Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
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Chapter 5, Problem 30P
Summary Introduction
To determine:
The reduction in the physical distance between the gene HD and the G8 DNA marker.
Introduction:
The genes are the sequence of
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Compared to the normal A allele, the disease-causing allele in sickle cell anemia (S allele) is missing an MstII restriction site. On a Southern blot of genomic DNA cut with MstII and hybridized with the probe shown on the diagram below, a person with sickle anemia, carrying two S alleles, will show
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a single band at 1.1 kb.
a single band at 1.3 kb.
a single band at 0.2 kb.
one band at 0.2 and one at 1.3 kb.
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146
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haplotype
1
A
C
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2
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G
G
3
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4
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5
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G
6
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T
G
G
7
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Chapter 5 Solutions
Genetics: From Genes to Genomes
Ch. 5 - Choose the phrase from the right column that best...Ch. 5 - a. A Drosophila male from a true-breeding stock...Ch. 5 - Prob. 3PCh. 5 - The Punnett square in Fig. 5.4 shows how Mendels...Ch. 5 - In mice, the dominant allele Gs of the X-linked...Ch. 5 - In Drosophila, males from a true-breeding stock...Ch. 5 - If the a and b loci are 20 m.u. apart in humans...Ch. 5 - CCDD and ccdd individuals were crossed to each...Ch. 5 - In mice, the autosomal locus coding for the...Ch. 5 - In a particular human family, John and his mother...
Ch. 5 - Albino rabbits lacking pigment are homozygous for...Ch. 5 - In corn, the allele A allows the deposition of...Ch. 5 - If the a and b loci are 40 cM apart and an AA BB...Ch. 5 - Write the number of different kinds of phenotypes,...Ch. 5 - A DNA variant has been found linked to a rare...Ch. 5 - Figure 5.7a shows chromosomes during prophase of...Ch. 5 - Figure 5.7b shows bivalents in mouse primary...Ch. 5 - Cinnabar eyes cn and reduced bristles rd are...Ch. 5 - In Drosophila, the autosomal recessive dp allele...Ch. 5 - From a series of two-point crosses, the following...Ch. 5 - Map distances were determined for four different...Ch. 5 - In the tubular flowers of foxgloves, wild-type...Ch. 5 - In Drosophila, the recessive allele mb of one gene...Ch. 5 - A snapdragon with pink petals, black anthers, and...Ch. 5 - In Drosophila, three autosomal genes have the...Ch. 5 - Drosophila females heterozygous for each of three...Ch. 5 - Male Drosophila expressing the autosomal recessive...Ch. 5 - a. In Drosophila, crosses between F1 heterozygotes...Ch. 5 - A true-breeding strain of Virginia tobacco has...Ch. 5 - Prob. 30PCh. 5 - The following list of four Drosophila mutations...Ch. 5 - Do the data that Mendel obtained fit his...Ch. 5 - Two genes control color in corn snakes as follows:...Ch. 5 - A mouse from a true-breeding population with...Ch. 5 - Neurospora of genotype a c are crossed with...Ch. 5 - A cross was performed between one haploid strain...Ch. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Indicate the percentage of tetrads that would have...Ch. 5 - Prob. 43PCh. 5 - This problem leads you through the derivation of a...Ch. 5 - a. In ordered tetrad analysis, what is the maximum...Ch. 5 - Prob. 46PCh. 5 - A single yeast cell placed on a solid agar will...Ch. 5 - Figure 5.29 shows mitotic recombination leading to...Ch. 5 - A diploid strain of yeast has a wild-type...Ch. 5 - In Drosophila, the yellow y gene is near the...Ch. 5 - Neurofibromas are tumors of the skin that can...Ch. 5 - Two important methods for understanding the...
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- In our simple model of DNA amplification we assumed that a successful amplification doubled the DNA each cycle. Reality isn't so kind! Two related problems encountered in DNA profiling are the issues of asymmetric peaks and "drop-out" where an allele produces a small to very-small peak compared to the other allele. Assume you have a sample with a heterozygous set of alleles. Let one of the alleles be successfully doubled each cycle but the second allele is (on average) only increased by 1.8. If the sample is subjected to 30 PCR cycles, how much larger will the "successful" peak be than the "less successful" peak? Set your answer up as a ratio of the "successful" /"unsuccessful" and round your number to 1 decimal place. (for example, if your calculations show that after 30 cycles the successful allele has 55340 copies and the unsuccessful has 10000 copies the ratio is 5.5)arrow_forwardWhy does evenly distributed peak in DNA chromatogram is an indication of a good sequence?arrow_forwardYou have identified a SNP marker that in one largefamily shows no recombination with the locus causinga rare hereditary autosomal dominant disease.Furthermore, you discover that all afflicted individuals in the family have a G base at this SNP on theirmutant chromosomes, while all wild-type chromosomes have a T base at this SNP. You would like tothink that you have discovered the disease locus andthe causative mutation but realize you need to consider other possibilities.a. What is another possible interpretation of the results?b. How would you go about obtaining additional genetic information that could support or eliminateyour hypothesis that the base-pair difference is responsible for the disease?arrow_forward
- If the bandicoot genome is 3.62 x 109 base pairs, and the "highly repetitive DNA" fraction is composed entirely of copies of sequence 5'TGCGTGTGTGC3' and its complement, how many copies of this sequence are present in the bandicoot genome?arrow_forwardSuppose you are constructing a human genomic library in BAC vectors where the human DNA fragments are on average 100,000 bp. a. What is the minimum number of different recombinant BACs you need to construct in order to havea greater than zero chance of having a completelibrary—meaning one in which the entire genomeis represented?The simple statistical equation that follows allows youto determine the size that a genomic library needs tobe (that is, the number of independent recombinantclones you need to make) for a given likelihood thatthe entire genome is represented in the library.N = ln (1 − P)ln (1 − f )In the equation, N is the number of independent recombinant clones; P is the probability that any particular partof the genome is represented at least one time; f is thefraction of the genome in a single recombinant clone.(Note: ln is the natural log, sometimes written as loge.)b. Calculate f for the genomic library described in part (a).c. How many different recombinant BAC…arrow_forwardBased on the attached image, if we are using the Holliday junction model of recombination, where exactly would be the positions where DNA is cut? Would it be to the right because of branch migration?arrow_forward
- Two pathways, homologous recombination and nonhomologous end joining (NHEJ), can repair double-strandbreaks in DNA. If homologous recombination is an errorfree pathway whereas NHEJ is not always error free, whyis NHEJ used most of the time in eukaryotes?arrow_forwardUsing a laser beam, you isolated several R bands from human chromosomes. Answer the following questions What kinds of genes are present in R bands? Which isochors do you expect to be present in the R band? What class of interspersed repeats will be present in R bands? What class of tandem repeats do you expect to find in RG bands? Would you expect to find telomere sequences in some R bands?arrow_forwardIn addition to correcting DNA mismatches, themismatch repair system functions to prevent homologousrecombination from taking place between similar but notidentical sequences. Why would recombination betweensimilar, but nonidentical sequences pose a problem forhuman cells?arrow_forward
- If you compare the frequency of the sixteen possible dinucleotide sequences in the E. coli and human genomes, there are no striking differences except for one dinucleotide, 5ʹ-CG-3ʹ. The frequency of CG dinucleotides in the human genome is significantly lower than in E. coli and significantly lower than expected by chance. Why do you suppose that CG dinucleotides are underrepresented in the human genome? (hint: The C in the CG pair is often methylated). Explain how this observation has an impact on the cells immune response.arrow_forwardA person with a rare genetic disease has a sample of her chromosomessubjected to in situ hybridization using a probe that is known to recognize band p11 on chromosome 7. Even though her chromosomes look cytologically normal, the probe does not bind to this person’s chromosomes. How would you explain these results? How would you use this information to positionally clone the gene that is related to this disease?arrow_forwardDraw the genetic map using the following two-point cross data. Locus1 Locus2 Recombination Frequency (%) Locus1 Locus2 Recombination Frequency (%) buckY captAm 50 falcoN tchallA 39 buckY falcoN 50 falcoN visioN 50 buckY natashA 11 falcoN wandA 39 buckY tchallA 50 falcoN wasP 5 buckY visioN 37 natashA tchallA 50 buckY wandA 50 natashA visioN 44 buckY wasP 50 natashA wandA 50 captAm falcoN 30 natashA wasP 50 captAm natashA 50 tchallA visioN 50 captAm tchallA 50 tchallA wandA 50 captAm visioN 50 tchallA wasP 42 captAm wandA 10 visioN wandA 50 captAm wasP 26 visioN wasP 50 falcoN natashA 50 wandA wasP 33arrow_forward
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