loop gain, Aol of 100 dB and a unity-gain bandwidth, fT of 1 MHzarrow_forwardA single-pole op amp has an open-loop gain of 100 dB and a unity-gain frequency of 2 MHz. Find an expression for the transfer function of the low-pass filter shown if R1 = 5.1kΩ, R2 = 100 kΩ and C = 750 pF. Make a Bode plot comparing the ideal and the actual transfer functions.arrow_forward
- An op amp has a dc gain of 100 dB and a unity-gain frequency of 10 MHz. What is the upper-cutoff frequency of the op amp itself? If the op amp is used to build a noninverting amplifier with a closed-loop gain of 60 dB, what is the bandwidth of the feedback amplifier? Write an expression for the transfer function of the op amp. Write an expression for the transfer function of the noninverting amplifier.arrow_forward(a) There are three voltage inputs of V1 = 1V, V2 = 3V and V3 = 4V, and three resistors with the value of 4kΩ, 2kΩ and 1kΩ. Design a single ideal operational amplifier circuit to combine these inputs to produce a single output voltage of Vout = -10.5v with a feedback resistor of Rf = 2kΩ. Provide the sketch and calculation for your designed circuit. (b) Figure 2 below shows a cascaded operational amplifier circuit. Determined the value of the output voltage Vout. (c) Figure 3 shows a bipolar junction transistor circuit in common-emitter configuration. Given that VBE = 0.7 v and ß = 110. Determine the current IB, IC, IE and the voltage VCE.arrow_forward(a) There are three voltage inputs of V1 = 1V, V2 = 3V and V3 = 4V, and three resistors with the value of 4kΩ, 2kΩ and 1kΩ. Design a single ideal operational amplifier circuit to combine these inputs to produce a single output voltage of Vout = -10.5v with a feedback resistor of Rf = 2kΩ. Provide the sketch and calculation for your designed circuit. (b) Figure 2 below shows a cascaded operational amplifier circuit. Determined the value of the output voltage Vout. (c) Figure 3 shows a bipolar junction transistor circuit in common-emitter configuration. Given that VBE = 0.7 v and ß = 110. Determine the current IB, IC, IE and the voltage VCE. [9 Marks]arrow_forward
- 3A Problem 1. (P1) Three op-amps are connected in cascade configuration. An 80 microVolts signal is connected to the non-inverting input of the first op-amp. Both the 2nd and 3rd op-amps operates as inverting amplifiers. All feedback resistors are 420 KOhms while the input resistances are 71.4kOhms, 19.1kOhms, and 14KOhms respectively. 3H Determine the total gain of the circuit in Problem No. 1 (P1) a.792.105 b.9000 c.792 V d.792arrow_forwardShow the connection of three combination op-amp stages using an LM348 IC to provide outputs that are 110, 1681, and 420 times larger than the input. Use a feedback resistor of Rf = 400 k? in all stages, while can use only (R= 40 k? for first stage), (R= 10 k? for second stage), and (R= 20 k? fot third stage)arrow_forwardDesign an inverting AC amplifier that has a mid-band gain of AV = −2 and with a low cut-off frequency of 105 Hz. Assume that C = 100 nF.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,