Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 5, Problem 5.10.2P
To determine
(a)
The most economical W-shape for the given beam by using LRFD.
To determine
(b)
The most economical W-shape for the given beam by using ASD
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
The beam-column in the figure below is a member of a braced frame. A second-order analysis was performed with factored loads and reduced member stiffnesses to obtain the moments and axial force shown. Use LRFDand determine whether this member is adequate. Suppose that P = 165 kFor W10 x 60 with L, = 15 ft and C6 = 1.0: ф,M, = 257 ft-kips, ф,M, = 280 ft-kips;for Lc = 15 ft: cPr = 556 kips.
The beam in the figure carries a uniform load of 20 kN/m including its own weight, a concentrated load of 400 kN at 2.4 m from the left support and another concentrated load at 280 kNat 1.2 m from right end. The beam is laterally unsupported except at the two vertical ends. The beam is to be made of W 16 x 77. Use AISC Specifications for A36 steel Fy= 248.69 MPa. a. Determine the maximum bending moment of the beam.
b. Determine the maximum or actual flexural stress of the beam.
c. Determine the allowable flexural stress of the beam.
d. Is it safe to use the said steel as beam? Why?
A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 6.6 m long, fixed at the top and bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows:
A = 14,500 mm^2
Ix = 258.6 x 10^6 mm^4
Iy = 84.375 x 10^6 mm^4
Calculate the effective slenderness ratio with respect to strong axis buckling using theoretical value of k.
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
Knowledge Booster
Similar questions
- P10.10. A W27×94 section of A572 Grade 50 steel 34 feet long, it is used as a simply supported beam. It is subjected to a factored concentrated load of 90 kips at 12 feet from each support. In addition, the beam is subjected to a factored moment of 340 kips-ft at its left end (counterclockwise). Neglect the self-weight of the beam in the calculations, and check whether the beam is safe according to the LRFD. Lateral support is only provided at the ends and load points.arrow_forwardRead the question carefully and give me right solution according to the question. A W12x79 of A573 Grade 60 (Fy=415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at the bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows: A = 14,500 mm^2 Ix = 258.6 x 10^6 mm^4 Iy = 84.375 x 10^6 mm^4 Calculate the effective slenderness ratio with respect to strong axis buckling using theoretical value of k.arrow_forwardThe continuous beam shown is to carry a distributed load w=15kN/m including its self-weight. The built-up section is made from 3-PL200mm x 12mm as shown (“PL” stands for plate). The allowable flexural (compression and tensile) and shearing stresses are 250 MPa and 120 MPa, respectively. Determine the (a) max allowable span L if the max allowable deflection of 10mm is considered. Use E=200GPa.arrow_forward
- The beam shown in Figure is a W16 x 31 of A992 steel. It supports a reinforced concrete floor slab that provides continuous lateral support of the compression flange. The service dead load is 450 /byft. This load is superimposed on the beam; it does not include the weight of the beam itself. The service live load is 550 lby/ft. Does this beam have adequate moment strength?arrow_forward12 A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 6.8 m long, fixed at the top and bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows: A = 14,500 mm^2 Ix = 258.6 x 10^6 mm^4 Iy = 84.375 x 10^6 mm^4 Calculate the critical slenderness ratio with respect to weak axis buckling using theoretical value of k.arrow_forwardThe frame shown in Figure P4.7-8 is unbraced, and bending is about the x-axis of the members. All beams areW1835, and all columns areW1054. a. Determine the effective length factor Kx for column AB. Do not consider the stiffness reduction factor. b. Determine the effective length factor Kx for column BC. Do not consider the stiffness reduction factor. c. If Fy=50 ksi, is the stiffness reduction factor applicable to these columns?arrow_forward
- The simply supported beam consists of a W21 × 44 structural steel wide-flange shape [E = 29,000 ksi; I = 843 in.4]. Assume d = 5 ft, w = 3 kips/ft, P = 48 kips. For the loading shown, determine (a) the beam deflection at point A. (b) the beam deflection at point C.arrow_forwardA W8x31, A36 steel is used as a simply supported beam uniformly loaded over a span of 6.4 m. If the top flange is continuously braced against lateral displacement by the floor, calculate the ultimate uniform load the beam can sustain against bending about the major axis. Write your answer in kN-m with 2 decimal places only. Use Zx = 498 x 103 mm3arrow_forwardProblem A member in a braced frame supports an axial compressive load and end moments that cause bending about both axes of the member. A second-order analysis was performed with factored loads and reduced member stiffnesses to obtain the moments and axial force. Use LRFD and select the lightest W shape of A992 steel. FIGURE P6.8-4arrow_forward
- Situation 17. A w12x79 of A573 Grade 60 (Fy-415MPa) steel is used as a compression member. It is 8m long pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows Ag=14,500 sq.mm = 258.6x10^6 mm^4 Iy=84.375x10^6 mm^4 Calculate the critical slenderness ratio with buckling about strong axis. calculate the critical slenderness ration with buckling about weak axis. calculate the flexural buckling stress Fcr in MPAarrow_forwardThe rigid bar BC is supported by the steel rod AC of cross-sectional area 0.35 in2. Find the vertical displacement (in inches and absolute value) of point Ccaused by the 2684-lb load if x = 9.9 ft and θ = 49.3ᵒ. Use E = 29213 ksi for steel. Note: Round off the final answer to four decimal places.arrow_forwardA W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6 mm ^4 Iy=84.375 x 10^6 mm^4. 55. calculate the critical slenderness ratio with buckling about strong axis.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning