   # Balance each chemical equation: a . C 2 H 6 + O 2 → CO 2 + H 2 O b . H 2 S + SO 2 → S + H 2 O c . CH 3 OH + O 2 → CO 2 + H 2 O ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 4, Problem 52E
Textbook Problem
1 views

## Balance each chemical equation: a .  C 2 H 6 + O 2   → CO 2 + H 2 O b .  H 2 S + SO 2   → S + H 2 O c .  CH 3 OH + O 2   → CO 2 + H 2 O

Interpretation Introduction

Interpretation:

The chemical equations are to be balanced for the given reactions.

Concept introduction:

A chemical equation is a symbolic depiction of a chemical reaction that contains symbols and formula.

In a chemical reaction, the starting substances on the left side are known as reactants, while the substances on the right side are known as products.

The chemical formula represents the precise number of atoms in a molecule, but not their structural arrangement.

### Explanation of Solution

a) C2H6+O2CO2+H2O

H atom is balanced by multiplying the coefficient 6 with H2O and the coefficient 2 with C2H6 as follows:

2C2H6+O2CO2+6H2O

In the next step, C atom is balanced by multiplying the coefficient 4 with CO2 as follows:

2C2H6+O24CO2+6H2O

Now, in the final step, O atom is balanced by multiplying the coefficient 7 with O2 in the reactant part as follows:

2C2H6+7O24CO2+6H2O

b) H2S+SO2S+H2O

O atom is balanced by multiplying the coefficient 2 with H2O, which is present in the product part as follows:

H2S+SO2S+2H2O

In the next step, H atom is balanced by multiplying the coefficient 2 with H</

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