All of the homeotic genes in Drosophila have been cloned. As discussed in Chapter 21, cloned genes can be manipulated in vitro. They can be subjected to cutting and pasting, gene mutagenesis, etc. After Drosophila genes have been altered in vitro, they can be inserted into a transposon vector (i.e., a P element vector), which can be injected into Drosophila embryos. The P element then transposes into the chromosomes, thereby introducing one or more copies of the altered gene into the Drosophila genome. This method is termed P element transformation.
With these ideas in mind, how would you create a gain-of-function mutation that caused the Antp gene to be expressed where the abd-A gene is normally expressed? What
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Genetics: Analysis and Principles
- In contrast with the genomic manipulations of animals and plants described in this chapter, human genetherapy is directed specifically at altering the genomes of somatic cells rather than germ-line cells.Why couldn’t or wouldn’t medical scientists try to alter the genome of human germ-line cells?arrow_forwardSCENARIO: You are studying a disease caused when the gene called BMP5 is not transcribed in osteoblasts. All other genes are transcribed normally. To investigate why BMP5 is not transcribed, you create a reporter transgene by putting GFP under the control of the BMP5 enhancer found in diseased osteoblasts. You put this reporter transgene into a normal, healthy osteoblast.-----------------Short Answer Question 4: In the question above, does it matter if the BMP5 enhancer-GFP reporter gene is tested in a normal, healthy osteoblast or in a diseased osteoblast? Why or why not?arrow_forwardIn the module, you have learned about P-element mediated transgenesis in Drosophila and the concept of using transgenes to rescue mutant phenotypes. In the figure below, you will see a wild type fly with its natural eye colour and three mutants with their eye colours changed to vermillion, white and rosy, respectively. A schematic of P-element mediated transgenesis (as shown in the lectures) is also included in the figure. Please inspect the schematic carefully and choose which of the following statements is true: I. Injection of the white experimental transgene into the vermillion mutant embryo will not change the vermillion mutant phenotype II. Injection of the white experimental transgene in the rosy mutant embryo will change rosy eye colour to red (wild type) III. Injection of the white experimental transgene in the white mutant embryo will not change the white mutant phenotype IV. Injection of the white experimental transgene in the rosy mutant…arrow_forward
- Mutations in the CFTR gene result in cystic fibrosis in humans, a conditions in which abnormal secretions are present in the lungs, pancreas, and sweat glands. The gene was mapped to a 500-kb region on chromosome 7 containing 3 candidate genes. a)Using your knowledge of the disease symptoms, how would you distinguish between the candidate genes to decide which is most likely to encode the CFTR gene? b)How would you prove that your chosen candidate is the CFTR gene?arrow_forwardExpression of recombinant proteins in yeast is an important tool for biotechnology companies that produce new drugs for human use. In an attempt to get a new gene X expressed in yeast, a researcher has integrated gene X into the yeast genome near a telomere. Will this strategy result in good expression of gene X? Why or why not? Would the outcome of this experiment differ if the experiment had been performed in a yeast line containing mutations in the H3 or H4 histone tails?arrow_forwardScientists carried out a microarray analysis to compare the gene expression of normal pancreatic cells to that of cancer cells from a person with pancreatic cancer. The scientists labeled the cDNA from the normal pancreatic cells with green fluorescent nucleotides. They labeled the cDNA from the cancer cells with red fluorescent nucleotides. The two cDNAs were mixed and allowed to hybridize to a microarray. Less p53 activity is found in cancer pancreatic cells than normal cells. What color would the spot for the p53 gene be on the microarray? Red Green Yellow Blackarrow_forward
- Expression of recombinant proteins in yeast is an important tool for biotechnology companies that produce new drugs for human use. In an attempt to get a new gene X expressed in yeast, a researcher has integrated gene X into the yeast genome near a telomere. Will this strategy result in good expression of gene X? Why or why not? please try to explain a bit elaborately.arrow_forward. Let’s say that you have incredible skill and can isolate the white and red patches of tissue from the Drosophila eyes shown in Figure 12-24 in order to isolate mRNA from each tissue preparation. Using your knowledge of DNA techniques from Chapter 10, design an experiment that would allow you to determine whether RNA is transcribed from the white gene in the red tissue or the whitetissue or both. If you need it, you have access to radioactive white-gene DNAarrow_forwardIn the sea urchin, early development may occur even in the presence of actinomycin D, which inhibits RNA synthesis. However, if actinomycin D is present early in development but is removed a few hours later, all development stops. In fact, if actinomycin D is present only between the sixth and eleventh hours of development, events that normally occur at the fifteenth hour are arrested. What conclusions can be drawn concerning the role of gene transcription between hours 6 and 15?arrow_forward
- The ability to selectively modify the genome in the mouse has revolutionized mouse genetics. Outline the procedure for generating a knockout mouse at a specific genetic locus. How can the loxP-Cre system be used to conditionally knock out a gene? What is an important medical application of knockout mice?arrow_forwardexpression of recombinant proteins in yeast is an important tool for biotechnology companies that produce new drugs for human use.in an attempt to get a new gene X expressed in yeast, a researcher has integrated gene X into the yeast genome near a telomere. will this strategy result in good expression of gene X? why or why not?arrow_forward
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