EBK ORGANIC CHEMISTRY
EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 22, Problem 22.51P
Interpretation Introduction

(a)

Interpretation:

Preparation of ethylbutanoate by using ethyl-2-butenoate as starting material is to be stated.

Concept-Introduction:

The carbon-carbon double bond of α,β-unsaturated compounds can be reduced by using catalytic reduction. In catalytic reduction, hydrogen is used with an inert metal as catalyst such as platinum and palladium. Inert metal provides the surface for adsorption of hydrogen and reactant to catalyze the reaction.

Answer:

The formation of ethylbutanoate using ethyl-2-butenoate as starting material is shown below:

EBK ORGANIC CHEMISTRY, Chapter 22, Problem 22.51P , additional homework tip  1

Explanation:

Compound, ethyl-2-butenoate is an α,β unsaturated compound so it can be reduced into ethylbutanoate using catalytic reduction. In the catalytic reduction reaction, inert metals are used as catalyst. Metals provide surface for the adsorption of hydrogen and reactant to facilitate the reaction. The formation of ethylbutanoate using ethyl-2-butenoate as starting material is shown below.

EBK ORGANIC CHEMISTRY, Chapter 22, Problem 22.51P , additional homework tip  2

Figure 1

Conclusion:

Preparation of ethylbutanoate from ethyl-2-butenoate is shown in Figure 1.

Interpretation Introduction

(b)

Interpretation:

Preparation of 2-butene-1-ol using ethyl-2-butenoate as starting material is to be stated.

Concept Introduction:

The α,β unsaturated compounds can be reduced to obtain alcohol by reduction with lithium aluminium hydride. In lithium aluminum hydride, hydride ion act as nucleophile and attacks at the electrophilic carbon centre of carbonyl group. Anion intermediate formed is stabilized by making ion pair with lithium ion. After hydrolysis intermediate will form enol.

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Chapter 22 Solutions

EBK ORGANIC CHEMISTRY

Ch. 22 - Prob. 22.11PCh. 22 - Prob. 22.12PCh. 22 - Prob. 22.13PCh. 22 - Prob. 22.14PCh. 22 - Prob. 22.15PCh. 22 - Prob. 22.16PCh. 22 - Prob. 22.17PCh. 22 - Prob. 22.18PCh. 22 - Prob. 22.19PCh. 22 - Prob. 22.20PCh. 22 - Prob. 22.21PCh. 22 - Prob. 22.22PCh. 22 - Prob. 22.23PCh. 22 - Prob. 22.24PCh. 22 - Prob. 22.25PCh. 22 - Prob. 22.26PCh. 22 - Prob. 22.27PCh. 22 - Prob. 22.28PCh. 22 - Prob. 22.29PCh. 22 - Prob. 22.30PCh. 22 - Prob. 22.31PCh. 22 - Prob. 22.32PCh. 22 - Prob. 22.33PCh. 22 - Prob. 22.34PCh. 22 - Prob. 22.35PCh. 22 - Prob. 22.36PCh. 22 - Prob. 22.37PCh. 22 - Prob. 22.38PCh. 22 - Prob. 22.39PCh. 22 - Prob. 22.40PCh. 22 - Prob. 22.41PCh. 22 - Prob. 22.42PCh. 22 - Prob. 22.43PCh. 22 - Prob. 22.44PCh. 22 - Prob. 22.45PCh. 22 - Prob. 22.46PCh. 22 - Prob. 22.47PCh. 22 - Prob. 22.48PCh. 22 - Prob. 22.49PCh. 22 - Prob. 22.50PCh. 22 - Prob. 22.51PCh. 22 - Prob. 22.52PCh. 22 - Prob. 22.53PCh. 22 - Prob. 22.54PCh. 22 - Prob. 22.55APCh. 22 - Prob. 22.56APCh. 22 - Prob. 22.57APCh. 22 - Prob. 22.58APCh. 22 - Prob. 22.59APCh. 22 - Prob. 22.60APCh. 22 - Prob. 22.61APCh. 22 - Prob. 22.62APCh. 22 - Prob. 22.63APCh. 22 - Prob. 22.64APCh. 22 - Prob. 22.65APCh. 22 - Prob. 22.66APCh. 22 - Prob. 22.67APCh. 22 - Prob. 22.68APCh. 22 - Prob. 22.69APCh. 22 - Prob. 22.70APCh. 22 - Prob. 22.71APCh. 22 - Prob. 22.72APCh. 22 - Prob. 22.73APCh. 22 - Prob. 22.74APCh. 22 - Prob. 22.75APCh. 22 - Prob. 22.76APCh. 22 - Prob. 22.77APCh. 22 - Prob. 22.78APCh. 22 - Prob. 22.79APCh. 22 - Prob. 22.80APCh. 22 - Prob. 22.81APCh. 22 - Prob. 22.82APCh. 22 - Prob. 22.83APCh. 22 - Prob. 22.84APCh. 22 - Prob. 22.85APCh. 22 - Prob. 22.86APCh. 22 - Prob. 22.87APCh. 22 - Prob. 22.88APCh. 22 - Prob. 22.89APCh. 22 - Prob. 22.90APCh. 22 - Prob. 22.91APCh. 22 - Prob. 22.92APCh. 22 - Prob. 22.93APCh. 22 - Prob. 22.94APCh. 22 - Prob. 22.95APCh. 22 - Prob. 22.96APCh. 22 - Prob. 22.97APCh. 22 - Prob. 22.98AP
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