Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 5, Problem 48P
Figure 5.29 shows mitotic recombination leading to single spots or twin spots occurring in the G2 stage of the cell cycle (after the chromosomes have replicated). However, because it usually is initiated by rare, random events of chromosome breakage, mitotic recombination can also take place in G1, prior to S phase. Redraw Fig. 5.29 with mitotic recombination taking place in G1 rather than G2, and demonstrate why any such event could not yield single spots or twin spots.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The following diagram represents two nonhomologous chromosomes:
A B • C D E F G R S • T U V W X
What type of chromosome mutation would produce of the following groups of chromosomes?
Q.A B • T U V F G R S • C D E W X
The garden pea (Pisum sativum) is normally a diploid and has 7 chromosomes in one set (in other words, n = 7). Use this information to answer the following questions:
a. How many centromeres would be in a cell of a tetraploid pea plant? ______
b. How many total chromatids would be in a cell of a tetraploid pea plant in metaphase of mitosis? _______
c. How many total chromosomes would be in a cell of a pea plant that is monosomic for a single chromosome?
. When a cell of genotype A/a ; B/b ; C/c having all thegenes on separate chromosome pairs divides mitotically,what are the genotypes of the daughter cells?
Chapter 5 Solutions
Genetics: From Genes to Genomes
Ch. 5 - Choose the phrase from the right column that best...Ch. 5 - a. A Drosophila male from a true-breeding stock...Ch. 5 - Prob. 3PCh. 5 - The Punnett square in Fig. 5.4 shows how Mendels...Ch. 5 - In mice, the dominant allele Gs of the X-linked...Ch. 5 - In Drosophila, males from a true-breeding stock...Ch. 5 - If the a and b loci are 20 m.u. apart in humans...Ch. 5 - CCDD and ccdd individuals were crossed to each...Ch. 5 - In mice, the autosomal locus coding for the...Ch. 5 - In a particular human family, John and his mother...
Ch. 5 - Albino rabbits lacking pigment are homozygous for...Ch. 5 - In corn, the allele A allows the deposition of...Ch. 5 - If the a and b loci are 40 cM apart and an AA BB...Ch. 5 - Write the number of different kinds of phenotypes,...Ch. 5 - A DNA variant has been found linked to a rare...Ch. 5 - Figure 5.7a shows chromosomes during prophase of...Ch. 5 - Figure 5.7b shows bivalents in mouse primary...Ch. 5 - Cinnabar eyes cn and reduced bristles rd are...Ch. 5 - In Drosophila, the autosomal recessive dp allele...Ch. 5 - From a series of two-point crosses, the following...Ch. 5 - Map distances were determined for four different...Ch. 5 - In the tubular flowers of foxgloves, wild-type...Ch. 5 - In Drosophila, the recessive allele mb of one gene...Ch. 5 - A snapdragon with pink petals, black anthers, and...Ch. 5 - In Drosophila, three autosomal genes have the...Ch. 5 - Drosophila females heterozygous for each of three...Ch. 5 - Male Drosophila expressing the autosomal recessive...Ch. 5 - a. In Drosophila, crosses between F1 heterozygotes...Ch. 5 - A true-breeding strain of Virginia tobacco has...Ch. 5 - Prob. 30PCh. 5 - The following list of four Drosophila mutations...Ch. 5 - Do the data that Mendel obtained fit his...Ch. 5 - Two genes control color in corn snakes as follows:...Ch. 5 - A mouse from a true-breeding population with...Ch. 5 - Neurospora of genotype a c are crossed with...Ch. 5 - A cross was performed between one haploid strain...Ch. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Indicate the percentage of tetrads that would have...Ch. 5 - Prob. 43PCh. 5 - This problem leads you through the derivation of a...Ch. 5 - a. In ordered tetrad analysis, what is the maximum...Ch. 5 - Prob. 46PCh. 5 - A single yeast cell placed on a solid agar will...Ch. 5 - Figure 5.29 shows mitotic recombination leading to...Ch. 5 - A diploid strain of yeast has a wild-type...Ch. 5 - In Drosophila, the yellow y gene is near the...Ch. 5 - Neurofibromas are tumors of the skin that can...Ch. 5 - Two important methods for understanding the...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- . With regards to the grasshopper testes experiment, diakinesis is an ideal stage to determine chromosome number due to the degree of condensation of the chromosomes? Count the chromosomes at this stage. Does it represent a diploid or a haploid number?arrow_forwardA chromosome of genotype C D recombines with a homolog of genotype c d during meiosis when Spo11 produces a double-strand break between genes C and D. If anticrossover helicase disentangles the invading strand, the likely outcome would be A) two C D and two c d gametes. B) two C d and two c D gametes. C) one C D, one C d, one c D, and one c d gamete. D) four C D gametes. E) four c d gametesarrow_forwardWhy do eukaryotic cells need to go through the elaborate procedure of mitosis rather than simply dividing during interphase? Select as many answers as apply. 