   Chapter 21, Problem 67PS

Chapter
Section
Textbook Problem

Review the structure of phosphorous acid in Table 21.6.(a) What is the oxidation number of the phosphorus atom in this acid?(b) Draw the structure of diphosphorous acid, H4P2O5. What is the maximum number of ionizable protons in a molecule of this acid?

(a)

Interpretation Introduction

Interpretation: The oxidation number of phosphorous atom in the phosphorous acid is to be stated.

Concept introduction:

Oxidation number is also called oxidation state. The total number of electrons that an atom gain or loss to form a chemical bond with another atom is known as its oxidation state.

Oxoacids are the acids containing oxygen atoms. Phosphorous is one element that forms a number of oxoacids. The phosphorous acid is an oxoacid of phosphorous atom.

Explanation

In phosphorous acid (H3PO3), The phosphorous is tetrahedrally surrounded by the oxygen atoms and a hydrogen atom. There is one P=O bond, two POH bond and one PH bond.

The phosphorous acid (H3PO3) is an electronically neutral substance. Therefore, the sum of oxidation state of each atom in phosphorous acid is equal to zero.

Each oxygen atom has an oxidation state of 2 beacause it can donate two electrons. Each hydrogen atom has an oxidation of +1 because it can donate one electron

(b)

Interpretation Introduction

Interpretation: To draw the structure of diphosphorous acid, H4P2O5 and maximum number of ionisable protons in diphosphorous acid is to be stated.

Concept introduction: In oxoacids of phosphorous, the phosphorous is tetrahedrally surrounded by other atoms. There are atleast one P=O and one POH bond in these acids. PP and PH bonds are also present besides the P=O bonds and POH bonds in oxoacids of phosphorous.

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