Explanation Given: The circuit is given as: Calculation: New diagram after adding the extra resistances to the given diagram: Applying the superposition theorem to the above circuit, the voltage source at the non-inverting end will be short-circuited. Let the inverting node is v n , non-inverting node v p and the output due to the first source is v 01 . By using the virtual ground concept, the voltage at inverting node is same as the voltage at the voltage at the non-inverting node. Due to the super-position theorem, v i 2 = 0 v n = 0 Applying the nodal at the inverting node: v n − v i 1 R 1 + R S + v n − v o 1 R 2 = 0 0 − v i 1 R 1 + R S + 0 − v o 1 R 2 = 0 v o 1 v i 1 = − R 2 R 1 + R S Now, considering the other source and short circuit the first source, v i 1 = 0 Applying the nodal analysis at non-inverting node: v n R 1 + R s + v n − v o 2 R 2 = 0 v p R 1 + R s = v o 2 − v p R 2 ( ∵ v n = v p ) By using the voltage division rule to determine the voltage at non-inverting terminal: v p = R 4 R 4 + R 3 + R S ( v i 2 ) ( ∵ V X = V R X R X + R Y ) Hence, ( 1 R 1 + R S ) ( R 4 R 4 + R 3 + R S ) ( v i 2 ) = v o 2 R 2 − 1 R 2 ( R 4 R 4 + R 3 + R S ) ( v i 2 ) ( 1 R 1 + R S ) ( R 4 R 4 + R 3 + R S ) ( v i 2 ) + 1 R 2 ( R 4 R 4 + R 3 + R S ) ( v i 2 ) = v o 2 R 2 ( R 4 R 4 + R 3 + R S ) ( R 1 + R 2 + R S R 2 ( R 1 + R S ) ) v i 2 = v o 2 R 2 ( R 4 R 4 + R 3 + R S ) ( R 1 + R 2 + R S ( R 1 + R S ) ) v i 2 = v o 2 v o 2 v i 2 = ( R 4 R 4 + R 3 + R S ) ( 1 + R 2 R 1 + R S ) It is given that the circuit is an ideal differential amplifier: So, v o = 0 Then, v o ( v i 2 + v i 2 ) = 0 v o v i 2 + v o v i 2 v i 2

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

7th Edition

ISBN: 9780199339136

Author: Adel S. Sedra, Kenneth C. Smith

Publisher: Oxford University Press

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Chapter 2, Problem 2.64P

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The condition in which the addition is applied so that the op-amp will function as ideal difference amplifier.

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Chapter 2, Problem 2.63P

Chapter 2, Problem 2.65P

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The resistors in the difference ampliﬁer shown are slightly mismatched due to their tolerances. (a) What is the ampliﬁer output voltage if v1 = 3.90 V and v2 = 4.10 V? (b) What would be the output voltage if the resistor pairs were matched? (c) What is the error in amplifying (v1 −v2)?

For an inverting amplifier if the current I = 1 mA with an internal output resistance of 500 Ω and a V1 = 5 mV calculate the output voltage if the dc voltage gain 60 db?

(a) An instrumentation amplifier shown in Figure 1 is an anplifier of low-level signals used in process control or measurement applications and conmercially available in single-package units: (i) Show that Vo=R3/R2(1+2R1/Rg)(v2−v1). (ii) Assume R1=50kohms and R2=R3. If Rg is a tunable resistor with resistance ranging from 1000 ohms to 10k ohms, what is the range of variable gain? (iii) Assume R1=10k ohms and R2=R3,∣v2−v1∣<=120mV and Vcc=12 V. In order to keep the op-amp circuit work in linear region, what is the minimum value of Rg ? (iv) State TWO characteristics of this op-amp circuit.

Chapter 2 Solutions

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

Ch. 2.1 - Prob. 2.1E Ch. 2.1 - Prob. 2.2E Ch. 2.1 - Prob. 2.3E Ch. 2.2 - Prob. D2.4E Ch. 2.2 - Prob. 2.5E Ch. 2.2 - Prob. 2.6E Ch. 2.2 - Prob. D2.7E Ch. 2.2 - Prob. D2.8E Ch. 2.3 - Prob. 2.9E Ch. 2.3 - Prob. 2.10E