1.Daughter cells must be genetically identical to the mother cell, for homeostasis and ordered tissue growth. 2.Bivalent chromosomes must condense and be separated in an orderly fashion, to allow equal distribution of copies into daughter cells 3.Physically dividing the nucleus during interphase would likely lead to gross chromosome breakage and highly unequal assortment of genetic information into daughter cells. 4.Dividing the nucleus during interphase would have the same outcome as mitosis 5.Daughter cells must have half the number of chromosomes after mitosis than the mother cells 6.The homologous pairs of chromosomes need to be separated, to ensure copies go to the daughter cells.arrow_forward
- In the following schematic drawing of a Holliday junction,one chromatid is shown in red, and the homologous chromatidis shown in blue. The red chromatid carries a dominant allelelabeled A and a recessive allele labeled b, whereas the blue chromatidcarries a recessive allele labeled a and a dominant allelelabeled B. Where would the DNA strands have to be cut to produce recombinantchromosomes? Would they be cut at sites 1 and 3, or at sites2 and 4? What would be the genotypes of the two recombinantchromosomes?arrow_forwardIf a gamete of an unknown animal species has 18 chromosomes, how many chromatids are at anaphase I? If a gamete of an unknown animal species has 18 chromosomes, how many chromatids are at telophase II? If a gamete of an unknown animal species has 18 chromosomes, how many centromeres after prophase II? If a gamete of an unknown animal species has 18 chromosomes, how many chromosomes are in after anaphase II? If a gamete of an unknown animal species has 18 chromosomes, how many chromosomes are in at metaphase I? PLEASE ANSWER ALL OF THEM THEY ARE ALL CONNECTED, THANK YOU!arrow_forwardA wild-type chromosome has the following segments: A B C • D E F G H I Researchers have found individuals that are heterozygous for each of the following chromosome mutations. For each mutation, sketch how the wild-type and mutated chromosomes would pair in prophase I of meiosis, showing all chromosome strands. a. A B C • D E F D E F G H I b. A B C • D H I c. A B C • D G F E H I d. A B E D • C F G H Iarrow_forward
- What structures are found in a chromosome? Group of answer choices Two structures for the mitotic spindle to bind, and two complex repetitive structures that are maintained by telomerase One structure for the mitotic spindle to bind, and two complex repetitive structures that are maintained by telomerase One structure for the mitotic spindle to bind, and one complex repetitive structure that is maintained by telomerase Two structures for the mitotic spindle to bind, and one complex repetitive structure that is maintained by telomerase.arrow_forwardWhy is chromosome 21 the smallest and not chromosome 22? considering that a karyogram is arranged from largest to smallestarrow_forwardDuring meiotic prophase in a eukaryotic cell, Spo11 initiates recombination by causing a double-strand break in DNA between Gene A and Gene B on one sister chromatid. Which of these events will occur prior to formation of a Holliday junction? A) A heteroduplex forms due to pairing of Gene A and Gene B. B) Resolvase cuts all four chromatids. C) Spo11 causes a double-strand break in a nonsister chromatid. D) Strand invasion causes one strand of the uncut chromatid to form a D loop. E) Branch migration lengthens the heteroduplex region to include Gene A and Genearrow_forward
- Assume that the diploid number of a certain species is four chromosomes, two large and two small (2n=4). a) Of the following figures, which represents a 3n (triploid) cell in mitotic metaphase? b) For each of the wrong answers from part (a) above, explain briefly why it cannot represent a triploid cell in mitotic metaphase.arrow_forwardIf the DNA content of a diploid cell in the G1 phase of the cell cycle is X, then the DNA content of the same cell at metaphase of meiosis would be 2X 0.25X 0.5X 4Xarrow_forwardVariations in Chromosome NumberAneuploidy Describe the process of nondisjunction and explain when it takes place during cell division.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage LearningHuman Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY