Explanation Given: Designing of amplifier by using the two-ideal op-amps and resistors. Summing function, v o = v 1 + 2 v 2 − 3 v 3 − 5 v 4 The given equation is v o = v 1 + 2 v 2 − 3 v 3 − 5 v 4 . Solving the circuit to determine the values of resistors and input-output voltages. v o = v 1 + 2 v 2 − 3 v 3 − 5 v 4 v o = − [ − ( v 1 + 2 v 2 ) ] − 3 v 3 − 4 v 4 Drawing the circuit by the help of two-ideal op-amps, resistors and the given summing function. From the circuit: v o 1 = − R a R 1 v 1 − R a R 2 v 2 v o = − R b R 5 v 01 − R b R 3 v 3 − R b R 4 v 4 v o = − R b R 5 [ − R a R 1 v 1 − R b R 2 v 2 ] − R b R 3 v 3 − R b R 4 v 4 v o = [ R a R b R 1 R 2 v 1 + R a R b R 5 R 2 v 2 − R b R

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

7th Edition

ISBN: 9780199339136

Author: Adel S. Sedra, Kenneth C. Smith

Publisher: Oxford University Press

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Operational Amplifier

An operational amplifier also called op amp is an integrated circuit or analog circuit that takes input as a differential voltage and produces output as a single-ended voltage. It is an IC that can amplify weak electric signals.An op amp has one output p…

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Chapter 2, Problem D2.41P

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To implement:Thegiven summing function using the two-ideal op-amps and resistors.

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Chapter 2, Problem D2.40P

Chapter 2, Problem D2.42P

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Chapter 2 Solutions

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

Ch. 2.1 - Prob. 2.1E Ch. 2.1 - Prob. 2.2E Ch. 2.1 - Prob. 2.3E Ch. 2.2 - Prob. D2.4E Ch. 2.2 - Prob. 2.5E Ch. 2.2 - Prob. 2.6E Ch. 2.2 - Prob. D2.7E Ch. 2.2 - Prob. D2.8E Ch. 2.3 - Prob. 2.9E Ch. 2.3 - Prob. 2.10E