Ch. 2.3 - Prob. D2.11E Ch. 2.3 - Prob. 2.12E Ch. 2.3 - Prob. 2.13E Ch. 2.3 - Prob. 2.14E Ch. 2.4 - Prob. 2.15E Ch. 2.4 - Prob. D2.16E Ch. 2.4 - Prob. 2.17E Ch. 2.5 - Prob. 2.18E Ch. 2.5 - Prob. D2.19E Ch. 2.5 - Prob. D2.20E Ch. 2.6 - Prob. 2.21E Ch. 2.6 - Prob. 2.22E Ch. 2.6 - Prob. 2.23E Ch. 2.6 - Prob. 2.24E Ch. 2.6 - Prob. 2.25E Ch. 2.7 - Prob. 2.26E Ch. 2.7 - Prob. 2.27E Ch. 2.7 - Prob. 2.28E Ch. 2.8 - Prob. 2.29E Ch. 2.8 - Prob. 2.30E Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - Prob. 2.7P Ch. 2 - Prob. 2.8P Ch. 2 - Prob. 2.9P Ch. 2 - Prob. 2.10P Ch. 2 - Prob. 2.11P Ch. 2 - Prob. D2.12P Ch. 2 - Prob. D2.13P Ch. 2 - Prob. D2.14P Ch. 2 - Prob. 2.15P Ch. 2 - Prob. 2.16P Ch. 2 - Prob. 2.17P Ch. 2 - Prob. 2.18P Ch. 2 - Prob. 2.19P Ch. 2 - Prob. D2.20P Ch. 2 - Prob. 2.21P Ch. 2 - Prob. 2.22P Ch. 2 - Prob. 2.23P Ch. 2 - Prob. 2.24P Ch. 2 - Prob. 2.25P Ch. 2 - Prob. D2.26P Ch. 2 - Prob. 2.27P Ch. 2 - Prob. 2.28P Ch. 2 - Prob. D2.29P Ch. 2 - Prob. 2.30P Ch. 2 - Prob. 2.31P Ch. 2 - Prob. 2.32P Ch. 2 - Prob. D2.33P Ch. 2 - Prob. D2.34P Ch. 2 - Prob. D2.35P Ch. 2 - Prob. 2.36P Ch. 2 - Prob. D2.37P Ch. 2 - Prob. D2.38P Ch. 2 - Prob. D2.39P Ch. 2 - Prob. D2.40P Ch. 2 - Prob. D2.41P Ch. 2 - Prob. D2.42P Ch. 2 - Prob. 2.43P Ch. 2 - Prob. D2.44P Ch. 2 - Prob. D2.45P Ch. 2 - Prob. D2.46P Ch. 2 - Prob. D2.47P Ch. 2 - Prob. D2.48P Ch. 2 - Prob. 2.49P Ch. 2 - Prob. 2.50P Ch. 2 - Prob. D2.51P Ch. 2 - Prob. D2.52P Ch. 2 - Prob. 2.53P Ch. 2 - Prob. 2.54P Ch. 2 - Prob. 2.55P Ch. 2 - Prob. D2.56P Ch. 2 - Prob. 2.57P Ch. 2 - Prob. 2.58P Ch. 2 - Prob. 2.59P Ch. 2 - Prob. 2.60P Ch. 2 - Prob. D2.61P Ch. 2 - Prob. 2.62P Ch. 2 - Prob. 2.63P Ch. 2 - Prob. 2.64P Ch. 2 - Prob. 2.65P Ch. 2 - Prob. 2.66P Ch. 2 - Prob. D2.67P Ch. 2 - Prob. 2.68P Ch. 2 - Prob. D2.69P Ch. 2 - Prob. 2.70P Ch. 2 - Prob. D2.71P Ch. 2 - Prob. 2.72P Ch. 2 - Prob. 2.73P Ch. 2 - Prob. 2.74P Ch. 2 - Prob. 2.75P Ch. 2 - Prob. D2.76P Ch. 2 - Prob. 2.77P Ch. 2 - Prob. 2.78P Ch. 2 - Prob. 2.79P Ch. 2 - Prob. D2.80P Ch. 2 - Prob. 2.81P Ch. 2 - Prob. D2.82P Ch. 2 - Prob. D2.83P Ch. 2 - Prob. 2.84P Ch. 2 - Prob. 2.85P Ch. 2 - Prob. D2.86P Ch. 2 - Prob. 2.87P Ch. 2 - Prob. 2.88P Ch. 2 - Prob. 2.89P Ch. 2 - Prob. 2.90P Ch. 2 - Prob. 2.91P Ch. 2 - Prob. D2.92P Ch. 2 - Prob. D2.93P Ch. 2 - Prob. 2.94P Ch. 2 - Prob. 2.95P Ch. 2 - Prob. 2.96P Ch. 2 - Prob. 2.97P Ch. 2 - Prob. 2.98P Ch. 2 - Prob. D2.99P Ch. 2 - Prob. D2.100P Ch. 2 - Prob. 2.101P Ch. 2 - Prob. 2.102P Ch. 2 - Prob. 2.103P Ch. 2 - Prob. 2.104P Ch. 2 - Prob. 2.105P Ch. 2 - Prob. 2.106P Ch. 2 - Prob. 2.107P Ch. 2 - Prob. 2.108P Ch. 2 - Prob. 2.109P Ch. 2 - Prob. 2.110P Ch. 2 - Prob. 2.111P Ch. 2 - Prob. 2.112P Ch. 2 - Prob. 2.113P Ch. 2 - Prob. 2.114P Ch. 2 - Prob. 2.115P Ch. 2 - Prob. D2.116P Ch. 2 - Prob. D2.117P Ch. 2 - Prob. D2.118P Ch. 2 - Prob. 2.119P Ch. 2 - Prob. 2.120P Ch. 2 - Prob. 2.121P Ch. 2 - Prob. 2.122P Ch. 2 - Prob. 2.123P Ch. 2 - Prob. 2.124P Ch. 2 - Prob. 2.125P Ch. 2 - Prob. 2.126P Ch. 2 - Prob. D2.127P

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