   # As the bead engineer of your starship in charge of the warp drive, you notice that the supply of dilithium is critically low. While searching for a replacement fuel, you discover some diboron, B 2 . a. What is the bond order in Li 2 and B 2 ? b. How many electrons must be removed from B 2 to make it isoelectronic with Li 2 so that it might be used in the warp drive? c. The reaction to make B 2 isoelectroruc with Li 2 is generalized (where n = number of electrons determined in part b) as follows: B 2 → B 2 n + + n e − Δ E = 6455 k J / m o l How much energy is needed to ionize 1.5 kg B 2 to lhe desired isoelectroruc species? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 4, Problem 125IP
Textbook Problem
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## As the bead engineer of your starship in charge of the warp drive, you notice that the supply of dilithium is critically low. While searching for a replacement fuel, you discover some diboron, B2.a. What is the bond order in Li2 and B2?b. How many electrons must be removed from B2 to make it isoelectronic with Li2 so that it might be used in the warp drive?c. The reaction to make B2 isoelectroruc with Li2 is generalized (where n = number of electrons determined in part b) as follows: B 2 →   B 2 n + + n e −                   Δ E =   6455   k J / m o l How much energy is needed to ionize 1.5 kg B2 to lhe desired isoelectroruc species?

(a)

Interpretation Introduction

Concept introduction: The electronic configuration for multi-electron diatomic molecule is written using the molecular orbitals, derived from the H2+ molecular ion.

The bond order is calculated by difference between the anti-bonding electrons and the bonding electrons by two. This can be stated as,

Bondorder=[(Electronsinbondingorbitals)(Electronsinanti-bondingorbitals)]2

As the bond order increases, the stability also increases.

To determine: The bond order of Li2 and B2 .

### Explanation of Solution

The molecular orbital diagram for the given Li2 molecule is,

Figure 1

According to this,

The electronic configuration of Li2 is,

(σ1s)2(σ1s*)2(σ2s)2

The bond order of Li2 is calculated as,

Bond order =12(42)=1_

Hence, the bond order of Li2 is 1_ .

The molecular orbital diagram for the given B2 molecule is,

(b)

Interpretation Introduction

Concept introduction: The electronic configuration for multi-electron diatomic molecule is written using the molecular orbitals, derived from the H2+ molecular ion.

The bond order is calculated by difference between the anti-bonding electrons and the bonding electrons by two. This can be stated as, Bondorder=[(Electronsinbondingorbitals )(Electronsinanti-bondingorbitals )]2

As the bond order increases, the stability also increases.

To determine: The number of electrons to be removed from B2 , to make it isoelectronic with Li2 .

(c)

Interpretation Introduction

Concept introduction: The electronic configuration for multi-electron diatomic molecule is written using the molecular orbitals, derived from the H2+ molecular ion.

The bond order is calculated by difference between the anti-bonding electrons and the bonding electrons by two. This can be stated as, Bondorder=[(Electronsinbondingorbitals )(Electronsinanti-bondingorbitals )]2

As the bond order increases, the stability also increases.

To determine: The energy required for the ionization of 1.5kg B2 to the desired isoelectronic species.

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