Ch. 2.3 - Prob. D2.11E Ch. 2.3 - Prob. 2.12E Ch. 2.3 - Prob. 2.13E Ch. 2.3 - Prob. 2.14E Ch. 2.4 - Prob. 2.15E Ch. 2.4 - Prob. D2.16E Ch. 2.4 - Prob. 2.17E Ch. 2.5 - Prob. 2.18E Ch. 2.5 - Prob. D2.19E Ch. 2.5 - Prob. D2.20E Ch. 2.6 - Prob. 2.21E Ch. 2.6 - Prob. 2.22E Ch. 2.6 - Prob. 2.23E Ch. 2.6 - Prob. 2.24E Ch. 2.6 - Prob. 2.25E Ch. 2.7 - Prob. 2.26E Ch. 2.7 - Prob. 2.27E Ch. 2.7 - Prob. 2.28E Ch. 2.8 - Prob. 2.29E Ch. 2.8 - Prob. 2.30E Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - Prob. 2.7P Ch. 2 - Prob. 2.8P Ch. 2 - Prob. 2.9P Ch. 2 - Prob. 2.10P Ch. 2 - Prob. 2.11P Ch. 2 - Prob. D2.12P Ch. 2 - Prob. D2.13P Ch. 2 - Prob. D2.14P Ch. 2 - Prob. 2.15P Ch. 2 - Prob. 2.16P Ch. 2 - Prob. 2.17P Ch. 2 - Prob. 2.18P Ch. 2 - Prob. 2.19P Ch. 2 - Prob. D2.20P Ch. 2 - Prob. 2.21P Ch. 2 - Prob. 2.22P Ch. 2 - Prob. 2.23P Ch. 2 - Prob. 2.24P Ch. 2 - Prob. 2.25P Ch. 2 - Prob. D2.26P Ch. 2 - Prob. 2.27P Ch. 2 - Prob. 2.28P Ch. 2 - Prob. D2.29P Ch. 2 - Prob. 2.30P Ch. 2 - Prob. 2.31P Ch. 2 - Prob. 2.32P Ch. 2 - Prob. D2.33P Ch. 2 - Prob. D2.34P Ch. 2 - Prob. D2.35P Ch. 2 - Prob. 2.36P Ch. 2 - Prob. D2.37P Ch. 2 - Prob. D2.38P Ch. 2 - Prob. D2.39P Ch. 2 - Prob. D2.40P Ch. 2 - Prob. D2.41P Ch. 2 - Prob. D2.42P Ch. 2 - Prob. 2.43P Ch. 2 - Prob. D2.44P Ch. 2 - Prob. D2.45P Ch. 2 - Prob. D2.46P Ch. 2 - Prob. D2.47P Ch. 2 - Prob. D2.48P Ch. 2 - Prob. 2.49P Ch. 2 - Prob. 2.50P Ch. 2 - Prob. D2.51P Ch. 2 - Prob. D2.52P Ch. 2 - Prob. 2.53P Ch. 2 - Prob. 2.54P Ch. 2 - Prob. 2.55P Ch. 2 - Prob. D2.56P Ch. 2 - Prob. 2.57P Ch. 2 - Prob. 2.58P Ch. 2 - Prob. 2.59P Ch. 2 - Prob. 2.60P Ch. 2 - Prob. D2.61P Ch. 2 - Prob. 2.62P Ch. 2 - Prob. 2.63P Ch. 2 - Prob. 2.64P Ch. 2 - Prob. 2.65P Ch. 2 - Prob. 2.66P Ch. 2 - Prob. D2.67P Ch. 2 - Prob. 2.68P Ch. 2 - Prob. D2.69P Ch. 2 - Prob. 2.70P Ch. 2 - Prob. D2.71P Ch. 2 - Prob. 2.72P Ch. 2 - Prob. 2.73P Ch. 2 - Prob. 2.74P Ch. 2 - Prob. 2.75P Ch. 2 - Prob. D2.76P Ch. 2 - Prob. 2.77P Ch. 2 - Prob. 2.78P Ch. 2 - Prob. 2.79P Ch. 2 - Prob. D2.80P Ch. 2 - Prob. 2.81P Ch. 2 - Prob. D2.82P Ch. 2 - Prob. D2.83P Ch. 2 - Prob. 2.84P Ch. 2 - Prob. 2.85P Ch. 2 - Prob. D2.86P Ch. 2 - Prob. 2.87P Ch. 2 - Prob. 2.88P Ch. 2 - Prob. 2.89P Ch. 2 - Prob. 2.90P Ch. 2 - Prob. 2.91P Ch. 2 - Prob. D2.92P Ch. 2 - Prob. D2.93P Ch. 2 - Prob. 2.94P Ch. 2 - Prob. 2.95P Ch. 2 - Prob. 2.96P Ch. 2 - Prob. 2.97P Ch. 2 - Prob. 2.98P Ch. 2 - Prob. D2.99P Ch. 2 - Prob. D2.100P Ch. 2 - Prob. 2.101P Ch. 2 - Prob. 2.102P Ch. 2 - Prob. 2.103P Ch. 2 - Prob. 2.104P Ch. 2 - Prob. 2.105P Ch. 2 - Prob. 2.106P Ch. 2 - Prob. 2.107P Ch. 2 - Prob. 2.108P Ch. 2 - Prob. 2.109P Ch. 2 - Prob. 2.110P Ch. 2 - Prob. 2.111P Ch. 2 - Prob. 2.112P Ch. 2 - Prob. 2.113P Ch. 2 - Prob. 2.114P Ch. 2 - Prob. 2.115P Ch. 2 - Prob. D2.116P Ch. 2 - Prob. D2.117P Ch. 2 - Prob. D2.118P Ch. 2 - Prob. 2.119P Ch. 2 - Prob. 2.120P Ch. 2 - Prob. 2.121P Ch. 2 - Prob. 2.122P Ch. 2 - Prob. 2.123P Ch. 2 - Prob. 2.124P Ch. 2 - Prob. 2.125P Ch. 2 - Prob. 2.126P Ch. 2 - Prob. D2.127P

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To implement: Thegiven summing function using the two-ideal op-amps and resistors.

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Chapter 2 Solutions