(a)
Interpretation:
The structure of the compound on the basis of NMR spectrum having molecular formula
Concept introduction:
Nuclear magnetic resonance is an analytical technique used to evaluate the chemical structure, molecular formula, arrangement of atoms in the structures and purity of the compound. It is one of the most useful techniques. It works on the principle of spins of atomic nuclei. Hydrogen atom must present in the compound for taking proton NMR spectrum because splitting of peaks occur according to the position of hydrogen atoms.
(b)
Interpretation:
The structure of the compound on the basis of NMR spectrum having molecular formula
Concept introduction:
Nuclear magnetic resonance is an analytical technique used to evaluate the chemical structure, molecular formula, arrangement of atoms in the structures and purity of the compound. It is one of the most useful techniques. It works on the principle of spins of atomic nuclei. Hydrogen atom must present in the compound for taking proton NMR spectrum because splitting of peaks occur according to the position of hydrogen atoms.
(c)
Interpretation:
The structure of the compound on the basis of NMR spectrum having molecular formula
Concept introduction:
Nuclear magnetic resonance is an analytical technique used to evaluate the chemical structure, molecular formula, arrangement of atoms in the structures and purity of the compound. It is one of the most useful techniques. It works on the principle of spins of atomic nuclei. Hydrogen atom must present in the compound for taking proton NMR spectrum because splitting of peaks occur according to the position of hydrogen atoms.
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Chapter 20 Solutions
EP ORGANIC CHEMISTRY -MOD.MASTERING 18W
- Treatment of 2-methylpropanenitrile [(CH3)2CHCN] withCH3CH2CH2MgBr, followed by aqueous acid, affords compound V, whichhas molecular formula C7H14O. V has a strong absorption in its IRspectrum at 1713 cm−1, and gives the following 1H NMR data: 0.91(triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and2.60 (septet, 1 H) ppm. What is the structure of V?arrow_forwardFollowing is the 1H-NMR spectrum of compound O, molecular formula C7H12. Compound O reacts with bromine in carbon tetrachloride to give a compound with the molecular formula C7H12Br2. The 13C-NMR spectrum of compound O shows signals at d 150.12, 106.43, 35.44, 28.36, and 26.36. Deduce the structural formula of compound O.arrow_forwardIndicate two basic differences that exist between the spectra of 1H y 13C in NMR.arrow_forward
- The following NMR spectra were obtained from a compound with the molecular formula C4H6O. Use this information to predict its structure.arrow_forwardCompound 1 has molecular formula C7H15Cl. It shows two signals in the 1H-NMR spectrum, one at 1.08 ppm and one at 1.59 ppm. The relative integrals of these two signals are 3 and 2, respectively. Propose structures for compound 1, explaining how you reach your conclusion.arrow_forwardSketch the 1H NMR spectra of the following compounds.arrow_forward
- The 1H-NMR spectrum of compound R, C6H14O, consists of two signals: d 1.1 (doublet) and d 3.6 (septet) in the ratio 6:1. Propose a structural formula for compound R consistent with this informationarrow_forwardCompound A has molecular formula C5H10O. It shows three signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.1 ppm, a singlet of integral 3 at 2.14 ppm, and a quintet of integral 1 at 2.58 ppm. Suggest a structure for A and explain your reasoning.arrow_forwardAs reaction of (CH3)2CO with LIC≡CH followed by H2O affords compound D, which has a molecular ion in its mass spectrum at 84 and prominent absorptions in its IR spectrum at 3600−3200, 3303, 2938, and 2120 cm−1. D shows the following 1H NMR spectral data: 1.53 (singlet, 6 H), 2.37 (singlet, 1 H), and 2.43 (singlet, 1 H) ppm. What is the structure of D?arrow_forward
- Compound 2 has molecular formula C6H12. It shows three signals in the 1H-NMR spectrum, one at 0.96 ppm, one at 2.03 ppm, and one at 5.33 ppm. The relative integrals of these three signals are 3, 2, and 1, respectively. Provide structure for compound 2, explain how you reached your conclusion.arrow_forward2) A compound having molecular formula C3H60 gave the following spectral data: ( 1 ) υν : λax 292 nm, εman 21 (ii) IR: 2720 cm1 (w) and 1738 cm(s) . Deduce the structure of the compound.arrow_forwardThe H1H1 NMR spectrum shown corresponds to an unknown compound with the molecular formula C6H10C6H10. There are no strong IR bands between 2100 and 2300 or 3250 and 3350 cm−1. Deduce and draw the structure of the molecule that corresponds to the spectrum.arrow_forward
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